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\(5x^3-5x^2y-10x^2+10xy=5x^2\left(x-y\right)-10x\left(x-y\right)=5x\left(x-2\right)\left(x-y\right)\)
ta có :
\(x^2-5x+5y-y^2=\left(x^2-y^2\right)-5\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y-5\right)\)
5x2 - 10xy + 5y2 - 20z2
=5(x2 - 2xy + y2 - 4z2)
= 5[ (x2 - 2xy + y2) - (2z)2]
= 5[(x-y)2 - (2z)2]
= 5(x-y-2z)(x-y+2z)
5x2-10xy+5y2-20z2
=5(x2-2xy+y2-4z2)
=5[(x-y)2-(2z)2]
=5(x-y-2z)(x-y+2z)
x2 - 2xy - 4z2 + y2
= (x2 - 2xy+y2) - (2z)2
= (x-y)2- (2z)2
= (x-y-2z)(x-y+2z)
x2-2xy-4z2+y2
=(x2-2xy+y2)-(2z)2
=(x-y)2-(2z)2
=(x-y-2z)(x-y+2z)
x3 - 3x2 - 4x + 12
= x2(x-3) - 4(x-3)
= (x-3)(x2 -4)
=(x-3)(x-2)(x+2)
\(x^3-3x^2-4x+12\)
\(=\left(x^3-3x^2\right)-\left(4x-12\right)\)
\(=x^2\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x^2-4\right)\left(x-3\right)\)
\(=\left(x-2\right)\left(x+2\right)\left(x-3\right)\)
x2 + 5x - 6 = (x2 + 6x) - (x + 6) = x(x + 6) - (x + 6)
= (x + 6)(x - 1)
x2 + 5x - 6
= (x2 + 6x) - (x + 6)
= x(x + 6) - (x + 6)
= (x + 6)(x - 1)