Question

[phan lạc gia hưng]

\(\dfrac{x-1}{65}\) + \(\dfrac{x-3}{63}\) = \(\dfrac{x-5}{61}\) + \(\dfrac{x-7}{59}\)

tìm x

Answer 1

[Nguyễn Lê Phước Thịnh]

\(\dfrac{x-1}{65}+\dfrac{x-3}{63}=\dfrac{x-5}{61}+\dfrac{x-7}{59}\)

=>\(\left(\dfrac{x-1}{65}-1\right)+\left(\dfrac{x-3}{63}-1\right)=\left(\dfrac{x-5}{61}-1\right)+\left(\dfrac{x-7}{59}-1\right)\)

=>\(\dfrac{x-66}{65}+\dfrac{x-66}{63}-\dfrac{x-66}{61}-\dfrac{x-66}{59}=0\)

=>x-66=0

=>x=66