Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
,2x^2-12x+18+2xy-6y
= 2(x^2-6x+9) + 2y(x-3)
= 2(x-3)^2 + 2y(x-3)
= (x-3)(2x-6+2y)
bài 1:= \(2x\left(x-3\right)-6\left(x-3\right)+2y\left(x-3\right)\)
=\(2\left(x-3\right)\left(x+y-3\right)\)
bài 2:P=\(x^2-2x+1+y^2+6y+9+2\)
P=\(\left(x-1\right)^2+\left(y+3\right)^2+2\ge2\)
vậy Pmin=2 khi x=1 và y=-3
a) \(9x^2-12x+4\)
\(=9x^2-6x-6x+4\)
\(=3x\left(3x-2\right)-2\left(3x-2\right)\)
\(=\left(3x-2\right)^2\)
b) \(2xy+16-x^2-y^2\)
\(=-\left(x^2-2xy+y^2-16\right)\)
\(=-\left(x-y\right)^2+16\)
\(=\left(4-x+y\right)\left(4+x-y\right)\)
c) \(3x+2x^2-2\)
\(=2x^2+4x-x-2\)
\(=2x\left(x+2\right)-\left(x+2\right)=\left(x+2\right)\left(2x-1\right)\)
\(36x^2-9y^2-12x-6y\)
\(=\left(36x^2-12x+1\right)-\left(9y^2+6y+1\right)\)
\(=\left(6x-1\right)^2-\left(9y+1\right)\)
\(=\left(6x+9y\right)\left(6x-3y-2\right)\)
\(=3\left(2x+3y\right)\left(6x-3y-2\right)\)
a/
\(=2\left(x^2-6x+9\right)+2y\left(x-3\right)\)
\(=2\left(x-3\right)^2+2y\left(x-3\right)\)
\(=2\left(x-3\right)\left(x-3+2y\right)\)
b/
\(=x^2-4y^2+4\left(x+2y\right)\)
\(=\left(x-2y\right)\left(x+2y\right)+4\left(x+2y\right)\)
\(=\left(x+2y\right)\left(x-2y+4\right)\)
2x2-12x+18+2xy-6y=2(x2-6x+9+xy-3y)=2[(x2-6x+9)+(xy-3y)]=2[(x-3)2+y(x-3)]=2(x-3)(x+y-3)
2x2-12x+18+2xy-6y
=2(x2-6x+9+xy-3y)
=2 [(x2-6x+9)+(xy-3y)]
=2 (x-3)2+y(x-3)
=2(x-3)(x-3+y)