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19 tháng 12 2018

a,x2-z2+y2-2xy

=(x2-2xy+y2)-z2

=(x-y)2-z2

b,-x-y2+x2-y

=(x2-y2)-(x+y)

=(x-y)(x+y)-(x+y)

=(x+y)(x-y-1)

c,x2-2xy-4z2+y2

=(x2-2xy+y2)-(2z)2

=(x-y)2-(2z)2

=(x-y-2z)(x-y+2z)

d,x(x+y)-5x-5y

=x(x+y)-5(x+y)

=(x+y)(x-5)

e, x2 - 5x + 5y - y2

=(x2-y2)-5(x-y)

=(x+y)(x-y)-5(x+y)

=(x+y)(x-y-5)

f, x2 + 4x + 3

=x2+x+3x+3

=x(x+1)+3(x+1)

=(x+1)(x+3)

g, 10x ( x - y) - 8 (y - x)

=10x(x-y)+8(x-y)

=2(x-y)(5x+4)

h, x2 - 3x + 2

=x2-x-2x+2

=x(x+1)-2(x-1)

=(x+1)(x-2)

12 tháng 7 2019

a,\(xy+3x-7y-21\)

\(=x\left(y+3\right)-7\left(y+3\right)\)

\(=\left(y+3\right)\left(x-7\right)\)

12 tháng 7 2019

\(b,2xy-15-6x+5y\)

\(=\left(2xy-6x\right)+\left(-15+5y\right)\)

\(=2x\left(y-3\right)-5\left(3-y\right)\)

\(=2x\left(y-3\right)+5\left(y-3\right)\)

\(=\left(y-3\right)\left(2x+5\right)\)

25 tháng 8 2017

b) \(5x-5y+ax-ay \)

\(=\left(5x-5y\right)+\left(ax-ay\right)\)

\(=5.\left(x-y\right)+a.\left(x-y\right)\)

\(=\left(x-y\right)\left(5+a\right)\)

c) \(a^3-a^2x-ay+xy\)

\(=\left(a^3-a^2x\right)-\left(ay-xy\right)\)

\(=a^2\left(a-x\right)-y\left(a-x\right)\)

\(=\left(a-x\right)\left(a^2-y\right)\)

24 tháng 7 2016

1)   \(x^2-x-y^2-y=\left(x^2-y^2\right)-\left(x+y\right)=\left(x-y\right)\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(x-y-1\right)\)

\(x^2-2xy+y^2-z^2=\left(x-y\right)^2-z^2=\left(x-y-z\right)\left(x-y+z\right)\)

2)\(5x-5y+ax-ay=5\left(x-y\right)+a\left(x-y\right)=\left(x-y\right)\left(a+5\right)\)

\(a^3-a^2x-ay+xy=a^2\left(a-x\right)-y\left(a-x\right)=\left(a-x\right)\left(a^2-y\right)\)

16 tháng 11 2018

b.10x(x-y)-6y(y-x)=10x(x-y)+6y(x-y)=(10x+6y)(x-y)

16 tháng 11 2018

c.3x2+5y-3xy-5x=(3x2--3xy)-(5x-5y)=3x(x-y)-5(x-y)=(3x-5)(x-y)

AH
Akai Haruma
Giáo viên
21 tháng 12 2018

a)

\(14x^2y-21xy^2+28x^2y^2\)

\(=7xy(2x-3y+4xy)\)

b) \(x(x+y)-5x-5y=x(x+y)-5(x+y)=(x-5)(x+y)\)

c)

\(10x(x-y)-8(y-x)=10x(x-y)+8(x-y)\)

\(=(x-y)(10x+8)=2(x-y)(5x+4)\)

21 tháng 12 2018

a. \(14x^2y-21xy^2+28x^2y^2\)

\(=7xy\left(2x-3y+4xy\right)\)

b. \(x\left(x+y\right)-5x-5y\)

\(=x\left(x+y\right)-5\left(x+y\right)\)

\(=\left(x-5\right)\left(x+y\right)\)

c. \(10x\left(x-y\right)-8\left(y-x\right)\)

\(=10x\left(x-y\right)+8\left(x-y\right)\)

\(=\left(10x+8\right)\left(x-y\right)\)

d. \(\left(3x+1\right)^2-\left(x+1\right)^2\)

\(=\left(3x+1+x+1\right)\left(3x+1-x-1\right)\)

\(=2x\left(4x+2\right)\)

\(=4x\left(2x+1\right)\)

e. Vì bài này giải không ra nên mình nghĩ nó sai đề, sửa lại tí nhé!

\(x^3+y^3+z^3-3xyz\)

\(=\left(x+y\right)^3+z^3-3xy\left(x+y\right)-3xyz\)

\(=\left(x+y+z\right)\left[\left(x+y\right)^2-z\left(x+y\right)+z^2\right]-3xy\left(x+y+z\right)\)

\(=\left(x+y+z\right)\left(x^2+2xy+y^2-xz+zy+z^2-3xy\right)\)

g. \(5x^2-10xy+5y^2-20z^2\)

\(=5\left(x^2-2xy+y^2-4z^2\right)\)

\(=5\left[\left(x-y^2\right)-4z^2\right]\)

\(=5\left(x-y+z\right)\left(x-y-z\right)\)

h. \(x^3-x+3x^2y+3xy^3+y^3-y\)

\(=\left(x^3+3x^2y+3xy^2+y^2\right)-\left(x+y\right)\)

\(=\left(x+y\right)^3-\left(x+y\right)\)

\(=\left(x+y\right)\left[\left(x+y\right)^2-1\right]\)

\(=\left(x+y\right)\left(x+y-1\right)\left(x+y+1\right)\)

i. \(x^2+7x-8\)

\(=x^2-x+8x-8\)

\(=x\left(x-1\right)+8\left(x-1\right)\)

\(=\left(x+8\right)\left(x-1\right)\)

c) \(x^2+x-ax-a\)

\(=x\left(x+1\right)-a\left(x+1\right)\)

\(=\left(x+1\right)\left(x-a\right)\)

d) \(2xy-ax+x^2-2ay\)

\(=2y\left(x-a\right)+x\left(x-a\right)\)

\(=\left(x-a\right)\left(2y+x\right)\)

e) \(x^2y+xy^2-x-y\)

\(=xy\left(x+y\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(xy-1\right)\)

f) \(25-10x-4y^2+x^2\)

\(=\left(x^2-10x+25\right)-\left(2y\right)^2\)

\(=\left(x-5\right)^2-\left(2y\right)^2\)

\(=\left(x-5-2y\right)\left(x-5+2y\right)\)

g) \(x^3-6xy+9y^2-36\)

h) \(4x^2-9y^2+4x-6y\)

\(=\left(2x\right)^2-\left(3y\right)^2+2\left(2x-3y\right)\)

\(=\left(2x-3y\right)\left(2x+3y\right)+2\left(2x-3y\right)\)

\(=\left(2x-3y\right)\left(2x+3y+2\right)\)

k) \(-x^2+5x+2xy-5y-y^2\)

\(=-\left(x^2-2xy+y^2\right)+5\left(x-y\right)\)

\(=-\left(x-y\right)^2+5\left(x-y\right)\)

\(=\left(x-y\right)\left(-x+y+5\right)\)

i) \(4x^2-25y^2-6x+15y\)

\(=\left(2x\right)^2-\left(5y\right)^2-3\left(2x-5y\right)\)

\(=\left(2x-5y\right)\left(2x+5y\right)-3\left(2x-5y\right)\)

\(=\left(2x-5y\right)\left(2x+5y-3\right)\)

28 tháng 1 2020

a, \(x\left(y+z\right)^2+y\left(x+z\right)^2+z\left(x+y\right)^2+4xyz\)

\(=x\left(y+z\right)^2+x^2\left(y+z\right)+yz\left(y+z\right)\)

\(=\left(y+z\right)\left(xy+xz+z^2+yz\right)\)

\(=\left(y+z\right)\left[x\left(x+y\right)+z\left(x+y\right)\right]\)

\(=\left(y+z\right)\left(x+z\right)\left(x+y\right)\)

b, \(yz\left(y+z\right)+xz\left(z-x\right)-xy\left(x+y\right)\)

\(=yz\left(y+z\right)+xz^2-x^2z-x^2y-xy^2\)

\(=yz\left(y+z\right)-x\left(y+z\right)\left(y-z\right)-x^2\left(y+z\right)\)

\(=\left(y+z\right)\left(yz-xy+xz-x^2\right)\)

\(=\left(y+z\right)\left[y\left(z-x\right)+x\left(z-x\right)\right]\)

\(=\left(y+z\right)\left(y+x\right)\left(z-x\right)\)

23 tháng 11 2017

a) \(x^2-y^2-5x-5y\)

\(=\left(x^2-y^2\right)-\left(5x+5y\right)\)

\(=\left(x-y\right)\left(x+y\right)-5\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-5\right)\)

b) \(5x^3-5x^2y-10x^2+10xy\)

\(=\left(5x^3-5x^2y\right)-\left(10x^2-10xy\right)\)

\(=5x^2\left(x-y\right)-10x\left(x-y\right)\)

\(=\left(x-y\right)\left(5x^2-10x\right)\)

\(=5x\left(x-y\right)\left(x-2\right)\)

c) \(x^3-2x^2-x+2\)

\(=\left(x^3-2x^2\right)-\left(x-2\right)\)

\(=x^2\left(x-2\right)-\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2-1\right)\)

\(=\left(x-2\right)\left(x-1\right)\left(x+1\right)\)

d) \(-y^2+2xy-x^2+3x-3y\)

\(=-\left(y^2-2xy+x^2\right)+\left(3x-3y\right)\)

\(=-\left(y-x\right)^2+3\left(x-y\right)\)

\(=-\left(x-y\right)^2+3\left(x-y\right)\)

\(=\left(x-y\right)\left[-\left(x-y\right)+3\right]\)

\(=\left(x-y\right)\left(-x+y+3\right)\)

g) \(4x^2-8x+3\)

\(=4x^2-6x-2x+3\)

\(=\left(4x^2-6x\right)-\left(2x-3\right)\)

\(=2x\left(2x-3\right)-\left(2x-3\right)\)

\(=\left(2x-3\right)\left(2x-1\right)\)

h) \(2x^2-5x-7\)

\(=2x^2+2x-7x-7\)

\(=\left(2x^2+2x\right)-\left(7x+7\right)\)

\(=2x\left(x+1\right)-7\left(x+1\right)\)

\(=\left(x+1\right)\left(2x-7\right)\)

k) \(x^4+4\)

\(=x^4+4x^2+4-4x^2\)

\(=\left[\left(x^2\right)^2+2.x^2.2+2^2\right]-4x^2\)

\(=\left(x^2+2\right)^2-\left(2x\right)^2\)

\(=\left(x^2+2-2x\right)\left(x^2+2+2x\right)\)

12 tháng 9 2020

a) x2 - y2 + 4x + 4

= ( x2 + 4x + 4 ) - y2

= ( x + 2 )2 - y2

= ( x + 2 - y )( x + 2 + y )

b) x2 - 2xy + y2 - 1

= ( x2 - 2xy + y2 ) - 1

= ( x - y )2 - 12

= ( x - y - 1 )( x - y + 1 )

c) x2 - 2xy + y2 - 4

= ( x2 - 2xy + y2 ) - 4

= ( x - y )2 - 22

= ( x - y - 2 )( x - y + 2 )

d) x2 - 2xy + y2 - z2

= ( x2 - 2xy + y2 ) - z2

= ( x - y )2 - z2

= ( x - y - z )( x - y + z )

e) 25 - x2 + 4xy - 4y2

= 25 - ( x2 - 4xy + 4y2 )

= 52 - ( x - 2y )2

= ( 5 - x + 2y )( 5 + x - 2y )

f) x2 + y2 - 2xy - 4z2

= ( x2 - 2xy + y2 ) - 4z2

= ( x - y )2 - ( 2z )2

= ( x - y - 2z )( x - y + 2z )