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9.8+8.7+7.6+...+2.1-1.2-2.3-3.4-...-8.9
=(9.8-8.9)+(8.7-7.8)+(7.6-6.7)+...+(2.1-1.2)
=0.9+0.9+0.9+0.9+0.9+0.9+0.9+0.9
mình ko biết à nha thực ra là mình cũng đang định hỏi nè
= 2-1/1.2 + 3-2/2.3 + 4-3/3.4 + ...... + 3024-3023/3023.3024
= 1-1/2+1/2-1/3+1/3-1/4+.....+1/3023-1/3024
= 1- 1/3024 = 3023/3024
bạn hãy hãy cộng theo cặp cho dễ nhé,có 50 cặp như thế do đó là 101*50=5050
ta có 2/1.2+2/2.3+2/3.4+...+2/8.9+2/9.10
=2/1-2/2+2/2-2/3+2/3-2/4+...+2/8-2/9+2/9-2/10
=2/1-2/10
=9/5
Đặt A = \(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{8.9}+\frac{2}{9.10}\)
\(A\times2=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}+\frac{1}{9.10}\)
\(A\times2=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\)
\(A\times2=\frac{1}{1}-\frac{1}{10}\)
\(A=\frac{9}{10}\times\frac{1}{2}=\frac{9}{20}\)
D=1.2+2.3+3.4+...+19.20
=>3D=1.2.3+2.3.3+3.4.3+...+19.20
=1.2.3+2.3(4-1)+3.4(5-2)+...+19.20(21-18)
=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+19.20.21-18.19.20
=>3D=1.2.3+2.3.3+3.4.3+...+19.20
=1.2.3+2.3(4-1)+3.4(5-2)+...+19.20(21-18)
=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+19.20.21-18.19.20
=19.20.21=7980
=>D=7980:3=2660
Vậy D=2660
số số hạng là : ( 99.100 - 1.2 ) / 1.1 +1=90 ( số )
tổng của S là : ( 1.2 + 99.100 ) * 90 / 2=4513.5
\(\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\right).100-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)
\(\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right).100-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)
\(\left(1-\frac{1}{10}\right).100-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)
\(90-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)
\(\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=1\)
\(\frac{5}{2}:\left(x+\frac{266}{100}\right)=\frac{1}{2}\Rightarrow x+\frac{266}{100}=5\Rightarrow x=\frac{117}{50}\)
Vậy x = 117/50
Ta có:
\(\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\right).100\\ =\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right).100\)
\(=\left(1-\frac{1}{10}\right).100\)
\(=\frac{9}{10}.100\)
= 90
Khi đó đề bài sẽ thành : \(90-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)
\(\Rightarrow\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=1\)
\(\Rightarrow\frac{5}{2}:\left(x+\frac{266}{100}\right)=\frac{1}{2}\)
\(\Rightarrow x+\frac{266}{100}=5\)
\(\Rightarrow x=\frac{117}{50}\)
Vậy \(x=\frac{117}{50}\)
\(S=9,8+8,7+7,6+...+2,1-1,2-2,3-3,4-...-8,9\)
\(=\left(9,8-8,9\right)+\left(8,7-7,8\right)+...+\left(2,1-1,2\right)\)
\(=0,9+0,9+...+0,9\)
\(=0,9\times8=7,2\)