Question

[Khánh Vy]

Giúp mình với mai tớ ktra rồi

Answer 1

[thuongnguyen]

Bai 3

Ta co pthh

Zn+2HCl\(\rightarrow\)ZnCl2+H2

Theo de bai ta co

nZn=\(\dfrac{13}{65}=0,2mol\)

a, Theo pthh

nH2=nZn=0,2 mol

\(\Rightarrow VH2=0,2.22,4=4,48l\)

b,Theo pthh

nZnCl2=nZn=0,2 mol

\(\Rightarrow mZnCl2=0,2.136=27,2g\)

c, Theo pthh

nHCl=2nZn=2.0,2=0,4 mol

\(\Rightarrow\)VHCl=0,4.22,4=8,96 l =8960ml

d, Nong do mol/l cua muoi thu duoc la

CM=\(\dfrac{n}{v}=\dfrac{0,2}{0,2.22,4}=0,04mol\)/l

Answer 2

[thuongnguyen]

Bai 4

Ta co pthh

Fe + H2SO4\(\rightarrow\)FeSO4+H2

Theo de bai ta co

Nong do mol cua dd H2SO4 la

CM=\(\dfrac{n}{v}\Rightarrow nH2SO4=CM.vH2SO4=1.\dfrac{300}{1000}=0,3mol\)

a,Theo pthh

nFe=nH2SO4=0,3 mol

\(\Rightarrow\)mFe=0,3 . 56=16, g

b, Theo pthh

nH2=nH2SO4=0,3 mol

\(\Rightarrow\)VH2=0,3.22,4=6,72 l

c, Nong do mol cua dd muoi thu duoc la

CM=\(\dfrac{n}{v}=\dfrac{0,3}{0,3.22,4}=0,04\)(M)