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(1) CaC2 + 2H2O => C2H2 + Ca(OH)2
(2) C2H2 + H2 => (to,Pd) C2H4
(3) C2H4 + H2O => (to,H2SO4đ) C2H5OH
(4) C2H5OH + O2 => (men giấm) CH3COOH + H2O
(5) CH3COOH + C2H5OH => <pứ hai chiều> (xt:H2SO4đ, to) CH3COOC2H5 + H2O
\(\left(1\right)CaC_2+2H_2O\rightarrow Ca\left(OH\right)_2+C_2H_2\)
\(\left(2\right)C_2H_2+H_2\xrightarrow[to]{Ni}C_2H_4\)
\(C_2H_4+2H_2O\xrightarrow[30-35^oC]{men.rượu}C_2H_5OH+H_2O\)
\(C_2H_5OH+O_2\xrightarrow[men.giấm]{30-35^oC}CH_3COOH+H_2O\)
\(C_2H_5OH+CH_3COOH\xrightarrow[\leftarrow]{H_2SO_4đ,t^o}CH_3COOC_2H_5+H_2O\)
\((1) CaC_2 + 2H_2O \to Ca(OH)_2 + C_2H_2\\ (2) C_2H_2 + H_2 \xrightarrow{t^o,PbCO_3} C_2H_4\\ (3) C_2H_4 + H_2O \xrightarrow{t^o,H^+} C_2H_5OH\\ (4) C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ (5) CH_3COOH + C_2H_5OH \buildrel{{H_2SO_4}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O\)
1)(-C6H10O5-)n +nH2O -axit ;to-> nC6H12O6
2) C6H12O6 --men ; 30o-32oC--> 2C2H5OH + 2CO2
3) C2H5OH + 3O2 -to-> 2CO2 + 3H2O
4) CO2 + 2NaOH -> Na2CO3 + H2O
5) Na2CO3 + 2CH3COOH -> 2CH3COONa + H2O + CO2
6) 2C2H5OH + 2Na -> 2C2H5ONa + H2
7) C2H5OH + CH3COOH -> H2O + CH3COOC2H5
(đk: H2SO4 đ ; to)
(1) (C6H10O5)n + nH2O => nC6H12O6
(2) C6H12O6 => (men rượu, to) 2CO2 + 2C2H5OH
(3) C2H5OH + 3O2 => (to) 2CO2 + 3H2O
(4) CO2 + 2NaOH => Na2CO3 + H2O
(5) Na2CO3 + 2CH3COOH => 2CH3COONa + CO2 + H2O
(6) C2H5OH + Na => C2H5ONa + 1/2 H2
(7) C2H5OH + CH3COOH => (to,xt: H2SO4đ) <pứ hai chiều> CH3COOC2H5 + H2O
g) 1. Fe2O3 + 6HCl → 2FeCl3 + 3H2O
2. FeCl3 + 3NaOH → 3NaCl + Fe(OH)3↓
3. 2Fe(OH)3 \(\underrightarrow{to}\) Fe2O3 + 3H2O
4. Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O
h) 1. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2↓
2. Zn(OH)2 + 2HCl → ZnCl2 + 2H2O
3. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2↓
4. NaCl + AgNO3 → NaNO3 + AgCl↓
1/ C2H4 + H2O => (140o,H2SO4đ) C2H5OH
C2H5OH + O2 => (men giấm) CH3COOH + H2O
CH3COOH + C2H5OH => (H2SO4đ,to) <pứ hai chiều> CH3COOC2H5 + H2O
CH3COOC2H5 + NaOH => (to) CH3COONa + C2H5OH
2/ C6H12O6 => (men rượu,to) 2CO2 + 2C2H5OH
C2H5OH + O2 => (men giấm) CH3COOH + H2O
2CH3COOH + CaCO3 => (CH3COO)2Ca + CO2 + H2O
3/ CaC2 + 2H2O => Ca(OH)2 + C2H2
C2H2 + H2 => (Pd, to) C2H4
C2H4 + 1/2 O2 => (xt,P,to) CH3CHO
CH3CHO + 1/2 O2 => CH3COOH
1) Al\(_2\)(SO\(_4\))\(_3\)+3BaCl\(_2\)→2AlCl\(_3\)+3BaSO\(_4\)↓
2)AlCl\(_3\)+3AgNO\(_3\)→Al(NO\(_3\))\(_3\)+3AgCl↓
3)Al(NO\(_3\))\(_3\)+3NaOH→Al(OH)\(_3\)+3NaNO\(_3\)
4)2Al(OH)\(_3\)\(\underrightarrow{to}\)Al2O3+3H2O
5)2Al2O3\(\xrightarrow[criolit]{đpnc}\)4Al+3O2
a) 1: Na + O2 \(\rightarrow\) Na2O
2: Na2O + H2O \(\rightarrow\) 2NaOH
3: NaOH + SO3 \(\rightarrow\) Na2SO4 + H2O
4: Na2SO4 + BaCl2 \(\rightarrow\) NaCl + BaSO4
b) 1: CaO + H2O \(\rightarrow\) Ca(OH)2
2: Ca(OH)2 + H2CO3 \(\rightarrow\) CaCO3 + 2H2O
3: CaCO3 \(\underrightarrow{t^o}\) CaO + CO2
4: CaO + HCl \(\rightarrow\) CaCl2 + H2O
CaO+H2O--->Ca(OH)2
Ca(OH)2+ 2HCl--->CaCl2+2H2O
CaCl2+ MgCO3---->CaCO3+MgCl2
CaCO3+2HCl---->CaCl2+H2O+CO2
CaCl2+2NaOH---->Ca(OH)2+2NaCl
Ca(OH)2+CO2--->CaCO3+H2O
CaCO3---->CaO+CO2
CÁI NÀY HƠI BỊ KHÓ HIỂU NHƯNG MÌNH SẼ LÀM THỬ ( THEO THỨ TỰ ) :
\(\left(1\right)Al_4C_3+12H_2O\rightarrow4Al\left(OH\right)_3+3CH_4.\)
\(\left(2\right)2CH_4\underrightarrow{1500^o}C_2H_2+3H_2.\)
\(\left(3\right)CaC_2+2H_2O\rightarrow Ca\left(OH\right)_2+C_2H_2.\)
\(\left(4\right)C_2H_2+H_2\underrightarrow{Ni,t^o}C_2H_4.\)
\(\left(5\right)C_2H_4+Br_2\rightarrow C_2H_4Br_2.\)
\(\left(6\right)C_2H_4+H_2O\underrightarrow{axit}C_2H_5OH.\)
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