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Ta có : x2 - x + 6x - 6
= x(x - 1) + 6(x - 1)
= (x + 6)(x - 1)
b) 5x2 + 5xy - x - y
= 5x(x + y) - (x + y)
= (5x - 1)(x + y)
câu a,b làm như trên. câu c:
c, 7x - 6x2 - 2 = -6x^2 + 7x - 2 = -( 6x^2-3x-4x+2) = -[ 3x ( 2x-1)-2(2x-1)]=-(3x-2)(2x-1)
Mình viết xuôi theo dạng ax2 + bx + c nhé ;-; cho dễ làm
a) 2x2 + 7x + 3 = 2x2 + x + 6x + 3 = x( 2x + 1 ) + 3( 2x + 1 ) = ( 2x + 1 )( x + 3 )
b) 3x2 - 8x + 4 = 3x2 - 6x - 2x + 4 = 3x( x - 2 ) - 2( x - 2 ) = ( x - 2 )( 3x - 2 )
c) 3x2 - 7x + 2 = 3x2 - 6x - x + 2 = 3x( x - 2 ) - ( x - 2 ) = ( x - 2 )( 3x - 1 )
d) -6x2 + 7x - 2 = -6x2 + 3x + 4x - 2 = -3x( 2x - 1 ) + 2( 2x - 1 ) = ( 2x - 1 )( 2 - 3x )
e) -3x2 + 7x - 2 = -3x2 + 6x + x - 2 = -3x( x - 2 ) + ( x - 2 ) = ( x - 2 )( 1 - 3x )
f) 2x2 - 5x + 2 = 2x2 - 4x - x + 2 = 2x( x - 2 ) - ( x - 2 ) = ( x - 2 )( 2x - 1 )
g) 3x2 - 8x + 4 = 3x2 - 6x - 2x + 4 = 3x( x - 2 ) - 2( x - 2 ) = ( x - 2 )( 3x - 2 )
h) 6x2 - 11x + 3 = 6x2 - 2x - 9x + 3 = 2x( 3x - 1 ) - 3( 3x - 1 ) = ( 3x - 1 )( 2x - 3 )
i) 2x2 + 3x - 27 = 2x2 - 6x + 9x - 27 = 2x( x - 3 ) + 9( x - 3 ) = ( x - 3 )( 2x + 9 )
j) 4x2 - 5x + 1 = 4x2 - 4x - x + 1 = 4x( x - 1 ) - ( x - 1 ) = ( x - 1 )( 4x - 1 )
a,\(xy+3x-7y-21\)
\(=x\left(y+3\right)-7\left(y+3\right)\)
\(=\left(y+3\right)\left(x-7\right)\)
\(b,2xy-15-6x+5y\)
\(=\left(2xy-6x\right)+\left(-15+5y\right)\)
\(=2x\left(y-3\right)-5\left(3-y\right)\)
\(=2x\left(y-3\right)+5\left(y-3\right)\)
\(=\left(y-3\right)\left(2x+5\right)\)
a)x2+5x-6
=x2+6x-x-6
=x(x+6)-(x+6)
=(x-1)(x+6)
b)7x-6x2-2
=-6x2+3x+4x-2
=-3x(2x-1)+2(2x-1)
=(2x-1)(-3x+2)
c)x2+4x+3
=x2+3x+x+3
=x(x+3)+(x+3)
=(x+1)(x+3)
d)2x2+3x-5
=2x2+5x-2x-5
=x(2x+5)-(2x+5)
=(x-1)(2x+5)
Bài 1 :
a) 3x2 . ( 5x2 - 7x + 4 ) = 15x4 - 21x3 + 12x2
b) xy2 . ( 2x2y - 5xy + y ) = 2x3y3 - 5x2y3 + xy3
c) ( 2x2 - 5x ) . ( 3x2 - 2x + 1 ) = 6x4 - 4x3 + 2x2 - 15x3 + 10x2 - 5x
= 6x4 - 19x3 + 12x2 - 5x
d) ( x - 3y ) . ( 2xy + y2 + x ) = 2x2y + xy2 + x2 - 6xy2 - 3y3 - 3xy
Bài 2 :
a) A = x2 + 9y2 - 6xy
=> A = x2 - 2 . x . 3y + ( 3y )2
=> A = ( x - 3y )2
Thay x = 19 và y = 13 vào biểu thức A ta có :
A = ( 19 - 3 . 13 )2
=> A = ( 19 - 39 )2
=> A = ( -20 )2
=> A = 400
b) B = x3 - 6x2y + 12xy2 - 8y3
=> B = ( x - 2y )3
Thay x = 12 và y = -4 vào biểu thức B ta có :
B = [ 12 - 2 . ( -4 ) ]3
=> B = ( 12 + 8 )3
=> B = 203
=> B = 8000
= -3y3 + 2x2y - 5xy2 + x2 - 3xy
- a] =-[6x^2 - 7x +2] = - [ 6x^2 - 3x - 4x + 2 ] = -[ 3x [ 2x-1] - 2 [2x - 1]] = - [ 2x - 1] [3x - 2 ]
a) 2x2-6x-x+3 = 2x(x-3) - (x-3) = (x-3)(2x-1)
b) x2-x-5x+5 = x(x-1) - 5(x-1) = (x-1)(x-5)
c) 5x(x-2y) + 2( x-2y)2 = (x-2y)(5x+2x-2y) = (x-2y)(7x-2y)
chú ý : (A-B)2=(B-A)2
d) 7x(4-y)2 - (4-y)3 = ( 16-8y+y2) (7x-4+y)
a) \(2x^2-7x+3=2x^2-6x-x+3=2x\left(x-3\right)-\left(x-3\right)=\left(x-3\right)\left(2x-1\right)\)
b) \(x^2-6x+5=x^2-5x-x+5=x\left(x-5\right)-\left(x-5\right)=\left(x-5\right)\left(x-1\right)\)
c)\(5x\left(x-2y\right)+2\left(2y-x\right)^2=5x\left(x-2y\right)+2\left(x-2y\right)^2\\ =\left(x-2y\right)\left(5x+2x-4y\right)=\left(x-2y\right)\left(7x-4y\right)\)
d) \(7x\left(y-4\right)^2-\left(4-y\right)^3=7x\left(y-4\right)+\left(y-4\right)^3=\left(y-4\right)\left(7x-y-4\right)\)
a)\(5x^2+5xy-x-y\)
= 5x(x+y) - (x+y)
= (x+y)(5x-1)
b) \(2x^2+3x-5\)
= \(2x^2-2x+5x-5\)
= 2x(x-1) + 5(x-1)
= (x-1)(2x+5)
c) \(-6x^2+7x-2\)
=\(-6x^2+3x+x-2\)
= -3x(2x-1) + 2(2x-1)
= (2x-1)(2-3x)
Bài làm
a) 5x2 + 5xy - x - y
= ( 5x2 + 5xy ) - ( x + y )
= 5x( x + y ) - ( x + y )
= ( x + y ) ( 5x - 1 )
b) 2x2 + 3x - 5
= 2x2 - 2x + 5x - 5
= ( 2x2 - 2x ) + ( 5x - 5 )
= 2x( x - 1 ) + 5( x - 1 )
= ( x - 1 )( 2x + 5 )
c) -6x2 + 7x - 2
= -6x2 + 3x + 4x - 2
= ( 3x + 6x2) + ( 4x - 2 )
= -3x( 2x - 1 ) + 2 ( 2x - 1 )
= ( 2x - 1 ) + ( 2 - 3x )
# Học tốt #