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a) 2 + 3x = (-15) - 19
\(2+3x=-34\\ 3x=-34-2\\ 3x=-36\\ x=-12\)
b,\(10-2x=32\\ 2x=10-32\\ 2x=-22\\ x=-11\)
c,\(Ix-1I-5=0\)
\(\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
Vậy ...
d,\(\left(5-x\right).\left(2x+8\right)=0\)
\(\orbr{\begin{cases}5-x=0\\2x+8=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-4\end{cases}}\)
Vậy...
e, x2 - 4x = 0
x.x - 4x = 0
x. ( 1- 4 ) = 0
x. (-3) = 0
x = 0
f, 3x - 15 = 25 - 5x
3x + 5x = 25 + 15
8x = 40
x= 5
g,( x2 + 2 ) . ( 4x - 16 ) = 0
\(\orbr{\begin{cases}x^2+2=0\\4x-16=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-\sqrt{2}\\x=-4\end{cases}}\)
Vậy ...
Học tốt
a) 2 + 3x = (-15) - 19
2+3x=-34
3x=-34-2
3x=-36
x=-36:3
x=-12
b) 10 - 2x = 32
2x=10-32
2x=-22
x=-11
c) / x - 1 / - 5 = 0
|x-1|=5
* x-1=5 * x-1=-5
x=5+1 x=-5+1
x=6 x=-4
d) ( 5 - x ) . ( 2x + 8 ) = 0
* 5-x=0 * 2x+8=0
x=5-0 2x=-8
x=5 x=-8:2=-4
e) x2 - 4x = 0
x(x-4)=0
*x=0
*x-4=0
x=0+4
x=4
f) 3x - 15 = 25 - 5x
3x+5x=25+15
8x=40
x=40:8
x=5
g) ( x2 + 2 ) . ( 4x - 16 ) = 0
* x2+2=0 *4x-16=0
x2=-2 4x=16
Vô lí vì -2 ko chuyển sang mũ 2 đc x=16:4=4
a) \(450-\left(x+1\right)-2\left(x+1\right)-...-9\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(1+2+...+9\right)=450\)
\(\Leftrightarrow\left(x+1\right)\cdot45=450\)
\(\Leftrightarrow x+1=10\)
\(\Leftrightarrow x=9\)
\(\left(x^2+2\right)\left(4x-16\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}x^2+2=0\\4x-16=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x^2=-2\\x=4\end{cases}}\)
Vậy x = 4
\(1,x.\left(x+7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=-7\end{cases}}}\)
\(2,\left(x+12\right).\left(x-3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+12=0\\x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-12\\x=3\end{cases}}}\)
\(3,\left(-x+5\right).\left(3-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}-x+5=0\\3-x=0\end{cases}\Rightarrow\orbr{\begin{cases}-x=-5\\x=3\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x=3\end{cases}}}\)
\(4,24:\left(3x-2\right)=-3\)
\(3x-2=-8\)
\(3x=-6\)
\(x=-2\)
\(5,-45:5\left(-3-2x\right)=3\)
\(5\left(-3-2x\right)=-15\)
\(-3-2x=-3\)
\(2x=0\)
\(x=0\)
\(6,x.\left(2+x\right)\left(7-x\right)=0\)
\(x=0\) hoặc \(\orbr{\begin{cases}2+x=0\\7-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-2\\x=7\end{cases}}}\)
\(7,\left(x-1\right)\left(x+2\right)\left(-x+3\right)=0\)
TH1: x-1=0 TH2 : x+2=0 TH3: -x+3=0
x=1 x=-2 -x=-3 => x=3
a) 2 + 3x = -15 - 9
2+3x=-24
3x=-26
x=-26/3
Vậy x=-26/3
b) 10 - 2x = 32
<=>2x=-22
<=>x=-11
Vậy x=-11
c) [ x -1 ] - 5 = 0
|x-1|=5
<=>x-1=5 hoặc 1-x=5
<=> x=6 hoặc x=-4
Vậy \(x\in\left\{6;-4\right\}\)
d) ( 5 - x ) . ( 2x + 8 ) = 0
<=>5-x=0 hoặc 2x+8=0
<=>x=5 hoặc 2x=-8
<=>x=5 hoặc x=-4
Vậy \(x\in\left\{5;-4\right\}\)
e) x2 - 4x = 0
<=>x(x-4)=0
<=>x=0 hoặc x-4=0
<=>x=0 hoặc x=4
Vậy \(x\in\left\{0;4\right\}\)
f) 3x - 15 = 25 - 5x
<=>3x-15=25-5x
<=>3x-15-25+5x=0
<=>8x-40=0
<=>8x=40
<=>x=5
g) Bạn chưa làm rõ đề bài
a) 2+3x=-15-9
<=> 2+3x=-24
<=>3x=-26
<=> x=\(\frac{-26}{3}\)
b) 10-2x=32
<=> -2x=-22
<=> x=11
c) (x-1)-5=0
<=> x-1=5
<=> x=6
d) (5-x)(2x+8)=0
<=> 5-x=0 hoặ 2x+8=0
<=> x=5 hoặc x=-4
e) x^2 -4x=0
<=> x(x-4)=0
<=> x=0 hoặc x-4=0
<=> x=0 hoặc x=4
f) 3x-15=25-5x
<=> 3x-15-25+5x=0
<=> 8x-40=0
<=> x=5
a,\(x+1\inƯ\left(6\right)\)
\(=>x+1\in\left\{-6;-3;-2;-1;1;2;3;6\right\}\)
\(=>x\in\left\{-7;-4;-3;-2;0;1;2;5\right\}\)
b,\(\left(4x+3\right).\left(x-2\right)=0\)
\(=>\orbr{\begin{cases}4x+3=0\\x-2=0\end{cases}=>\orbr{\begin{cases}4x=-3\\x=2\end{cases}}}\)
\(=>\orbr{\begin{cases}x=\frac{-3}{4}\\x=2\end{cases}}\)
c,\(\left(15x+8\right).\left(12x-1\right)=0\)
\(=>\orbr{\begin{cases}15x+8=0\\12x-1=0\end{cases}}=>\orbr{\begin{cases}15x=-8\\12x=1\end{cases}}\)
\(=>\orbr{\begin{cases}x=\frac{-8}{15}\\x=\frac{1}{12}\end{cases}}\)
e,\(xy-x+y=6\)
\(=>x.\left(y-1\right)+y-1=5\)
\(=>\left(x+1\right).\left(y-1\right)=5\)
Ta có bảng sau :
tự lập bảng =))
a) \(\left(x-5\right)-\frac{1}{3}=\frac{2}{5}\)
\(\Rightarrow\left(x-5\right)=\frac{2}{5}+\frac{1}{3}\)
\(\Rightarrow\left(x-5\right)=\frac{11}{15}\)
\(\Rightarrow x-5=\frac{11}{15}\)
\(\Rightarrow x=\frac{11}{15}+5\)
\(\Rightarrow x=\frac{86}{15}\)
b) \(\frac{2}{3}\cdot x-\frac{3}{2}\cdot x=\frac{5}{12}\)
\(\Rightarrow x\cdot\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}\)
\(\Rightarrow x\cdot\left(-\frac{5}{6}\right)=\frac{5}{12}\)
\(\Rightarrow x=\frac{5}{12}:\left(-\frac{5}{6}\right)\)
\(\Rightarrow x=-\frac{1}{2}\)
c) \(-\frac{2}{3}\cdot x+\frac{1}{5}=\frac{3}{10}\)
\(\Rightarrow-\frac{2}{3}\cdot x=\frac{3}{10}-\frac{1}{5}\)
\(\Rightarrow-\frac{2}{3}\cdot x=\frac{1}{10}\)
\(\Rightarrow x=\frac{1}{10}:\left(-\frac{2}{3}\right)\)
\(\Rightarrow x=-\frac{3}{20}\)
d) \(4-\left(\frac{1}{2}\cdot x+\frac{3}{4}\right)=-\frac{1}{5}\)
\(\Rightarrow\left(\frac{1}{2}\cdot x+\frac{3}{4}\right)=4-\left(-\frac{1}{5}\right)\)
\(\Rightarrow\)\(\frac{1}{2}\cdot x+\frac{3}{4}=\frac{21}{5}\)
\(\Rightarrow\)\(\frac{1}{2}\cdot x=\frac{21}{5}-\frac{3}{4}\)
\(\Rightarrow\)\(\frac{1}{2}\cdot x=\frac{69}{20}\)
\(\Rightarrow\)\(x=\frac{69}{20}:\frac{1}{2}\)
\(\Rightarrow\)\(x=\frac{69}{10}\)
a) \(\frac{3}{4}x-\frac{1}{4}=2\left(x-3\right)+\frac{1}{4}x\)
\(\frac{3}{4}x-\frac{1}{4}=2x-6+\frac{1}{4}x\)
\(\frac{3}{4}x-2x-\frac{1}{4}x=\frac{1}{4}-6\)
\(x\left(\frac{3}{4}-2-\frac{1}{4}\right)=-\frac{23}{4}\)
\(-\frac{3}{2}x=-\frac{23}{4}\)
\(x=-\frac{23}{4}\div\left(-\frac{3}{2}\right)\)
\(x=\frac{23}{6}\)
Bài 1 :
\(2^x.8=512\)
\(2^x=512:8\)
\(2^x=64\)
\(2^x=2^6\)
\(\Rightarrow x=6\)
\(b,\left(2x+1\right)^3=125\)
\(\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
\(c,x^{20}=x\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
\(d,\left(x-3\right)^{10}=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
a) 2x - 8 = 5
2x = 5 + 8
2x = 13
x = \(\frac{13}{2}\)
b) ( 6x - 12 ) . ( x + 5 ) = 0
\(\Rightarrow\orbr{\begin{cases}6x-12=0\\x+5=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\\x=-5\end{cases}}\)
c) |2x - 1 | + 3 = 62
|2x - 1 | + 3 = 36
|2x - 1 | = 36 - 3
|2x - 1 | = 33
\(\Rightarrow\orbr{\begin{cases}2x-1=33\\2x-1=-33\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=17\\x=-16\end{cases}}\)
d) 4x - 3 = 2 . ( x + 2 ) - 17
4x - 3 = 2x + 4 - 17
4x - 2x = 4 - 17 + 3
2x = -10
x = -10 : 2
x = -5
a) 2x - 8 = 5
2x = 5 + 8
2x = 13
x = 13/2
vậy x = 13/2
b) ( 6x - 12 ).( x + 5 ) = 0
=> 6x - 12 = 0
x + 5 = 0
=> x = 2
x = -5
vậy x = 2; -5
c) | 2x - 1 | + 3 = 6^2
| 2x - 1 | + 3 = 36
| 2x - 1 | = 36 - 3
| 2x - 1 | = 33
* 2x - 1 = 33
2x = 34
x = 34 : 2
x = 17
* 2x - 1 = -33
2x = -33 + 1
2x = 32
x = 32 : 2
x = 16
vậy x thuộc {17; 16}