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a) s=(14+14)/2
S=14 m2
b) S(MICA)= 28m2
c) S(MICK)=73.5m2
A B M C
a) M điểm giữa của BC nên CM = MB
Tam giác ABM và tam giác ACM có : đáy CM = MB, chung đường cao tương ứng với đáy.
Nên S(ABM) = S(ACM)
b) S(ABC) = S(ABM) + S(ACM) mà S(ABM) = S(ACM)
Nên \(S\left(ABM\right)=\frac{1}{2}S\left(ABC\right)\)
1/2 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000% luob
Gấp 3 lần phải không bạn ?