Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, x2 + x - 6
= x2 + 3x - 2x - 6
= x(x + 3) - 2(x + 3)
= (x + 3)(x - 2)
b, x2 - 2x - 15
= x2 - 5x + 3x -15
= x(x - 5) + 3(x - 5)
= (x + 3)(x - 5)
c,4x2 - 12x - 160
= 4x2 - 32x + 20x - 160
= 4x(x - 8) + 20(x - 8)
= (4x + 20)(x - 8)
d, 5x2y - 10xy - 15y
= y(5x2 - 10x - 15)
= y(5x2 - 15x + 5x - 15)
= y(5x(x - 3) + 5(x - 3)
= y(5x + 5)(x - 3)
a)5x2y-10xy2
=5xy(x-2y)
b,:4x(2y-z)+7y(z-2y)
=4x(2y-z)-7y(2y-z)
=(2y-z)(4x-7y)
c,:y(x-z)+7(z-x)
=y(x-z)-7(x-z)
=(x-z)(y-7)
d)36-12x+x^2
=x2-2.x.6+62
=(x-6)2
e) (x-5)^2-16
=(x-5)2-42
=(x-5-4)(x-5+4)
=(x-9)(x-1)
f) 8x^3+1/27
=(2x)3+(1/3)3
=(2x+1/3)(4x2+2/3.x+1/9)
c, x4+6x3+11x2+6x+1
=x4+6x3+9x2+2x2+6x+1
=x4+9x2+1+6x3+2x2+6x
=(x2)2+(3x)2+12+2.x2.3x+2.x2.1+2.3x.1 (1)
Áp dụng hằng đẳng thức (a+b+c)2=a2+b2+c2+2ab+2ac+2bc
=> (1)=(x2+3x+1)2
Câu a nhé bạn:
a, 3x2−22xy−4x+8y+7y2+1
=3x2-21xy-xy-3x-x+7y+y+7y2+1
=(3x2−21xy−3x)−(xy-7y2-y)−(x-7y-1)
=3x(x−7y−1)−y(x−7y−1)−(x−7y−1)
=(3x−y−1)(x−7y−1)
a) \(-5x-10xy-15y=-5\left(x+2xy+3y\right) \)
b) \(3a^2x-ba^2y+12a=a\left(3ax-bay+12\right) \)
c) \(2\left(x-y\right)-a\left(y-x\right)=\left(2+a\right)\left(x-y\right) \)
d) \(3a\left(x-y\right)-a^2\left(y-x\right)=\left(3a+a^2\right)\left(x-y\right) \)
c ) \(4x^2-12x-160\)
\(=4x^2-32x+20x-160\)
\(=4x\left(x-8\right)+20\left(x-8\right)\)
\(=4.x\left(x-8\right)+4.5\left(x-8\right)\)
\(=4\left(x+5\right)\left(x-8\right)\)
d ) \(5x^2y-10xy-15y\)
\(=y\left(5x^2-10x-15\right)\)
\(=y\left(5x^2-15x+5x-15\right)\)
\(=y\left[5x\left(x-3\right)+5\left(x-3\right)\right]\)
\(=y\left[5.x\left(x-3\right)+5\left(x-3\right)\right]\)
\(=y.\left[5.\left(x+1\right)\left(x-3\right)\right]\)
\(=5y.\left(x+1\right)\left(x-3\right)\)