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A =\(\frac{2^2-1}{2^2}\)+ \(\frac{3^2-1}{3^2}\)+ \(\frac{4^2-1}{4^2}\)+,,,+
= 1 - \(\frac{1}{2^2}\)+ 1 - \(\frac{1}{3^2}\)+ ...+ 1 - \(\frac{1}{30^2}\)
= ( 1+ 1+1 +... + 1 ) - ( \(\frac{1}{2^2}\)+ \(\frac{1}{3^2}\)+ ... +\(\frac{1}{30^2}\))
= 29 - ( \(\frac{1}{2^2}\)+ \(\frac{1}{3^2}\)+ ... +\(\frac{1}{30^2}\))
Vậy A không là số nguyên
\(A=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\frac{899}{900}=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}....\frac{29.31}{30.30}=\frac{1.3.2.4.3.5...29.31}{2.2.3.3.4.4...30.30}=\frac{\left(1.2.3...29\right)\left(3.4.5...31\right)}{\left(2.3.4...30\right)\left(2.3.4...30\right)}\)
\(=\frac{1.31}{30.2}=\frac{31}{60}\)
\(A=\frac{3}{4}+\frac{8}{9}+\frac{15}{16}+...+\frac{899}{900}\)
\(A=\left(1-\frac{1}{4}\right)+\left(1-\frac{1}{9}\right)+\left(1-\frac{1}{16}\right)+...+\left(1-\frac{1}{900}\right)\)
\(A=\left(1+1+1+...+1\right)-\left(\frac{1}{4}+\frac{1}{9}+\frac{1}{16}+...+\frac{1}{900}\right)\)
\(A=29-\left(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{30^2}\right)\)
đặt \(B=\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{30^2}\)
Ta thấy \(\frac{1}{2^2}< \frac{1}{1.2}\); \(\frac{1}{3^2}< \frac{1}{2.3}\); \(\frac{1}{4^2}< \frac{1}{3.4}\); ... ; \(\frac{1}{30^2}< \frac{1}{29.30}\)
\(\Rightarrow B< \frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{29.30}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{29}-\frac{1}{30}\)
\(=1-\frac{1}{30}< 1\)
\(\Rightarrow B< 1\)
\(\Rightarrow A=29-\left(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{30^2}\right)< 29\)
a ) 13/20
B)
C..........................................................
minh dang tính
a ) \(-\frac{3}{7}.\frac{3}{11}+-\frac{3}{7}.\frac{8}{11}+1\frac{3}{7}\)
\(=-\frac{3}{7}.\left(\frac{3}{11}+\frac{8}{11}\right)+\frac{10}{7}\)
\(=-\frac{3}{7}.\frac{11}{11}+\frac{10}{7}\)
\(=-\frac{3}{7}.1+\frac{10}{7}\)
\(=\frac{10}{7}\)
b ) \(75\%.10,5=\frac{3}{4}.10,5=7,875\)
c ) \(5-3.\left(\left|-4\right|-30:15\right)\)
\(=5-3.\left(4-2\right)\)
\(=5-3.2\)
\(=5-6\)
\(=-1\)
d ) \(-\frac{5}{7}.\frac{2}{11}+-\frac{5}{7}.\frac{9}{11}+1\frac{5}{7}\)
\(=-\frac{5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)
\(=-\frac{5}{7}.1+\frac{12}{7}\)
\(=\frac{7}{7}\)
\(=1\)
Chúc bạn học tốt !!!
A = \(\dfrac{3}{4}.\dfrac{8}{9}.\dfrac{15}{16}....\dfrac{899}{900}\)
= \(\left(\dfrac{1.3}{2.2}\right).\left(\dfrac{2.4}{3.3}\right).\left(\dfrac{3.5}{4.4}\right)...\left(\dfrac{29.31}{30.30}\right)\)
= \(\left[\left(1.2.3...29\right).\left(3.4.5...31\right)\right]:\left[\left(2.3.4...30\right).\left(2.3.4...30\right)\right]\)
= \(\dfrac{1.2.3...29}{2.3.4...30}.\dfrac{3.4.5...31}{2.3.4...30}\)
= \(\dfrac{1}{30}.\dfrac{31}{2}\)
= \(\dfrac{31}{62}\)
A= \(\dfrac{3}{4}\).\(\dfrac{8}{9}\).\(\dfrac{15}{16}\).....\(\dfrac{899}{900}\)
A= \(\dfrac{1.3}{2.2}\).\(\dfrac{2.4}{3.3}\).\(\dfrac{3.5}{4.4}\).....\(\dfrac{29.31}{30.30}\)
A= \(\dfrac{\left(1.2.3....29\right)}{\left(2.3.4....30\right)}\) . \(\dfrac{\left(3.4.5....31\right)}{\left(2.3.4....30\right)}\)
A= \(\dfrac{1.2.3....29}{2.3.4....30}\) . \(\dfrac{3.4.5...31}{2.3.4...30}\)
A= \(\dfrac{1}{30}\) . \(\dfrac{31}{2}\)
A= \(\dfrac{31}{6}\)
\(=\left(2x+\frac{3}{4}\right)\frac{7}{9}=\frac{15}{8}\)
\(=2x+\frac{3}{4}\)\(=\frac{15}{8}:\frac{7}{9}\)
=\(2x+\frac{3}{4}=\frac{135}{56}\)
=2x=\(\frac{135}{56}-\frac{3}{4}\)
=2x=\(\frac{93}{56}\)
x=\(\frac{93}{56}:2\)
x=\(\frac{93}{112}\)
k nha
a. (-7) . (-13) + 8 . (-13) = (-7 + 8) . (-13) = 1 . (-13) = -13
b. (-5) . [-4 - (-14)] = (-5) . (-4) - (-5) . (-14) = (-5) . 10 = -50