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88+220=(23)8+220=224+220=224(216+1)=224x17chia het cho 17
(2011x2012+2012x2013)x(1+\(\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\))
= A x(1+\(\frac{1}{3}-1\frac{1}{3}\))
=A x(\(\frac{4}{3}-1\frac{1}{3}\))
= A x 0
=0
xy-3x+y=10
(=) x.(y-3)+y=10
(=) x.(y-3)+(y-3)=7
(=) (y-3).(x+1)=7
Ta có bảng sau
y-3 | 1 | 7 | -1 | -7 |
y | 4 | 11 | 2 | -4 |
x+1 | 7 | 1 | -7 | -1 |
x | 6 | 0 | -8 | -2 |
\(35.60+35.41-35\)
\(=35.\left(60+41-1\right)\)
\(=35.100\)
\(=3500\)
\(=\left(2x+\frac{3}{4}\right)\frac{7}{9}=\frac{15}{8}\)
\(=2x+\frac{3}{4}\)\(=\frac{15}{8}:\frac{7}{9}\)
=\(2x+\frac{3}{4}=\frac{135}{56}\)
=2x=\(\frac{135}{56}-\frac{3}{4}\)
=2x=\(\frac{93}{56}\)
x=\(\frac{93}{56}:2\)
x=\(\frac{93}{112}\)
k nha
( x - 10 ) ( 2x - 30 ) = 0
\(\Rightarrow\hept{\begin{cases}x-10=0\\2x-30=0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=10\\2x=30\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=10\\x=15\end{cases}}\)
Vậy,........
A = 2/32 + 2/52 + 2/72 +.....+ 2/20212 = 2 ( 2/32 + 2/52 + 2/72 +.....+ 2/20212 )
Đặt A1 = 2/32 + 2/52 + 2/72 +.....+ 2/20212
1/32 < 1/32 - 1 = 1/2.4 = 1/2 ( 1/2 - 1/4 )
1/52 < 1/52 - 1 = 1/4.6 = 1/2 ( 1/4 - 1/6 )
2/20212 < 1/20212 - 1 = 1/ 2020.2022 = 1/2 ( 1/2020 - 1/2022 )
A1 < 1/2 ( 1/2 - 1/4 + 1/4 - 1/6 + 1/2020 - 1/2022 )
A1 < 1/2 ( 1/2 - 1/2022 ) = 1/2.1010/2022
2A1 < 2.1/2.1010/2022 nên A = 2A1 < 1010/2022
Vậy A < 1010/2022