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S=1/1.3.5 +1/3.5.7+...................+1/19.21.23
---> 4S=4/1.3.5 + 4/ 3.5.7 +.........................+4/19.21.23
= (1/1.3 -1/3.5 ) + ( 1/3.5 -1/3.7) +...................................+(1/... -1/21.23 )
= 1/1.3 -1/21.23
= 1/3 -1/483 =160/483
----> S = 160/483 : 4 = 160 / 1932
(em tự rút gọn nhé! )S=1/1.3.5 +1/3.5.7+...................+1/19.21.23
---> 4S=4/1.3.5 + 4/ 3.5.7 +.........................+4/19.21.23
= (1/1.3 -1/3.5 ) + ( 1/3.5 -1/3.7) +...................................+(1/... -1/21.23 )
= 1/1.3 -1/21.23
= 1/3 -1/483 =160/483
----> S = 160/483 : 4 = 160 / 1932
(em tự rút gọn nhé! )
M=1/1.3.5 +1/3.5.7+.....+1/19.21.23
4M=4/1.3.5 + 4/ 3.5.7 +...+4/19.21.23
= (1/1.3 -1/3.5 ) + ( 1/3.5 -1/3.7) +....+(1/19.21 -1/21.23 )
= 1/1.3 -1/21.23
= 1/3 -1/483
=160/483
⇒ S = 160/483 : 4
= 160 / 1932
=40/438
\(M=\dfrac{1}{31}+\dfrac{1}{32}+.................+\dfrac{1}{89}+\dfrac{1}{90}\)
\(\Leftrightarrow M=\left(\dfrac{1}{31}+\dfrac{1}{32}+.........+\dfrac{1}{60}\right)+\left(\dfrac{1}{61}+\dfrac{1}{62}+........+\dfrac{1}{90}\right)\)
Đặt :
\(A=\dfrac{1}{31}+\dfrac{1}{32}+.......+\dfrac{1}{60}>\dfrac{1}{60}+\dfrac{1}{60}+.......+\dfrac{1}{60}=\dfrac{1}{60}.30=\dfrac{1}{2}\)
\(B=\dfrac{1}{61}+\dfrac{1}{62}+.......+\dfrac{1}{90}>\dfrac{1}{90}+\dfrac{1}{90}+......+\dfrac{1}{90}=\dfrac{1}{90}.30=\dfrac{1}{3}\)
\(\Leftrightarrow M=\dfrac{1}{31}+\dfrac{1}{32}+.........+\dfrac{1}{89}+\dfrac{1}{90}=A+B< \dfrac{1}{2}+\dfrac{1}{3}=\dfrac{5}{6}\)
\(\Leftrightarrow M< \dfrac{5}{6}\rightarrowđpcm\)
Help me! Please!