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25 tháng 12 2021
\(a,=5\left(x^2+2xy+y^2\right)-10y^2+5=5\left(x+y\right)^2-10y^2+5\\ =5\left(1+2\right)^2-10\cdot4+5=45-40+5=10\\ b,=7\left(x-y\right)-\left(x-y\right)^2=\left(x-y\right)\left(7-x+y\right)\\ =\left(2-2\right)\left(7-2+2\right)=0\)
25 tháng 12 2021
b: \(=7\left(x-y\right)-\left(x-y\right)^2\)
\(=\left(x-y\right)\left(7-x+y\right)=0\)
25 tháng 1 2022
a: \(=3\left[\left(m-5\right)^3+8\right]\)
\(=3\left(m-5+2\right)\left[\left(m-5\right)^2-2\left(m-5\right)+4\right]\)
\(=3\left(m-3\right)\left(m^2-10m+25-2m+10+4\right)\)
\(=3\left(m-3\right)\left(m^2-12m+39\right)\)
b: \(=5\left(1-6k\right)^3-5\cdot64\)
\(=5\left(1-6k-4\right)\left[\left(1-6k\right)^2+4\left(1-6k\right)+16\right]\)
\(=5\left(-6k-3\right)\left(36k^2-12k+1+4-24k+16\right)\)
\(=-15\left(2k+1\right)\left(36k^2-36k+21\right)\)
\(=-45\left(2k+1\right)\left(12k^2-12k+7\right)\)
c: \(=\left(a+b-2b+a\right)\left[\left(a+b\right)^2+\left(a+b\right)\left(2b-a\right)+\left(2b-a\right)^2\right]\)
\(=\left(2a-b\right)\left(a^2+2ab+b^2+2ab-a^2+2b^2-ab+4b^2-4ab+b^2\right)\)
\(=\left(2a-b\right)\cdot b\cdot\left(6b+a\right)\)
15 tháng 10 2023
2:
a: \(9x^2-1=\left(3x\right)^2-1=\left(3x-1\right)\left(3x+1\right)\)
b: \(2\left(x-1\right)+x^2-x\)
\(=2\left(x-1\right)+x\left(x-1\right)\)
\(=\left(x-1\right)\left(x+2\right)\)
c: \(3x^2+14x-5\)
\(=3x^2+15x-x-5\)
\(=3x\left(x+5\right)-\left(x+5\right)=\left(x+5\right)\left(3x-1\right)\)
3:
a: \(2x\left(x-1\right)-2x^2=4\)
=>\(2x^2-2x-2x^2=4\)
=>-2x=4
=>x=-2
b: \(x\left(x-3\right)-\left(x+2\right)\left(x-1\right)=5\)
=>\(x^2-3x-\left(x^2+x-2\right)=5\)
=>\(x^2-3x-x^2-x+2=5\)
=>-4x=3
=>x=-3/4
c: \(4x^2-25+\left(2x+5\right)^2=0\)
=>\(\left(2x-5\right)\left(2x+5\right)+\left(2x+5\right)^2=0\)
=>\(\left(2x+5\right)\left(2x-5+2x+5\right)=0\)
=>4x(2x+5)=0
=>\(\left[{}\begin{matrix}x=0\\x=-\dfrac{5}{2}\end{matrix}\right.\)
31 tháng 8 2021
Câu 3:
a: \(49^2=2401\)
b: \(51^2=2601\)
c: \(99\cdot100=9900\)
T
1
H9
HT.Phong (9A5)
CTVHS
22 tháng 7 2023
a) \(x\left(x-1\right)+\left(1-x\right)^2\)
\(=x\left(x-1\right)+\left(x-1\right)^2\)
\(=\left(x-1\right)\left(x+x-1\right)\)
\(=\left(x-1\right)\left(2x-1\right)\)
b) \(\left(x+1\right)^2-3\left(x+1\right)\)
\(=\left(x+1\right)\left[\left(x+1\right)-3\right]\)
\(=\left(x+1\right)\left(x+1-3\right)\)
\(=\left(x+1\right)\left(x-2\right)\)
c) \(2x\left(x-2\right)-\left(x-2\right)^2\)
\(=\left(x-2\right)\left[2x-\left(x-2\right)\right]\)
\(=\left(x-2\right)\left(2x-x+2\right)\)
\(=\left(x-2\right)\left(x+2\right)\)
20 tháng 10 2021
a: \(x^4+2x^3+x^2=x^2\left(x+1\right)^2\)
b: \(5x^2+5xy-x-y\)
\(=5x\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(5x-1\right)\)
\(\left(\frac{1}{2}x-0,5\right)^2=\left(\frac{1}{2}x-\frac{1}{2}\right)^2=\frac{1}{4}x^2-\frac{1}{2}x+\frac{1}{4}\)
\(\left(2x+5y\right)^3=\left(2x\right)^3+3.\left(2x\right)^2.5y+3.2x.\left(5y\right)^2+\left(5y\right)^3=8x^3+60x^2y+150xy^2+125y^3\)
Tham khảo nhé~
a) (1/2x - 0,5)2 = 1/4x2 - 1/2x + 1/4
b) (2x+5y)3 = 8x3 + 60x2y + 150xy2 + 125y3
phân tích như z ak bn