Câu hỏi của rongxanh

Question

phan tich da thuc thanh nhan tu a, x^7+x^2+1b,  x^7+x^5+1

Le Thi Khanh Huyen · Accepted Answer

a) $x^7+x^2+1$$=x^7-x+x+x^2+1$$=\left(x^7-x\right)+\left(x^2+x+1\right)$$=x\left(x^6-1\right)+\left(x^2+x+1\right)$$=x\left(x^3+1\right)\left(x^3-1\right)+\left(x^2+x+1\right)$$=x\left(x^3+1\right)\left(x-1\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)$$=\left(x^4+x\right)\left(x-1\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)$$=\left(x^5-x^4+x^2-x\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)$$=\left(x^5-x^4+x^2-x+1\right)\left(x^2+x+1\right)$Câu trả lời: a) $x^7+x^2+1$$=x^7-x+x+x^2+1$$=\left(x^7-x\right)+\left(x^2+x+1\right)$$=x\left(x^6-1\right)+\left(x^2+x+1\right)$$=x\left(x^3+1\right)\left(x^3-1\right)+\left(x^2+x+1\right)$$=x\left(x^3+1\right)\left(x-1\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)$$=\left(x^4+x\right)\left(x-1\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)$$=\left(x^5-x^4+x^2-x\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)$$=\left(x^5-x^4+x^2-x+1\right)\left(x^2+x+1\right)$

Le Thi Khanh Huyen · Answer

b) $x^7+x^5+1$$=x^7+x^6+x^5-x^6+1$$=\left(x^7+x^6+x^5\right)-\left(x^6-1\right)$$=x^5\left(x^2+x+1\right)-\left(x^3+1\right)\left(x^3-1\right)$$=x^5\left(x^2+x+1\right)-\left(x^4-x^3+x-1\right)\left(x^2+x+1\right)$$=\left(x^5-x^4+x^3-x^2+1\right)\left(x^2+x+1\right)$Câu trả lời: b) $x^7+x^5+1$$=x^7+x^6+x^5-x^6+1$$=\left(x^7+x^6+x^5\right)-\left(x^6-1\right)$$=x^5\left(x^2+x+1\right)-\left(x^3+1\right)\left(x^3-1\right)$$=x^5\left(x^2+x+1\right)-\left(x^4-x^3+x-1\right)\left(x^2+x+1\right)$$=\left(x^5-x^4+x^3-x^2+1\right)\left(x^2+x+1\right)$

Chúng tôi đề xuất

Tài nguyên

Ứng dụng mobile

Bảng xếp hạng

Các khóa học có thể bạn quan tâm

Yêu cầu VIP