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1a) \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)
b) \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)
\(a,=-\left(x-1\right)^3\left[=\left(1-x\right)^3\right]\\ b,=\left(1-x\right)^3\)
a: \(ab+a+b+1\)
\(=a\left(b+1\right)+\left(b+1\right)\)
\(=\left(b+1\right)\left(a+1\right)\)
c: \(4x^2-12xy+3x-9y\)
\(=4x\left(x-3y\right)+3\left(x-3y\right)\)
\(=\left(x-3y\right)\left(4x+3\right)\)
Bài này sử dụng \(a^2-b^2=\left(a-b\right)\left(a+b\right).\)
a) \(4b^2c^2-\left(b^2+c^2-a^2\right)^2=\left(2bc-b^2-c^2+a^2\right)\left(2bc+b^2+c^2-a^2\right)\)
\(=\left(a^2-\left(b-c\right)^2\right)\left(\left(b+c\right)^2-a^2\right)=\left(a-b+c\right)\left(a+b-c\right)\left(a+b+c\right)\left(b+c-a\right)\)
b) \(\left(4x^2-3x-18\right)^2-\left(4x^2+3x\right)^2=\left(4x^2-3x-18-4x^2-3x\right)\left(4x^2-3x-18+4x^2+3x\right)\)
\(=\left(-6x-18\right)\left(8x^2-18\right)=-12\left(x+3\right)\left(4x^2-9\right)=-12\left(x+3\right)\left(2x-3\right)\left(2x+3\right).\)
c) \(\left(4abcd+\left(a^2+b^2\right)\left(c^2+d^2\right)\right)^2-4\left(cd\left(a^2+b^2\right)+ab\left(c^2+d^2\right)\right)^2\)
\(=\left(4abcd+\left(a^2+b^2\right)\left(c^2+d^2\right)-2cd\left(a^2+b^2\right)-2ab\left(c^2+d^2\right)\right)\times\)
\(\times\left(4abcd+\left(a^2+b^2\right)\left(c^2+d^2\right)+2cd\left(a^2+b^2\right)+2ab\left(c^2+d^2\right)\right)\)
\(=\left(\left(a^2+b^2\right)\left(c-d\right)^2-2ab\left(c-d\right)^2\right)\times\left(\left(a^2+b^2\right)\left(c+d\right)^2+2ab\left(c+d\right)^2\right)\)
\(=\left(c-d\right)^2\cdot\left(a-b\right)^2\cdot\left(a+b\right)^2\cdot\left(c+d\right)^2.\)
a/ \(4x^2-9\)
\(=\left(2x-3\right)\left(2x+3\right)\)
b/ \(3x\left(3x-2\right)+1\)
\(=9x^2-6x+1\)
\(=\left(3x-1\right)^2\)
\(a,=\left(2x-3\right)\left(2x+3\right)\)
\(b,=9x^2-6x+1=\left(3x-1\right)^2\)
a) \(5x^3-10x^2+15x=5x\left(x^2-2x+3\right)\)
b) \(x^2-3x+2=x\left(x-2\right)-\left(x-2\right)=\left(x-2\right)\left(x-1\right)\)
a. \(x^2\) - 9y2
= (\(x\))2 - (3y)2
= (\(x\) - 3y)(\(x\) + 3y)
a) 4x2 - 3x - 1 = 3x2 -3x + x2 - 1= 3x(x-1) + (x-1)(x+1) = (x-1)(3x +x+1)= (x-1)(4x+1)
b) chưa biết làm :)
(a^3x-x)-(ab+b)=x(a^3-1)-b(a-1)=x(a-1)(a^2+ab+1)-b(a-1)=(a-1)(a^2x+abx+x-a+1)