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Ta có: (x - 1)(2x2 - 7x) + 6
= 2x3 - 9x2 + 7x + 6
= 2x3 - 4x2 - 5x2 + 10x - 3x + 6
= 2x2(x - 2) - 5x(x - 2) - 3(x - 2)
= (x - 2)(2x2 - 5x - 3)
= (x - 2)(2x2 - 6x + x - 3)
= (x - 2)[2x(x - 3) + x - 3]
= (x - 2)(x - 3)(2x + 1)
\(x^3-7x-6\)
\(=x^3+2x^2-2x^2-4x-3x-6\)
\(=x^2\left(x+2\right)-2x\left(x+2\right)-3\left(x+2\right)\)
\(=\left(x+2\right)\left(x^2-2x-3\right)\)
\(=\left(x+2\right)\left(x^2+x-3x-3\right)\)
\(=\left(x+2\right)\left[x\left(x+1\right)-3\left(x+1\right)\right]\)
\(=\left(x+2\right)\left(x+1\right)\left(x-3\right)\)
x³ -7x - 6
= x³ -x²+x²-x-6x- 6
= x²(x-1)+x(x-1)-6(x+1)
= (x-1)(x² +x) - 6(x+1)
= (x-1)x(x+1) - 6(x+1)
=(x2-x-6)(x+1)
=(x2 - 3x + 2x - 6)(x+1)
=[x(x+2)-3(x+2)](x+1)
=(x-3)(x+2)(x+1)
x³ -7x +6
= x³ -x²+x²-x-6x+6
= x²(x-1)+x(x-1)-6(x-1)
= (x-1)(x² +x-6)
= (x-1)(x²-2x+3x-6)
=(x-1)(x-2)(x+3)
\(x^3+7x-6=\left(x^3-1\right)+\left(7x-7\right)\)
\(=\left(x-1\right)\left(x^2+x+1\right)-7\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2+x-6\right)\)
\(=\left(x-1\right)\left(x^2+3x-2x-6\right)\)
\(=\left(x-1\right)\left(x+3\right)\left(x-2\right)\)
x3-7x+6=x3-x-6x+6=x(x-1)(x+1)-6(x-1)=(x-1)(x2+x-6)=(x-1)(x-2)(x+3)
\(x^3-7x+6=x^3+3x^2-3x^2-9x+2x+6\)
\(=x^2.\left(x+3\right)-3x.\left(x+3\right)+2.\left(x+3\right)\)
\(=\left(x+3\right).\left(x^2-3x+2\right)\)
\(=\left(x+3\right).\left(x^2-x-2x+2\right)\)
\(=\left(x+3\right).\left[x.\left(x-1\right)-2.\left(x-1\right)\right]\)
\(=\left(x+3\right).\left(x-1\right).\left(x-2\right)\)
a) \(x^2-5x+6=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\)
b)\(3x^2+9x-30=3x^2-6x+15x-30=3\left(x-2\right)\left(x+5\right)\)
c)\(x^2-7x+12=x^2-3x-4x+12=\left(x-3\right)\left(x-4\right)\)
d)\(x^2-7x+10=x^2-2x-5x+10=\left(x-2\right)\left(x-5\right)\)
a) \(x^2-5x+6=x^2-2x-3x+6=\left(x^2-2x\right)-\left(3x-6\right)\)
\(=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)
b) \(3x^2+9x-30=3\left(x^2+3x-10\right)=3\left(x^2-2x+5x-10\right)\)
\(=3\left[\left(x^2-2x\right)+\left(5x-10\right)\right]=3\left[x\left(x-2\right)+5\left(x-2\right)\right]\)
\(=3\left(x-2\right)\left(x+5\right)\)
c) \(x^2-7x+12=x^2-3x-4x+12=\left(x^2-3x\right)-\left(4x-12\right)\)
\(=x\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x-4\right)\)
d) \(x^2-7x+10=x^2-2x-5x+10=\left(x^2-2x\right)-\left(5x-10\right)\)
\(=x\left(x-2\right)-5\left(x-2\right)=\left(x-2\right)\left(x-5\right)\)
a) Ta có : x2 + 7x + 12
= x2 + 3x + 4x + 12
= (x2 + 3x) + (4x + 12)
= x(x + 3) + 4(x + 3)
= (x + 4)(x + 3)
Bạn ơi mk nhầm đề rồi số 30 thay bằng số 60 còn 36 thay bằng 72 và 39 thay bằng 75 nha
=x3-7x+6
=x3-2x2+2x2-4x-3x+6
=x2(x-2)+2x(x-2)-3(x-2)
=(x-2)(x2+2x-3)
=(x-2)(x2+2x+1-4)
=(x-2)[(x+1)2-4]
=(x-2)(x+1-2)(x+1+2)=(x-1)(x-2)(x+3)
x3 - 7x + 6
= x3 - 2x2 + 2x2 - 4x - 3x + 6
= x2 ( x - 2 ) + 2x ( x - 2 ) + 3 ( x - 2 )
= ( x2 + 2x + 3 ) ( x - 2 )
= ( x2 + 2x + 1 - 4 ) ( x - 2 )
= [ ( x + 1 )2 - 22 ] ( x - 2 )
= ( x + 1 - 2 ) ( x + 1 + 2 ) ( x - 2 )
= ( x - 1 ) ( x + 3 ) ( x - 2 )
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