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Bài làm
a) x2 - 2xy + y2 - zx + yz
= ( x2 - 2xy + y2 ) - ( zx - yz )
= ( x - y )2 - z( x - y )
= ( x - y )( x - y - z )
b) x3 - x2 - 5x + 125
= ( x3 + 125 ) - ( x2 + 5x )
= ( x + 5 )( x2 -.5x + 25 ) - x( x + 5 )
= ( x + 5 )( x2 - 5x + 25 - x )
= ( x + 5 )( x2 - 6x + 25 )
# Học tốt #
câu a nhầm đề à bạn,mk nghĩ -xz chứ ko phải -xy.
\(x^2-3x+xy-3y\)
\(=x\left(x+y\right)-3\left(x+y\right)\)
\(=\left(x+y\right)\left(x-3\right)\)
\(x^2-2xy+y^2-4=\left(x-y\right)^2-2^2=\left(x-y-2\right)\left(x-y+2\right)\)
\(x^2+x-y^2+y=\left(x-y\right)\left(x+y\right)+\left(x+y\right)=\left(x+y\right)\left(x-y+1\right)\)
Câu 2 nha
\(a,x^4+2x^3+x^2\)
\(=x^2\left(x^2+2x+1\right)\)
\(=x^2\left(x+1\right)^2\)
\(c,x^2-x+3x^2y+3xy^2+y^3-y\)
\(=\left(x^3+3x^2y+3xy^2+y^3\right)-\left(x+y\right)\)
\(=\left(x+y\right)^3-\left(x+y\right)\)
\(=\left(x+y\right)\left(x^2+2xy+y^2-1\right)\)
\(x^3y-5x^2y-2xy+10y\)
\(=\left(x^3y-2xy\right)+\left(10y-5x^2y\right)\)
\(=xy\left(x^2-2\right)+5y\left(2-x^2\right)\)
\(=xy\left(x^2-2\right)-5y\left(x^2-2\right)\)
\(=\left(xy-5y\right)\left(x^2-2\right)\)
\(a.\left(xy+yz\right)-\left(5x+5z\right)\)
\(=y\left(x+z\right)-5\left(x+z\right)\)
\(=\left(x+z\right)\left(y-5\right)\)
\(b.\left(x^2+2xy+y^2\right)-9x^2\)
\(=\left(x+y\right)^2-9x^2\)
\(=\left(x+y-3x\right).\left(x+y+3x\right)\)
\(=\left(y-2x\right).\left(y+4x\right)\)
a. Đề=\(y\left(x+z\right)-5\left(x+z\right)\)\(=\left(x+z\right)\left(y-5\right)\)
b. Đề=\(\left(x+y\right)^2-\left(3x\right)^2\)\(=\left(x+y-3x\right)\left(x+y+3x\right)\)\(=\left(y-2x\right)\left(y+4x\right)\)
a, \(a+2\sqrt{ab}+b=\left(\sqrt{a}+\sqrt{b}\right)^2\)
b,\(x^2+2xy+y^2+x^2-y^2=\left(x+y\right)^2+\left(x-y\right)\left(x+y\right)\)\(=\left(x+y\right)\left(x+y+x-y\right)=2x\left(x+y\right)\)
\(x^2-2xy+5x-10y\)
\(=x\left(x-2y\right)+5\left(x-2y\right)\)
\(=\left(x+5\right)\left(x-2y\right)\)
\(x^2-2xy+5x-10y\)
\(=\left(x^2-2xy\right)+\left(5x-10y\right)\)
\(=x\left(x-2y\right)+5\left(x-2y\right)\)
\(=\left(x-2y\right)\left(x+5\right)\)
\(x-3\sqrt{x}+\sqrt{xy}-3y\)
\(=\left(x-3\sqrt{x}\right)+\left(\sqrt{xy}-3y\right)\)
\(=\sqrt{x}\left(\sqrt{x}-3\right)+y\left(\sqrt{x}-3\right)\)
\(=\left(\sqrt{x}-3\right)\left(\sqrt{x}+y\right)\)