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\(A=2x^2-5xy-3y^2\)
\(A=2x^2-6xy+xy-3y^2\)
\(A=2x\left(x-3y\right)+y\left(x-3y\right)\)
\(A=\left(x-3y\right)\left(2x+y\right)\)
mk dùng p2 tách hạng tử ko bt đúng ko nha
A = x^2 - 4x -5
A = x^2 - 4x - x -4
A = x ( x - 1 ) - 4( x - 1)
A = ( x -1 ) . (x - 4)
câu b chờ mk suy nghĩ
\(=x^3-3x^2+6x^2-18x+8x-24\\ =\left(x-3\right)\left(x^2+6x+8\right)\\ =\left(x-3\right)\left(x^2+2x+4x+8\right)\\ =\left(x-3\right)\left(x+2\right)\left(x+4\right)\)
\(x^3+3x^2-10x-24=\left(x^3-3x^2\right)+\left(6x^2-18x\right)+\left(8x-24\right)=x^2\left(x-3\right)+6x\left(x-3\right)+8\left(x-3\right)=\left(x-3\right)\left(x^2+6x+8\right)=\left(x-3\right)\left[\left(x^2+2x\right)+\left(4x+8\right)\right]=\left(x-3\right)\left[x\left(x+2\right)+4\left(x+2\right)\right]=\left(x-3\right)\left(x+2\right)\left(x+4\right)\)
ko ghi lại đề nha:
=(5x2-10x)+5y2-5z
=5(x-2)+5y2-5z
mk chỉ làm đc đến đây thôi
a) \(-10x^2-17x+6\)
\(=-10x^2-20x+3x+6\)
\(=-10x\left(x+2\right)+3\left(x+2\right)\)
\(=\left(x+2\right)\left(3-10x\right)\)
b)\(x^2-10x+9\)
\(=x^2-x-9x+9\)
\(=x\left(x-1\right)-9\left(x-1\right)\)
\(=\left(x-1\right)\left(x-9\right)\)
c) \(x^2-10x+24\)
\(=x^2-4x-6x+24\)
\(=x\left(x-4\right)-6\left(x-4\right)\)
\(=\left(x-4\right)\left(x-6\right)\)
a: \(4x^2-x-5=\left(4x-5\right)\left(x+1\right)\)
b: \(x^2-2x-15=\left(x-5\right)\left(x+3\right)\)
x^2 - 10x + 24
= x^2 - 4x - 6x + 24
= x(x - 4) - 6(x - 4)
= (x - 6)(x - 4)
a) \(-10x^3+2x^2=0\)
\(\Rightarrow-2x^2\left(5x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{5}\end{matrix}\right.\)
b) \(5x\left(x-2016\right)-x+2016=0\)
\(\Rightarrow5x\left(x-2016\right)-\left(x-2016\right)=0\)
\(\Rightarrow\left(x-2016\right)\left(5x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=2016\\x=\dfrac{1}{5}\end{matrix}\right.\)
a: Ta có: \(-10x^3+2x^2=0\)
\(\Leftrightarrow-2x^2\left(5x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{5}\end{matrix}\right.\)
c1: x2-10x+24=(x2-2.x.5+52)-1=(x-5)2-1=(x-5-1)(x-5+1)=(x-6)(x-4)
c2: x2-10x+24=x2-4x-6x+24=x(x-4)-6(x-4)=(x-6)(x-4)
c1 =x2-6x-4x+24
=x(x-6)-4(x-6)
=(x-4)(x-6)
c2 =x2-10x+25-1
=(x-5)2-1
=(x-5-1)(x-5+1)
=(x-6)(x-4)