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1) \(7.4^x=7.4^3\Leftrightarrow4^x=4^3;x=3\)
2) \(\frac{3}{2.5^x}=\frac{3}{2.5^{12}}\Leftrightarrow5^x=5^{12};x=12\)
\(2^x=2.2^8=2^9;x=9\)
4) \(5.3^x=7.3^5-2.3^5\Leftrightarrow5.3^x=3^5.\left(7-2\right)\)
\(\Leftrightarrow3^5.x=3^5.5;x=5\)
\(\Leftrightarrow3^{x-1}\left(1+5\right)=162\)
\(\Leftrightarrow3^{x-1}.6=162\)
\(\Leftrightarrow3^{x-1}=27\)
\(\Leftrightarrow x-1=3\)
\(\Leftrightarrow x=3+1=4\)
\(3^{x-1}+5.3^{x-1}=162\)
\(3^{x-1}.\left(1+5\right)=162\)
\(3^{x-1}.6=162\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Leftrightarrow x-1=3\)
\(x=4\)
Vậy x = 4
1. \(\left(-\dfrac{3}{2}\right)^2=\dfrac{9}{4}\)
\(\Rightarrow\left(-\dfrac{3}{2}\right)^x=\left(-\dfrac{3}{2}\right)^2\)
\(\Rightarrow x=2\)
2.\(3^{2x+2}=9^{10}\)
\(\Rightarrow3^{2x+2}=\left(3^2\right)^{10}\)
\(\Rightarrow3^{2x+2}=3^{20}\)
\(\Rightarrow2x+2=20\)
\(\Rightarrow2x=18\)
\(\Rightarrow x=9\)
3)\(3^{3-2x}=27^{13}\)
\(\Rightarrow3^{3-2x}=\left(3^3\right)^{13}\)
\(\Rightarrow3^{3-2x}=3^{39}\)
\(\Rightarrow3-2x=39\)
\(\Rightarrow2x=-36\)
\(\Rightarrow x=-18\)
4)\(5.3^x=7.3^5-2.3^5\)
\(\Rightarrow5.3^x=3^5\left(7-2\right)\)
\(\Rightarrow5.3^x=3^5.5\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\)
a) (2x-1)3=-8=> 2x-1=-2
<=> 2x=-1=> x=-1/2
b)
7.3x=5.37+2.37=(5+2).37=7.37
=> x=7
a, ( 2x - 1 )3 = -8
\(\Rightarrow\) 2x - 1 = -2
2x = -2 + 1
2x = -1
x = -1 : 2 = \(\frac{-1}{2}\)
b, 7 . 3x = 5 . 37 + 2 . 37
7.3x = ( 5 + 2 ) . 37
7.3x = 7. 37
Vậy x = 7
a, 5n+5n+2=650
=>5n+5n.52=650
=>5n(1+25)=650
=>5n.26=650
=>5n=25
=>5n=52
=>n=2
Vậy n=2
\(9^{x+1}+5.3^{2x}=324\)
\(9^x.9+5.\left(3^2\right)^x=324\)
\(9^x.9+5.9^x=324\)
\(9^x.\left(5+9\right)=324\)
\(9^x.14=324\)
\(9^x=\frac{324}{14}\)
\(\Rightarrow x\in\varnothing\)