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1) \(3x^3-12x\)
\(=3x\left(x^2-4\right)\)
\(=3x\left(x+2\right)\left(x-2\right)\)
2)\(x^3+x^2-x-1\)
\(=\left(x^3+x^2\right)-\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2-1\right)\)
\(=\left(x+1\right)^2\left(x-1\right)\)
3) \(x^2-7xy+10y^2\)
\(=\left(x^2-2xy\right)-\left(5xy-10y^2\right)\)
\(=x\left(x-2y\right)-5y\left(x-2y\right)\)
\(=\left(x-5y\right)\left(x-2y\right)\)
1) \(3x^3-12x\)
\(=3x\left(x^2-4\right)\)
\(=3x\left(x-2\right)\left(x+2\right)\)
2) \(x^3+x^2-x-1\)
\(=x^2\left(x+1\right)-\left(x+1\right)\)
\(=\left(x^2-1\right)\left(x+1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left(x+1\right)\)
a/ \(=x^2+2x-7x-14=x\left(x+2\right)-7\left(x+2\right)=\left(x-7\right)\left(x+2\right)\)
b/ \(=15-3x=3\left(5-x\right)\)
c/ \(=x^2-3xy-4xy+12y^2=x\left(x-3y\right)-4y\left(x-3y\right)=\left(x-4y\right)\left(x-3y\right)\)
d/ \(=x^3-2x^2+x+2x^2-4x+2=x\left(x^2-2x+1\right)+2\left(x^2-2x+1\right)=\left(x+2\right)\left(x-1\right)^2\)
a)x2-5x-14=(x2-7x)+(2x-14)=x(x-7)+2(x-7)=(x-7)(x+2)
b)4x2-3x-1=(4x2-4x)+(x-1)=4x(x-1)+(x-1)=(x-1)(4x+1)
c)x2-7xy+12y2=x2-7xy+12,25y2-0,25y2=(x-3,5y)2-0,25y2=(x-3,5y-0,5y)(x-3,5y+0,5y)=(x-4y)(x-2y)
d)x3-3x+2=(x3-x)-(2x-2)=(x-1)(x2+x)-2(x-1)=(x-1)(x2+x-2)=(x-1)(x2-2x+x-2)=(x-1)(x+1)(x-2)
a) x2 - 5x - 14 = x2 + 2x - 7x - 14 = x(x + 2) - 7(x + 2) = (x + 2)(x - 7)
b) 4x2 - 3x - 1 = 4x2 - 4x + x - 1 = 4x(x - 1) + (x - 1) = (x - 1)(4x + 1)
c) x2 - 7xy + 12y2 = x2 - 4xy - 3xy + 12y2 = x(x - 4y) - 3y(x - 4y) = (x - 4y)(x - 3y)
d) x2 - 3x + 2 = x2 - x - 2x - 2 = x(x - 1) - 2(x - 1) = (x - 1)(x - 2)
\(x^2+4x-y^2+4\)
\(=\left(x^2+4x+4\right)-y^2\)
\(=\left(x^2+2\right)^2-y^4\)
\(=\left(x^2+y^2+2\right)\left(x^2-y^2+2\right)\)
\(\left(x^2+4x+4\right)-y^2\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2+y\right)\left(x+2-y\right)\)
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hk tôt
a) \(x^2-5x-14=x^2-7x+2x-14=x\left(x-7\right)+2\left(x-7\right)=\left(x-7\right)\left(x+2\right)\)
b) \(4^2-3x-1=16-1-3x=15-3x=3\left(5-x\right)\)
x^2 - 7xy + 10y^2
= (x^2 - 2xy) - (5xy - 10y^2)
= x(x - 2y) - 5y( x - 2y)
= (x - 5y)(x - 2y)
mik mới học lớp 7 thôi!