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2NaOH + Cu(NO3)2 -> Cu(OH)2 + 2NaNO3
AgNO3 + HCl -> AgCl + HNO3
K2SO4 + Ba(NO3)2 -> BaSO4 + 2KNO3
Mg + H2SO4 -> MgSO4 + H2
a) CaCO3\(\rightarrow\)CaO(A)+CO2(P)
CaO+H2O(B)\(\rightarrow\)Ca(OH)2(C)
Ca(OH)2+2HCl(D)\(\rightarrow\)CaCl2(E)+2H2O
CaCl2+K2CO3(F)\(\rightarrow\)CaCO3+2KCl
CO2+NaOH(X)\(\rightarrow\)NaHCO3(Q)
2NaHCO3+2KOH(Y)\(\rightarrow\)Na2CO3+K2CO3(R)+2H2O
K2CO3+Ca(NO3)2(Z)\(\rightarrow\)CaCO3+2KNO3
CaO+H2O---->Ca(OH)2
Pt2 ko ổn lw
Na2CO3+2HCl----->2NaCl+H2O+CO2
2NaCl+H2SO4---->Na2SO4+2HCl
Na2SO4+BaCl2---->2NaCl+BaSO4
2NaCl+2H2O---->Cl2+H2+2NaOH
NaOH+HCl----->NaCl+H2O
2NaCl+H2SO4---->Na2SO4+2HCl
a.PTHH: Al+ FeCl3----> AlCl3+ Fe
Al+ CuCl2----> AlCl3+Cu
Al+ 6HCl----> AlCl3+ 3H2
b. Tính từng cái suy ra.
Fe2O3+3H2->2Fe+3H2O
Fe+2HCl->FeCl2+H2
FeCl2+2NaOH->Fe(OH)2+2NaCl
Fe(OH)2+MgSO4->FeSO4+Mg(OH)2
2FeCl2+Cl2->2FeCl3
FeCl3+3NaOH->Fe(OH)3+3NaCl
2Fe(OH)3->Fe2O3+H2O
Viết các PTHH theo chuỗi phản ứng.
\(\left(1\right)Fe_2O_3+3H_2\rightarrow2Fe+3H_2O\)
\(\left(2\right)Fe+2HCl\rightarrow FeCl_2+H_2\uparrow\)
\(\left(3\right)FeCl_2+Ba\left(OH\right)_2\rightarrow Fe\left(OH\right)_2\downarrow+BaCl_2\)
\(\left(4\right)Fe\left(OH\right)_2+H_2SO_4\rightarrow FeSO_4+2H_2O\)
\(\left(5\right)2Fe+3Cl_2\rightarrow2FeCl_3\)
\(\left(6\right)FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3\downarrow+3NaCl\)
\(\left(7\right)2Fe\left(OH\right)_3\underrightarrow{t^o}Fe_2O_3+3H_2O\)
\(\left(1\right)C_3H_8\rightarrow CH_4+C_2H_4\left(đk:t^o\right)\)
\(\left(2\right)CH_4+Cl_2\rightarrow CH_3Cl+HCl\left(đk:as\right)\)
\(\left(3\right)CH_3Cl+NaOH\rightarrow CH_3OH+NaCl\left(đk:t^o\right)\)
\(\left(4\right)CH_3OH+CuO\rightarrow HCHO+Cu+H_2O\left(đk:t^o\right)\)
\(\left(5\right)HCHO+\dfrac{1}{2}O_2\rightarrow HCOOH\left(đk:xtMnO_2\right)\)
\(\left(6\right)HCOOH+2\left(Ag\left(NH_3\right)_2\right)OH\rightarrow\left(NH_4\right)_2CO_3+2Ag\downarrow+2H_2O+2NH_3\uparrow\)
\(\left(7\right)\left(NH_4\right)_2CO_3+2HCl\rightarrow2NH_4Cl+H_2O+CO_2\uparrow\)
\(\left(8\right)\left(NH_4\right)_2CO_3+2NaOH\rightarrow Na_2CO_3+2NH_3\uparrow+H_2O\)
@Rainbow