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a) \(=y\left(z-3y\right)+5z\left(z-3y\right)=\left(z-3y\right)\left(y+5z\right)\)
b) \(=5y\left(z^2-2xz+x^2\right)=5y\left(z-x\right)^2\)
c: \(=\left(5x-y\right)\left(5x+y\right)\)
e: \(=\left(x-2\right)\left(x-3\right)\)
a) x(4y-10x)
b)3(x+2y)+(x+1)
c)(5x-y)(5x+y)
d)5x(y-z)2
e)(x-3)(x-2)
f)(2x+y)3
Phân tích đa thức sau thành nhân tử
a) 8x3 - 27=(2x-3)(4x2+6x+9)
b) 3x ( x - 7) - 5y ( y- x) xem lại đề hộ mk câu này vs nhá
c) 5xy2 - 10xyz + 5xz2=5x(y2-2yz+z2)=5x(y-z)2
a/ \(3x+6y-12xy\)
\(=3\left(x+2y-4xy\right)\)
b/ \(x^2-2x+xy-2y\)
\(=x\left(x-2\right)+y\left(x-2\right)\)
\(=\left(x-2\right)\left(x+y\right)\)
c/ \(5x^2-5z^2\)
\(=5\left(x^2-z^2\right)\)
\(=5\left(x-z\right)\left(x+z\right)\)
d/ \(x^2-9+2x\left(x-3\right)\)
\(=\left(x-3\right)\left(x+3\right)+2x\left(x+3\right)\)
\(=\left(x+3\right)\left(3x-3\right)\)
\(=3\left(x+3\right)\left(x-3\right)\)
a: 3x^2-12y^2
=3(x^2-4y^2)
=3(x-2y)(x+2y)
b: 5xy^2-10xyz+5xz^2
=5x(y^2-2yz+z^2)
=5x(y-z)^2
g: (a+b+c)^3-a^3-b^3-c^3
=(a+b+c-a)[(a+b+c)^2+a(a+b+c)+a^2]-(b+c)(b^2-bc+c^2)
=(b+c)[a^2+b^2+c^2+2ab+2ac+2bc+a^2+ab+ac+a^2-b^2+bc-c^2]
=(b+c)[3a^2+3ab+3bc+3ac]
=3(a+b)(b+c)(a+c)
a) \(9\left(x-5\right)^2-\left(x-7\right)^2=\left[3\left(x-5\right)-\left(x-7\right)\right]\left[3\left(x-5\right)+\left(x-7\right)\right]\)
\(\left(3x-15-x+7\right)\left(3x-15+x-7\right)=\left(2x-8\right)\left(4x-22\right)=4\left(x-4\right)\left(2x-11\right)\)
b)\(x^4+x^3+x+1=x^3\left(x+1\right)+\left(x+1\right)=\left(x+1\right)\left(x^3+1\right)=\left(x+1\right)^2\left(x^2-x+1\right)\)
c)\(5xy^2-10xyz+5xz^2=5x\left(y^2-2yz+z^2\right)=5x\left(y-z\right)^2\)
1a) \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)
b) \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)
\(a,=-\left(x-1\right)^3\left[=\left(1-x\right)^3\right]\\ b,=\left(1-x\right)^3\)
= 5.( xy2 - 2xyz + z2 )
= 5.( xy - z )2
tk nha b