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6 tháng 6 2017

a) \(A=\left(5x+2y\right)^2\)

\(=\left(5x\right)^2+2\cdot5x\cdot2y+\left(2y\right)^2\)

\(=25x^2+20xy+4y^2\)

b) \(B=\left(4x-y\right)^2\)

\(=\left(4x\right)^2-2\cdot4xy+y^2\)

\(=16x^2-8xy+y^2\)

c) \(C=9x^2-25\)

\(=\left(3x-5\right)\left(3x+5\right)\)

d) \(D=\left(x+2\right)^3\)

\(=x^3+3x^2\cdot2+3x\cdot2^2+2^3\)

\(=x^3+6x^2+3x\cdot4+8\)

\(=x^3+6x^2+12x+8\)

6 tháng 6 2017

a, \(A=\left(5x+2y\right)^2=25x^2+20xy+4y^2\)

b, \(B=\left(4x-y\right)^2=16x^2-8xy+y^2\)

c, \(C=9x^2-25=\left(3x-5\right)\left(3x+5\right)\)

d, \(D=\left(x+2\right)^3=x^3+6x^2+12x+8\)

e, \(E=\left(3x-1\right)^3=27x^3-9x^2+9x-1\)

g, \(G=x^3+64=\left(x+4\right)\left(x^2-4x+16\right)\)

h, \(H=27x^3-1=\left(3x-1\right)\left(9x^2+3x+1\right)\)

23 tháng 12 2016

\(1-2y+y^2=\left(1-y\right)^2\)

\(\left(x+1\right)^2-25=\left(x+1-5\right)\left(x+1+5\right)=\left(x-4\right)\left(x+6\right)\)

\(1-4x^2=\left(1-2x\right)\left(1+2x\right)\)

\(27+27x+9x^2=9\left(3+3x+x^2\right)\)

\(8x^3-12x^2y+6xy^2-y^3=\left(2x-y\right)^3\)

\(3x^2-6xy+9y^2=3\left(x^2-2xy+3y^2\right)\)

\(x^2+4x+3=x^2+x+3x+3=x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x+3\right)\)

\(x^2-4x-5=x^2+x-5x-5=x\left(x+1\right)-5\left(x+1\right)=\left(x-5\right)\left(x+1\right)\)

23 tháng 12 2016

a ) \(1-2y+y^2=y^2-2y+1=\left(y-1\right)^2\)

b ) \(\left(x+1\right)^2-25=\left(x+1-5\right)\left(x+1+5\right)=\left(x-4\right)\left(x+6\right).\)

c ) \(1-4x^2=\left(1-2x\right)\left(1+2x\right).\)

d ) \(27+27x+9x^2=9\left(3+3x+x\right)=9\left(3+4x\right).\)

e ) \(8x^3-12x^2y+6xy^2-y^3=\left(2x-y\right)^3\)

f ) \(3x^2-6xy+9y^2=3\left(x^2-2xy+3y^2\right).\)

g ) \(x^2+4x+3==x^2+3x+x+3=\left(x+1\right)\left(x+3\right)\)

h ) \(x^2-4x-5=x^2+x-5x-5=\left(x-5\right)\left(x+1\right).\)

27 tháng 11 2018

a) 1 - 2y + y2

= (1-y)2

b) ( x + 1 )- 25

=( x + 1 )- 52

=(x+1+5)(x+1-5)

27 tháng 11 2018

c) 1 - 4x2

= 1- 2x2

=(1-2x)(1+2x)

30 tháng 8 2020

a) x2( x - 1 ) - x + 1

= x2( x - 1 ) - ( x - 1 )

= ( x - 1 )( x2 - 1 )

= ( x - 1 )( x - 1 )( x + 1 )

= ( x - 1 )2( x + 1 )

b) ( a + b )3 - ( a - b )3

= ( a3 + 3a2b + 3ab2 + b3 ) - ( a3 - 3a2b + 3ab2 - b3 )

= a3 + 3a2b + 3ab2 + b3 - a3 + 3a2b - 3ab2 + b3

= 6a2b + 2b3

= 2b( 3a2 + b )

c) 6x( x - 3 ) + 9 - 3x2

= 6x2 - 18x + 9 - 3x2

= 3x2 - 18x + 9

= 3( x2 - 6x + 3 )

d) x( x - y ) - 5x + 5y

= x( x - y ) - ( 5x - 5y )

= x( x - y ) - 5( x - y )

= ( x - y )( x - 5 )

e) 3( x + 4 ) - x2 - 4x

= 3( x + 4 ) - ( x2 + 4x )

= 3( x + 4 ) - x( x + 4 )

= ( x + 4 )( 3 - x )

f) x2 + 4x - y2 + 4

= ( x2 + 4x + 4 ) - y2

= ( x + 2 )2 - y2

= ( x + 2 - y )( x + 2 + y )

g) x2 + 5x

= x( x + 5 )

h) -x2 + 2x + 2y + y2

= ( y2 - x2 ) + ( 2x + 2y )

= ( y - x )( y + x ) + 2( x + y )

= ( x + y )( y - x + 2 )

27 tháng 11 2018

a. \(1-2y+y^2=\left(1-y\right)^2\)

b. \(\left(x+1\right)^2-25=\left(x+1+5\right)\left(x+1-5\right)=\left(x+6\right)\left(x-4\right)\)

c. \(1-4x^2=\left(1+2x\right)\left(1-2x\right)\)

d. \(8-27x^3=\left(2-3x\right)\left(4+6x+9x^2\right)\)

e. \(27+27x+9x^2+x^3=\left(x+3\right)^3\)

f, \(8x^3-12x^2y+6xy^2-y^3=\left(2x-y\right)^3\)

g, \(x^3+8y^3=\left(x+2y\right)\left(x^2-2xy+4y^2\right)\)

27 tháng 11 2018

\(\left(a\right)1-2y+y^2\)

\(\Leftrightarrow y^2-2y+1\)

\(\Leftrightarrow\left(y-1\right)^2\)

\(\left(b\right)\left(x+1\right)^2-25\)

\(\Leftrightarrow\left(x+1\right)^2-5^2\)

\(\Leftrightarrow\left(x-4\right)\left(x+6\right)\)

\(\left(c\right)1-4x^2\)

\(\Leftrightarrow1-\left(2x\right)^2\)

\(\Leftrightarrow\left(1-2x\right)\left(1+2x\right)\)

\(\left(d\right)8-27x^3\)

\(\Leftrightarrow2^3-\left(3x\right)^3\)

\(\Leftrightarrow\left(2-3x\right)\left(4+6x+9x^2\right)\)

\(\left(e\right)27+27x+9x^2+x^3\)

\(\Leftrightarrow\left(x+3\right)^3\)

\(\left(f\right)8x^3-12x^2y+6xy^2-y^3\)

\(\Leftrightarrow\left(2x\right)^3-12x^2y+6xy^2-y^3\)

\(\Leftrightarrow\left(2x-y\right)^3\)

\(\left(g\right)x^3+8y^3\)

\(\Leftrightarrow\left(x+2y\right)\left(x^2-2xy+4y^2\right)\)

25 tháng 5 2017

a) 2x2.(5x3-4x2y-7xy +1) =10x5-8x4y-14x3y+2x2 b) (5x -2y)(x2 -xy +1) =5x3-5x2y+5x-2x2y+2xy2-2y =5x3-7x2y+2xy2+5x-2y c) (\(\dfrac{1}{2}\)x -1)(2x -3) =x2-\(\dfrac{3}{2}\)x-2x+3 =x2-\(\dfrac{7}{2}\)x+3 d) (x +3y)2 =x2+6xy+9y2 e) (3x -2y)2 =9x2-12xy+4y2 g) (\(\dfrac{1}{4}\)x - 3y)(\(\dfrac{1}{4}\)x +3y) =\(\dfrac{1}{16}\)x2-9y2 f) (2x +3)3 =8x3+36x2+54x+27 h) (3 -2y)3 =27-54y+36y2-8y3

17 tháng 6 2017

b1:

câu a,f áp dụng a2-b2=(a-b)(a+b)

câu b,c áp dụng a3-b3=(a-b)(a2+ab+b2)

câu d: \(x^2+2xy+x+2y=x\left(x+2y\right)+\left(x+2y\right)=\left(x+1\right)\left(x+2y\right)\)

câu e: \(7x^2-7xy-5x+5y=7x\left(x-y\right)-5\left(x-y\right)=\left(7x-5\right)\left(x-y\right)\)

câu g xem lại đề

17 tháng 6 2017

b2:

\(f\left(x;y\right)=x^2+y^2-6x+5y+9=\left(x^2-6x+9\right)+\left(y^2+5y+\frac{25}{4}\right)-\frac{25}{4}\)

\(=\left(x-3\right)^2+\left(y+\frac{5}{2}\right)^2-\frac{25}{4}\ge-\frac{25}{4}\)

Dấu "=" xảy ra khi x=3 và y=-5/2

câu c làm tương tự

20 tháng 9 2017

a) 5x-15y=5x-3.5.y=5(x-3y)

c) 14xy(xy+28x)

d) \(\dfrac{2}{7}\left(3x-1\right)\left(x-1\right)\)

e) (x-1)3

f) (x+y-2x)(x+y+2x)=(y-x)(3x+y)

g) (3x+\(\dfrac{1}{2}\))(9x2+\(\dfrac{3}{2}x\)+\(\dfrac{1}{4}\))

h) (x+y-x+y)\(\left[\left(x+y\right)^2-\left(x+y\right)\left(x-y\right)+\left(x-y\right)^2\right]\)

20 tháng 9 2017

2a)

(x+1)(x2+2x)=0

(x+1)x(x+2)=0

\(\left[{}\begin{matrix}x+1=0\\x=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=0\\x=-2\end{matrix}\right.\)

7 tháng 10 2019

a) \(x^3+6x^2+12x+8\)

\(=\left(x+2\right)^3\)

b) \(x^3-3x^2+3x-1\)

\(=\left(x-1\right)^3\)

c) \(1-9x+27x^2-27x^3\)

\(=-\left(27x^3-27x^2+9x-1\right)\)

\(=-\left(3x-1\right)^3\)

7 tháng 10 2019

d) \(x^3+\frac{3}{2}x^2+\frac{3}{4}x+\frac{1}{8}\)

\(=\left(x+\frac{1}{2}\right)^3\)

e) \(27x^3-54x^2y+36xy^2-8y^3\)

\(=\left(3x-2y\right)^3\)