Câu hỏi của Nobly

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mong mọi người giúp mình

Lấp La Lấp Lánh · Accepted Answer

$\dfrac{\dfrac{3}{5}.7^2-3.5^6+\dfrac{3}{5}.3^9}{\dfrac{3}{4}.7^2-\dfrac{3}{4}.5^7+\dfrac{3}{4}.3^9}=\dfrac{\dfrac{3}{5}.7^2-\dfrac{3}{5}.5^7+\dfrac{3}{5}.3^9}{\dfrac{3}{4}.7^2-\dfrac{3}{4}.5^7+\dfrac{3}{4}.3^9}$

$=\dfrac{\dfrac{3}{5}\left(7^2-5^7+3^9\right)}{\dfrac{3}{4}\left(7^2-5^7+3^9\right)}=\dfrac{3}{5}:\dfrac{3}{4}=\dfrac{3}{5}.\dfrac{4}{3}=\dfrac{4}{5}$

Câu trả lời:

$\dfrac{\dfrac{3}{5}.7^2-3.5^6+\dfrac{3}{5}.3^9}{\dfrac{3}{4}.7^2-\dfrac{3}{4}.5^7+\dfrac{3}{4}.3^9}=\dfrac{\dfrac{3}{5}.7^2-\dfrac{3}{5}.5^7+\dfrac{3}{5}.3^9}{\dfrac{3}{4}.7^2-\dfrac{3}{4}.5^7+\dfrac{3}{4}.3^9}$

$=\dfrac{\dfrac{3}{5}\left(7^2-5^7+3^9\right)}{\dfrac{3}{4}\left(7^2-5^7+3^9\right)}=\dfrac{3}{5}:\dfrac{3}{4}=\dfrac{3}{5}.\dfrac{4}{3}=\dfrac{4}{5}$

Nguyễn Lê Phước Thịnh · Answer

$=\dfrac{3\left(\dfrac{1}{5}\cdot49-5^6+\dfrac{1}{5}\cdot3^9\right)}{3\left(\dfrac{1}{4}\cdot7^2-\dfrac{1}{4}\cdot5^7+\dfrac{1}{4}\cdot3^9\right)}=\dfrac{3\cdot\dfrac{-58393}{5}}{3\cdot\dfrac{-58393}{4}}$

$=\dfrac{4}{5}$

Câu trả lời:

$=\dfrac{3\left(\dfrac{1}{5}\cdot49-5^6+\dfrac{1}{5}\cdot3^9\right)}{3\left(\dfrac{1}{4}\cdot7^2-\dfrac{1}{4}\cdot5^7+\dfrac{1}{4}\cdot3^9\right)}=\dfrac{3\cdot\dfrac{-58393}{5}}{3\cdot\dfrac{-58393}{4}}$

$=\dfrac{4}{5}$

x	10	-2	-3	1	0	1.21	0.25
\(^{x^2}\)	100	4	9	1	0	1.4641	0.0625

1.44	-25	\(\dfrac{4}{9}\)
2.0736	625	\(\dfrac{16}{81}\)

Giá trị (x)	Tần số (n)	Các tích (x.n)
17	3	51
18	5	90
19	4	76
20	2	40
21	3	63
22	2	44
24	3	72
26	3	78
28	1	28
30	1	30
31	2	62
32	1	32	$\overline{X}$ = \(\dfrac{666}{30}=22,2\)
	N = 30	Tổng: 666

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