Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(100x^2-\left(x^2+25\right)^2=\left(10x\right)^2-\left(x^2+25\right)^2=\left(10x-x^2-25\right)\left(x^2+10x+25\right)\)
\(=-\left(x-5\right)^2\left(x+5\right)^2\)
\(b,x-y+5=a\text{ thì biểu thức bằng:}a^2-2a+4>0\text{ nên k phân tích đc}\)
\(d,x^3+27y^3=\left(x+3y\right)\left(x^2-3xy+9y^2\right)\)
a) 100x2 - ( x2 + 25 )2
= ( 10x )2 - ( x2 + 25 )2
= [ 10x - ( x2 + 25 ) ][ 10x + ( x2 + 25 ) ]
= ( -x2 + 10x - 25 )( x2 + 10x + 25 )
= -( x2 - 10x + 25 )( x2 + 10x + 25 )
= -( x - 5 )2( x + 5 )2
b) ( x - y + 5 )2 + 4 - 4( x - y + 5 ) ( 4 may ra còn phân tích được :)) )
= ( x - y + 5 )2 - 2( x - y + 5 ).2 + 22
= ( x - y + 5 - 2 )2
= ( x - y + 3 )2
c) a2 - 25( b - c ) ( không phân tích được :)) )
d) x3 + 27y3 = x3 + ( 3y )3 = ( x + 3y )( x2 - 3xy + 9y2 )
\(\left(3x+1\right)^2-4\left(x-2\right)^2=9x^2+6x+1-4\left(x^2-4x+4\right)=9x^2+6x+1-4x^2+16x-16=5x^2+22x-15=\)
\(\left(5x-3\right)\left(x+5\right)\)
\(9\left(2x+3\right)^2-4\left(x+1\right)^2=9\left(4x^2+12x+9\right)-4\left(x^2+2x+1\right)=36x^2+108x+81-4x^2-8x-4=32x^2+100x+77\)
\(\left(8x+11\right)\left(4x+7\right)\)
Ta có:
a) 5x - 20y = 5(x - 4y)
b) 5x(x - 1) - 3x(x - 1) = x(x - 1)2
c) x(x + y) - 5x - 5y = x(x + y) - (5x + 5y) = x(x + y) - 5(x + y) = (x - 5)(x + y)
d) x2 - 9 = (x - 3)(x + 3)
e) 42 - 25 = (4 - 5)(4 + 5) f) x6 - y6 = (x4)2 - (y4)2 = (x4 - y4)(x4 + y4)
a) 5x - 20y = 5( x - 4y)
b) 5x(x-1) - 3x(x-1) =2x (x-1)
c) x2 - 9 = x2 - 32 = ( x-3)(x+3)
e) 42-25 = 42 - 52 = ( 4-5)(4+5)= -9
f) x6 - y6 = (x3)2 - (y3)2 = ( x3 - y3 ) ( x3 + y3)
= (x-y) ( x2 + xy + y2 ) ( x+y) ( x2 -xy +y2)
1. \(\left(x+1\right)^3-125\)
\(=\left(x+1\right)^3-5^3\)
\(=\left(x+1-5\right).\left[\left(x+1\right)^2+\left(x+1\right).5+5^2\right]\)
2. \(\left(x+4\right)^3-64\)
\(=\left(x+4\right)^3-4^3\)
\(=\left(x+4-4\right).\left[\left(x+4\right)^2+\left(x+4\right).4+4^2\right]\)
3. \(x^3-\left(y-1\right)^3\)
\(=(x^3-y+1).\left[\left(x^2\right)+x.\left(y+1\right)+\left(y+1\right)^2\right]\)
\(\)4. \(\left(a+b\right)^3-c^3\)
\(=\left[\left(a+b\right)-c\right].\left[\left(a+b\right)^2+\left(a+b\right).c+c^2\right]\)
5. \(125-\left(x+2\right)^3\)
\(=5^3-\left(x+2\right)^3\)
\(=\left(5-x-2\right).\left[5^2+5.\left(x+2\right)+\left(x+2\right)^2\right]\)
6. \(\left(x+1\right)^3+\left(x-2\right)^3\)
\(=\left[\left(x+1\right)+\left(x-2\right)\right].\left[\left(x+1\right)^2-\left(x+1\right).\left(x-2\right)+\left(x-2\right)^2\right]\)
mjk sửa lại
a)100x^2 -( x^2+25)^2
=[10x-(x2+25)][10x+(x2+25)]
=(10x-x2-25)(10x+x2+25)
=-(x2-10x+25)(x+5)2
=-(x-5)2(x+5)2
b)(x+4)^3 - 64
=(x+4)3-43
=(x+4-4)[(x+4)2+(x+4).4+16]
=x(x2+8x+16+4x+16+16)
=x(x2+12x+48)
c) x^6 + y^6
=(x2)3+(y2)3
=(x2+y2)(x4+x2y2+y4)