Question

[Nguyễn Thị Hồng Anh]

help me

1) \(\frac{3-7x}{1+x}=\frac{1}{2}\)

2)\(\frac{x+1}{x-2}=\frac{1}{x^2-4}\)

3) \(\frac{y-1}{y-2}-\frac{5}{y+2}=\frac{12}{y^2-4}+1\)

4) \(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{4}{x^2+1}\)

5) \(1+\frac{1}{x+2}=\frac{12}{8-x^3}\)

6) \(\frac{x}{x-1}-\frac{2x}{x^2-1}=0\)

7) \(\frac{2x}{x+2}-\frac{x}{x-2}=\frac{-4x}{x^2-4}\)

8) \(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)

9) \(\frac{3}{1-4x}=\frac{2}{4x+1}-\frac{8+6x}{16x^2-1}\)

10) \(\frac{2x-3}{x+2}-\frac{x+2}{x-2}=\frac{2}{x^2-4}\)

11)\(\frac{x-1}{x+2}-\frac{x}{x-2}=\frac{5x-2}{4-x^2}\)

12)\(\frac{1}{x+1}-\frac{5}{x-2}=\frac{15}{\left(x+1\right)\left(2-x\right)}\)

Answer 1

[le bao truc]

bài 1

\(ĐKXĐ:1+x\ne0\Rightarrow x\ne-1\)
\(\frac{3-7x}{1+x}=\frac{1}{2}\Rightarrow2\left(3-7x\right)=1+x\)
\(\Leftrightarrow6-14x=1+x\\ \Leftrightarrow-14x-x=1-6\\ \Leftrightarrow-15x=-5\\ \Leftrightarrow x=\frac{1}{3}\left(N\right)\)