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a) \(9x^2-12x+4\)
\(=9x^2-6x-6x+4\)
\(=3x\left(3x-2\right)-2\left(3x-2\right)\)
\(=\left(3x-2\right)^2\)
b) \(2xy+16-x^2-y^2\)
\(=-\left(x^2-2xy+y^2-16\right)\)
\(=-\left(x-y\right)^2+16\)
\(=\left(4-x+y\right)\left(4+x-y\right)\)
c) \(3x+2x^2-2\)
\(=2x^2+4x-x-2\)
\(=2x\left(x+2\right)-\left(x+2\right)=\left(x+2\right)\left(2x-1\right)\)
a) \(\left(x^2-2x+1\right)-\left(y^2+2y+1\right)\)
\(=\left(x-1\right)^2-\left(y+1\right)^2\)
\(=\left(x-y-2\right)\left(x+y\right)\)
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
Câu 1 :
\(a,x^3-6x^2+9x\)
\(=x\left(x^2-6x+9\right)\)
\(=x\left(x-3\right)\)
b;c tự lm nha !!! : câu 2 cx vậy
1.b) x2 - 2xy + 3x - 6y = x2 - 2xy + 3x - 3y x 2
= (x2 - 2xy) + (3x - 3y) x 2
= 2x (x - y) + 3 (x - y) x 2
= (x - y) (2x + 3 x 2)
= (x - y) (2x + 6)
2.
(2x4 - 3x3 + 3x2 - 3x + 1) : (x2 + 1)
2x4 - 3x3 + 3x2 - 3x + 1 / x2 + 1
2x4 + 2x2 / 2x2 - 3x + 1
0 - 3x3 + x2 - 3x + 1 /
- 3x3 - 3x /
0 + x2 + 0 + 1 /
x2 + 1 /
0
=> đây là phép chia hết
Vậy (2x4 - 3x3 + 3x2 - 3x + 1) : (x2 + 1) = 2x2 - 3x + 1
(Sai thì thôi)
a) \(x^3-6x^2+9x\)
\(=x\left(x^2-6x+9\right)\)
\(=x\left(x-3\right)^2\)
b) \(x^2-2xy+3x-6y\)
\(=x\left(x-2y\right)+3\left(x-2y\right)\)
\(=\left(x+3\right)\left(x-2y\right)\)
c) \(x^2-8x+7\)
\(=x^2-7x-x+7\)
\(=x\left(x-7\right)-\left(x-7\right)\)
\(=\left(x-1\right)\left(x-7\right)\)
Câu tính chia mk lm đc nhg ko cs phần mềm trình bày
b = x.(x2 + 6x + 9 - 4y2 ) =x.((x+3)2 -4y2 )= x.(x+3-2y).(x+3+2y)
c = (x2 - 2x)+(2y-xy) = x.(x-2) +y.(2-x)= x.(x-2) + y.(-x+2)= x.(x-2) - y.(x-2) = (x-y).(x-2)
d = (x2 +1)2 - 4x2 = (x2 + 1 - 2x).(x2 +1 +2x) = (x-1)2 . (x+1)2
a = (7x)2 - (0.5y)2 = (7x - 0,5y).(7x+0,5y)
\(9x^2-12xy-20y-25=9x^2-25-4y\left(3x+5\right)\)
\(=\left(3x+5\right)\left(3x-5\right)-4y\left(3x+5\right)=\left(3x+5\right)\left(3x-4y-5\right)\)
\(xy^2-49x^3-28x^2-4x=x\left[y^2-\left(49x^2+28x+4\right)\right]\)
\(=x\left[y^2-\left(7x+2\right)^2\right]=x\left(y+7x+2\right)\left(y-7x-2\right)\)
\(x^2-3x-2019.2022=x^2-3x-2019\left(2019+3\right)\)
\(=x^2-3x-2019^2-3.2019=\left(x-2019\right)\left(x+2019\right)-3\left(x+2019\right)\)
\(=\left(x+2019\right)\left(x-2022\right)\)
a: \(9x^2-12xy-20y-25\)
\(=\left(3x-5\right)\left(3x+5\right)-4y\left(3x+5\right)\)
\(=\left(3x+5\right)\left(3x-5-4y\right)\)