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a) \(\left(x^2-2x+1\right)-\left(y^2+2y+1\right)\)
\(=\left(x-1\right)^2-\left(y+1\right)^2\)
\(=\left(x-y-2\right)\left(x+y\right)\)
a. 2x-1-x2= -(x2-2x+1)=-(x-1)2
b. 8x3+y6=(2x)3+(y2)3
=(2x+y2)(4x2-2xy2+y4)
c. x2-16+4xy+4y2=(x2+4xy+4y2)-16
=(x+2y)2-16=(x+2y+4)(x+2y-4)
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
a) xy – 3x + 2y – 6
= (xy - 3x) + (2y - 6)
= x(y - 3) + 2(y - 3)
= (y - 3)(x + 2)
b) x2y + 4xy + 4y – y3
= y(x2 + 4x + 4 - y2)
= y[(x2 + 4x + 4) - y2]
= y[(x + 2)2 - y2]
= y(x + 2 + y)(x + 2 - y)
c) x2 + y2 + xz + yz + 2xy
= (x2 + 2xy + y2) + (xz + yz)
= (x + y)2 + z(x + y)
= (x + y)(x + y + z)
d) x3 + 3x2 – 3x – 1
= (x3 - 1) + (3x2 - 3x)
= (x - 1)(x2 + x + z) + 3x(x - 1)
= (x - 1)(x2 + 4x + 1)
a )
\(xy-3x+2y-6\)
\(=\left(xy+2y\right)-3x-6\)
\(=y\left(x+2\right)-3\left(x+2\right)\)
\(=\left(y-3\right)\left(x+2\right)\)
b )
\(x^2y+4xy+4y-y^3\)
\(=y\left(x^2+4x+4-y^2\right)\)
\(=y\left[\left(x+2\right)^2-y^2\right]\)
\(=y\left(x+2-y\right)\left(x+2+y\right)\)
c )
\(x^2+y^2+xz+yz+2xy\)
\(=\left(x+y\right)^2+z\left(x+y\right)\)
\(=\left(x+y\right)\left(x+y+z\right)\)
b = x.(x2 + 6x + 9 - 4y2 ) =x.((x+3)2 -4y2 )= x.(x+3-2y).(x+3+2y)
c = (x2 - 2x)+(2y-xy) = x.(x-2) +y.(2-x)= x.(x-2) + y.(-x+2)= x.(x-2) - y.(x-2) = (x-y).(x-2)
d = (x2 +1)2 - 4x2 = (x2 + 1 - 2x).(x2 +1 +2x) = (x-1)2 . (x+1)2
a = (7x)2 - (0.5y)2 = (7x - 0,5y).(7x+0,5y)
a) x^4 - x^3 - x + 1
= x^3 ( x - 1 ) - ( x- 1 )
= ( x^3 - 1 )(x - 1)
= ( x- 1 )^2 (x^2 + x + 1 )
a)x4-x3-x+1
=x3(x-1)-(x-1)
=(x-1)(x3-1)
=(x-1)(x-1)(x2+x+1)
=(x-1)2(x2+x+1)
b)5x2-4x+20xy-8y
(sai đề)
Câu 1: (2x+y)(y-2x)+4x2=y2-4x2+4x2=y2
Với y=10 giá trị biểu thức trên là 102=100
Câu 2:
a. xy-11x=x.(y-11)
b. x2+4y2+4xy-16=(x2+4xy+4y2)-16
=(x+2y)2-16=(x+2y+4)(x+2y-4)
a) xy + y2 - x - y
= ( xy – x ) + ( y^2 – y )
= x (y – 1) + y (y – 1)
= (y – 1) (x + y)
b) 25 – x^2 + 4xy - 4y^2
= 5^2 – (x^2 – 4xy + 4y^2)
= 5^2 – (x – 2y)^2
= (5 – x + 2y)(5 + x – 2y)
Tik mình với
c) 2x^3y - 2xy^3 - 4xy^2 - 2xy
= 2xy ( x^2 - y^2 - 2y - 1 )
= 2xy ( x^2 - ( y^2 + 2y + 1 )
= 2xy ( x^2 - ( y + 1 )^2 )
= 2x ( x - y - 1 )( x + y + 1 )
sai bạn ơi !
đáp án là
= 2xy (x + y + 1) (x - y + 1)
that pun cho ban Nguyen Dieu Thao :((
a,\(x^2-2x+2y-xy\)
\(=\left(x^2-xy\right)+\left(-2x+2y\right)\)
\(=x\left(x-y\right)-2\left(x-y\right)\)
\(=\left(x-2\right)\left(x-y\right)\)
a. \(x^2-2x+2y-xy=\left(x^2-2x\right)-\left(xy-2y\right)=x\left(x-2\right)-y\left(x-2\right)=\left(x-2\right)\left(x-y\right)\)
b. \(x^2+4xy-16+4y^2=\left(x^2+4xy+4y^2\right)-16=\left(x+2y\right)^2-4^2=\left(x+2y-4\right)\left(x+2y+4\right)\)
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