Question

[Nguyễn Thuỳ Linh]

phân tích đa thức thành nhân tử;

a. (x-9)(x-7)+1

b.x³+2x²-3x-6

c.x²-y²+xz-yz

d.x³-x+3x²y+y³-y

Answer 1

[Minh Nguyen]

a) \(\left(x-9\right)\left(x-7\right)+1\)

\(=x^2-16x+63+1\)

\(=x^2-16x+64\)

\(=\left(x-8\right)^2\)

b) \(x^3+2x^2-3x-6\)

\(=x^2\left(x+2\right)-3x\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2-3x\right)\)

\(=x\left(x+2\right)\left(x-3\right)\)

c) \(x^2-y^2+xz-yz\)

\(=x\left(x+z\right)-y\left(y+z\right)\)

\(=\left(x-y\right)\left(y+z\right)\)

d) \(x^3-x+3x^2y+y^3-y\)

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