Question

[quynh le]

PHân tích đa thức thành nhân tử

A, x^3 - 4x^2 - 8x + 8

b, 6x^3 - x^2 - 486x + 81

c, x^(x^2 + 4) - x^2 + 4

d, x^4 - x^2 +4x - 1

e, x^(x + 4 ) - ( x + 4)^2 - ( x^2 - 1)

Answer 1

[Ran Mori]

\(x^3-4x^2-8x+8\)

\(=x^3+2x^2-6x^2-12x+4x+8\)

\(=x^2\left(x+2\right)-6x\left(x+2\right)+4\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2-6x+4\right)\)