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a, Thiếu 1 vế
b, Xét vế trái:
7520 = 2520 . 320
= 520. 520 . 320
= 530.510.310.310
= 530.4510 = Vế phải
=> 7520 = 4510.530 (Đpcm)
b)
Ta có:
\(75^{20}=45^{10}.5^{30}\\ hay\left(5^2.3\right)^{20}=\left(5.3^2\right)^{10}.5^{30}\\ 5^{40}.3^{20}=5^{10}.3^{20}.5^{30}\\ 5^{40}.3^{20}=5^{40}.3^{20}\)
Vậy \(75^{20}=45^{10}.5^{30}\left(ĐPCM\right)\)
Câu a hình như sai đề, không làm được
a) 128 . 912 = ( 3 . 22 )8 . ( 32 )12
= 38 . 216 . 324 = 332 . 216 = ( 32 )16 . 216 = ( 32 . 2 )16 = 1816
b) 4510 . 530 = 4510 . ( 53 )10
= ( 45 . 53 )10 = 562510
Mà 7520 = ( 752 )10 = 562510
Vậy 4510 . 530 = 7520
a đề sai
b) 75^20 = ( 5*5*3)^20= 5^40 * 3^20 = 5^30 * ( 5^10 * 9^10)= 5^30 * 45^10.
\(12^8.12^{16}=12^{24}=\left(2^2.3\right)^{24}=2^{48}.3^{24}=2^{32}.2^{16}.3^{24}\)
\(4^{16}.3^{40}=\left(2^2\right)^{16}.3^{40}=2^{32}.3^{40}=2^{32}.3^{24}.3^{16}\)
\(12^8.12^{16}\ne4^{16}.3^{40}\)
\(75^{20}=\left(3.5^2\right)^{20}=3^{20}.5^{40}\)
\(45^{10}.5^{30}=\left(3^2.5\right)^{10}.5^{30}=3^{20}.5^{40}\)
\(75^{20}=45^{10}.5^{30}\)
a) Ta có : \(45^{10}=5^{10}.3^{20}\)
\(\Rightarrow45^{10}.5^{30}=3^{20}.5^{10}.5^{30}=3^{20}.5^{40}=3^{20}.\left(5^2\right)^{20}=3^{20}.25^{20}=\left(3.25\right)^{20}=75^{20}\)
Vậy \(45^{10}.5^{30}=75^{20}\)
b) Ta có : \(12^8=3^8.2^{16}\)và \(9^{12}=3^{24}\)
\(\Rightarrow12^8.9^{12}=3^8.2^{16}.3^{24}=2^{16}.\left(3^2\right)^{16}=2^{16}.9^{16}=\left(2.9\right)^{16}=18^{16}\)
Vậy \(12^8.9^{12}=18^{16}\)
a/ 12^8*18^16=3^8*2^16*2*16*3^32=3^40*2^32
b/ 45^10*5^30=45^10*125^10=5625^10+75^20
kb với mk nhé
a, \(12^8.18^{16}=\left(2^2.3\right)^8.\left(2.3^2\right)^{16}=2^{16}.3^8.2^{16}.3^{32}=2^{32}.3^{40}\)
b, \(75^{20}=\left(5^2.3\right)^{20}=5^{40}.3^{20}=5^{40}.\left(3^2\right)^{10}=5^{30}.5^{10}.9^{10}=5^{30}.\left(5.9\right)^{10}=5^{30}.45^{10}\)
Ta có : 128 . 912 = ( 3. 4 )8. (32)12
= 38. 48. 324
= (22)8. 332
=216. (32)16
= 216. 916
= (2 . 9)16
=1816
ý thứ hai làm tương tự
a.\(2^{225}=\left(2^3\right)^{75}=8^{75}\left(1\right)\)
\(3^{150}=\left(3^2\right)^{75}=9^{75}\left(2\right)\)
\(\left(1\right),\left(2\right)\Rightarrow2^{225}< 3^{150}\)
b.\(2^{91}=2^{7.13}=\left(2^{13}\right)^7=8192^7\left(1\right)\)
\(5^{35}=5^{7.5}=\left(5^5\right)^7=3125^7\left(2\right)\)
\(\left(1\right),\left(2\right)\Rightarrow5^{35}< 2^{91}\)
c.\(9999^{10}=\left(99.101\right)^{10}=99^{10}.101^{10}>99^{10}.99^{10}=99^{20}\)
\(\Rightarrow9999^{10}>99^{20}\)
Bài 2:
\(b.\)\(75^{20}=\left(3.5^2\right)^{20}=\left(3^{20}.5^{10}\right).5^{30}=\left[̣\left(3^2\right)^{10}.5^{10}\right].5^{30}=45^{10}.5^{30}\)
\(\Rightarrowđpcm\)
Bài 3:
a,\(25^4.2^8=\left(5^2\right)^4.2^8=5^8.2^8=10^8\)
b. \(\frac{27^2}{25^3}=\frac{\left(3^3\right)^2}{\left(5^2\right)^3}=\frac{3^6}{5^6}=\left(\frac{3}{5}\right)^3\)\(:v\)
\(27^2.25^3=3^6.5^6=15^6\)( đề phòng you viết sai đề )
a) \(12^8.9^{12}=18^{16}\)
ta cóvế trái : \(12^8.9^{12}=\left(2^2.3\right)^8.\left(3^2\right)^{12}=2^{16}.3^8.3^{24}=2^{16}.3^{32}\)
vế phải :\(18^{16}=\left(2.3^2\right)^{16}=2^{16}.3^{32}\)
=> VT =VP
b) \(75^{20}=45^{10}.5^{30}\)
VT=\(75^{20}=\left(3.5^2\right)^{20}=3^{20}.5^{40}\)
VP = \(45^{10}.5^{30}=\left(2^2.5\right)^{10}.5^{30}=2^{20}.5^{30}\)
ta tháy VT=VP
=> ĐPCM