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a/ \(=3y^2-6y-2x+1\)
b/ \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)
c/ \(=\left(2-x\right)^3\)
d/ \(=xy^2+x^2y+3xy+x^2y+x^3+3x^2-3xy-3x^2-9x\)
\(=xy\left(y+x+3\right)+x^2\left(y+x+3\right)-3x\left(y+x+3\right)\)
\(=\left(xy+x^2-3x\right)\left(y+x+3\right)=x\left(y+x-3\right)\left(y+x+3\right)\)
e/ \(=xy-x^2+2x-y^2+xy-2y\)
\(=x\left(y-x+2\right)-y\left(y-x+2\right)=\left(x-y\right)\left(y-x+2\right)\)
a) =(2x+3y-1)2
b)=-(x-1)3
c)=-(x3-6x2+12x-8)=-(x-2)3
d)x3 + 2x2y + xy2 – 9x
= x(x2 + 2xy + y2 -9)
= x[(x2 + 2xy + y2) - 32]
= x[(x + y)2 - 32]
= x (x + y – 3)(x + y + 3)
e) 2x-2y-x2+2xy-y2=2(x-y)-(x-y)2=(x-y)(2-x+y)
1)
\(6x^2+12xy+6y^2\)
\(=6(x^2+2xy+y^2)=6[(x^2+xy)+(xy+y^2)]\)
\(=6[x(x+y)+y(x+y)]=6(x+y)^2\)
2)
\(-3x^4y^2-6x^3y^2-3x^2y^3\)
\(=-3x^2y^2(x^2+2x+y)\)
3) \(-3x^4y-12x^2y-12x^2y\)
\(=-3x^4y-24x^2y\)
\(=-3x^2y(x^2+8)\)
4)
\(5x^4y^2+20x^3y^2+20x^2y^2\)
\(=5x^2y^2(x^2+4x+4)\)
\(=5x^2y^2[x^2+2x+2x+4]\)
\(=5x^2y^2[x(x+2)+2(x+2)]=5x^2y^2(x+2)^2\)
5)
\(4x^5y^2-8x^4y^2+4x^3y^2\)
\(=4x^3y^2(x^2-2x+1)\)
\(=4x^3y^2(x^2-x-x+1)\)
\(=4x^3y^2[x(x-1)-(x-1)]=4x^3y^2(x-1)^2\)
a) Đặt \(x^2-y=a\) , ta có đa thức : \(3a^2+4a-15=\left(3a^2-5a\right)+\left(9a-15\right)=a\left(3a-5\right)+3\left(3a-5\right)=\left(a+3\right)\left(3a-5\right)\)
Thay \(x^2-y=a\)vào đa thức trên được : \(\left(x^2-y+3\right)\left(3x^2-3y-5\right)\)
b) \(12x^2-12xy+3y^2-20x+10y+8=\left(12x^2-6xy-12x\right)-\left(6xy-3y^2-6y\right)-\left(8x-4y-8\right)\)\(=6x\left(2x-y-2\right)-3y\left(2x-y-2\right)-4\left(2x-y-2\right)=\left(2x-y-2\right)\left(6x-3y-4\right)\)
\(\text{a) }x^3y^3+x^2y^2+4\)
\(=x^3y^3+2x^2y^2-x^2y^2+4\)
\(=\left(x^3y^3+2x^2y^2\right)-\left(x^2y^2-4\right)\)
\(=x^2y^2\left(xy+2\right)-\left(xy+2\right)\left(xy-2\right)\)
\(=\left(xy+2\right)\left(x^2y^2-xy+2\right)\)
\( {c)}\)\(x^4+x^3+6x^2+5x+5\)
\(=\left(x^4+x^3+x^2\right)+\left(5x^2+5x+5\right)\)
\(=x^2\left(x^2+x+1\right)+5\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^2+5\right)\)
\({d)}\)\(x^4-2x^3-12x^2+12x+36\)
\(=\left(x^4-2x^3-6x^2\right)-\left(6x^2-12x-36\right)\)
\(=x^2\left(x^2-2x-6\right)-6\left(x^2-2x-6\right)\)
\(=\left(x^2-2x-6\right)\left(x^2-6\right)\)
Câu b sai đề thì phải ah
1) 2x3 + 4x2 y + 2xy2
= 2x(x2 + 2xy +y2)
= 2x (x+y)2
2) -3x2 - 12x - 12
= -3(x2 + 4x +4)
=-3(x+2)2
3) 4x5 y2 + 16x4 y2 + 16x3 y2
= 4x3y2(x2 + 4x + 4)
=4x3y2 (x+2)2
4) 2x3 - 4x2 + 2x
= 2x(x2 - 2x + 1)
=2x(x-1)2
5) 5x4 y2 - 10x3 y2 + 5x2 y2
= 5x2y2(x2- 2x + 1)
=5x2y2 (x-1)2
Mong giúp đc bn.
3) =2(x2+2xy+y2)
=2(x+y)2
6)= -3(x2+4x+4)
= -3(x2+2.x.2+22)
= -3(x+2)2
9) = 4x3y2(x2+4x+4)
=4x3y2(x+2)2
12)=2x(x2-2x+1)
=2x(x-1)2
15)= 5x2y2(x2-2x+1)
=5x2y2(x-1)2
\(x^2-2xy+y^2-a^2+4ab-4b^2\)
\(=\left(x-y\right)^2-\left(a-2b\right)^2\)
\(=\left(x-y-a+2b\right)\left(x-y+a-2b\right)\)
hk tốt
^^
1) \(12x^2-12xy+3y^2\)
\(=3\left(4x^2-4xy+y^2\right)\)
\(=3\left(2x-y\right)^2\)
5) \(4a^2-x^2-2x-1\)
\(=\left(2a\right)^2-\left(x^2+2x+1\right)\)
\(=\left(2a\right)^2-\left(x+1\right)^2\)
\(=\left(2a-x-1\right)\left(2a+x+1\right)\)