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\(mx^2-4mx+4m-nx^2+4nx-4n\)
\(=\left(mx^2-4mx+4m\right)-\left(nx^2-4nx+4n\right)\)
\(=m\left(x^2-4x+4\right)-n\left(x^2-4x+4\right)\)
\(=\left(m-n\right)\left(x^2-4x+4\right)\)
\(=\left(m-n\right)\left(x-2\right)^2\)
\(mx^2-4mx+4m-nx^2+4nx-4n\)
\(=x^2\left(m-n\right)+4x\left(n-m\right)+4\left(m-n\right)\)
\(=x^2\left(m-n\right)-4x\left(m-n\right)+4\left(m-n\right)\)
\(=\left(x^2-4x+4\right)\left(m-n\right)\)
\(=\left(x-2\right)^2\left(m-n\right)\)
Ta có :
\(mx^2-4mx+4m-nx^2+4nx-4n\)
\(=\left(mx^2-4mx+4m\right)-\left(nx^2-4nx+4n\right)\)
\(=m\left(x^2-4x+4\right)-n\left(x^2-4x+4\right)\)
\(=m\left(x-2\right)^2-n\left(x-2\right)^2\)
\(=\left(x-2\right)^2\left(m-n\right)\)
Đề sai nhé .Sửu lại
\(x^2-4x^2y^2+4+4x\)
\(=\left(x^2+4x+4\right)-4x^2y^2\)
\(=\left(x+2\right)^2-\left(2xy\right)^2\)
\(=\left(x+2+2xy\right)\left(x+2-2xy\right)\)
1/(x+2)2 -(3x-1)2=(x+2+3x-1)(x+2-3x+1)=4x(-2x+3)=-8x2+12x
2/(x4+x2)(-2x3-2x)=x2(x2+1)-2x(x2+1)=(x2+1)(x2-2x)
p) \(x^3-3x^2+3x-1+2\left(x^2-x\right)\\ =\left(x^3-1\right)-\left(3x^2-3x\right)+2x\left(x-1\right)\\ =\left(x-1\right)\left(x^2+x+1\right)-3x\left(x-1\right)+2x\left(x-1\right)\\ =\left(x-1\right)\left(x^2+x+1-3x+2x\right)\\ =\left(x-1\right)\left(x^2+1\right)\)
p:Ta có: \(x^3-3x^2+3x-1+2\left(x^2-x\right)\)
\(=\left(x-1\right)^3+2x\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2-2x+1+2x\right)\)
\(=\left(x-1\right)\left(x^2+1\right)\)
\(x^3-x^2+7x-7=x^2\left(x-1\right)+7\left(x-1\right)=\left(x-1\right)\left(x^2+7\right)\)
\(x^2+xy-5x-5y=\left(x^2+xy\right)-\left(5x+5y\right)\)
\(=x\left(x+y\right)-5\left(x+y\right)=\left(x-5\right)\left(x+y\right)\)
x(x+y)-5(x+y) = (x-5)(x+y) bài này mik hok qua rùi mik đang ôn tập nên là mik tự làm chứ ko chép mấy câu trả lời khác
x2 - x - y2 - y
=x2 - y2 - x - y
=(x - y)(x + y) - (x + y)
=(x + y)(x - y - 1)
\(mx^2-4mx+4m-nx^2+4nx-4n\)
\(=\left(mx^2-4mx+4m\right)-\left(nx^2-4nx+4n\right)\)
\(=m\left(x^2-4x+4\right)-n\left(x^2-4x+4\right)\)
\(=\left(x^2-4x+4\right)\left(m-n\right)\)
\(=\left(m-n\right)\left(x-2\right)^2\)