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A) \(\frac{4}{5}+\frac{5}{4}-2=\frac{16}{20}+\frac{25}{20}-\frac{40}{20}\)
\(=\frac{1}{20}\)
B) \(3-\frac{2}{3}-\frac{3}{2}=\frac{18}{6}-\frac{4}{6}-\frac{9}{6}\)
\(=\frac{5}{6}\)
C) \(\frac{7}{8}-\left(\frac{1}{4}+\frac{2}{5}\right)=\frac{7}{8}-\frac{13}{20}\)
\(=\frac{35}{40}-\frac{26}{40}=\frac{9}{40}\)
D) \(\frac{9}{10}-\left(\frac{2}{5}+\frac{3}{10}\right)+\frac{7}{10}=\frac{9}{10}-\frac{7}{10}+\frac{7}{10}\)
\(=\frac{9}{10}\)
Ta có:\(x.\frac{1}{5}+x.\frac{4}{5}=2\)
=>\(x.\frac{1}{5}+\frac{4}{5}=2\)
=>\(x.\frac{5}{5}=2\)
=>\(x.1=2\)
=>\(x=2:1\)
=>\(x=2\)
= 3/4 + 5/6 x 3/2 + 1/5
= 3/4 + 5/4 + 1/5
= 15/20 + 25/20 + 4/20
= 44/20
= 11/5
TL
\(\frac{3}{4}+\frac{5}{6}:\frac{2}{3}+\frac{1}{5}\)
\(=\frac{3}{4}+\frac{5}{4}+\frac{1}{5}\)
\(=\frac{11}{5}\)
nhaaaaaaa
HT
\(\frac{2}{6}+\frac{9}{24}\)
\(=\frac{8}{24}+\frac{9}{24}\)
\(=\frac{17}{24}\)
Tương Tự vs các câu còn lại
\(\frac{7}{2}+\frac{1}{3}-\frac{5}{2}\)
\(=\left(\frac{7}{2}-\frac{5}{2}\right)+\frac{1}{3}\)
\(=1+\frac{1}{3}\)
\(=\frac{4}{3}\)
a: \(x:5=\dfrac{15}{14}\\ \Rightarrow x=\dfrac{15}{70}=\dfrac{3}{14}\)
a) \(\dfrac{5}{3}+\dfrac{4}{9}:\dfrac{1}{2}=\dfrac{5}{3}+\dfrac{4}{9}\times2=\dfrac{5}{3}+\dfrac{8}{9}=\dfrac{23}{9}\)
b) \(\dfrac{11}{10}-\dfrac{2}{5}:\dfrac{2}{3}=\dfrac{11}{10}-\dfrac{2}{5}\times\dfrac{3}{2}=\dfrac{11}{10}-\dfrac{3}{5}=\dfrac{11}{10}-\dfrac{6}{10}=\dfrac{5}{10}=\dfrac{1}{2}\)
Câu 4
\(\dfrac{12\times15\times20}{10\times16\times25}=\dfrac{3\times4\times3\times5\times4\times5}{5\times2\times4\times4\times5\times5}=\dfrac{3\times3}{5\times2}=\dfrac{9}{10}\)
Câu 3:
\(a.\dfrac{5}{3}+\dfrac{4}{9}:\dfrac{1}{2}=\dfrac{5}{3}+\dfrac{8}{9}=\dfrac{15}{9}+\dfrac{8}{9}=\dfrac{23}{9}\)
\(b.\dfrac{11}{10}-\dfrac{2}{5}:\dfrac{2}{3}=\dfrac{11}{10}-\dfrac{3}{5}=\dfrac{11}{10}-\dfrac{6}{10}=\dfrac{5}{10}=\dfrac{1}{2}\)
Câu 4:
\(\dfrac{12\times15\times20}{10\times16\times25}=\dfrac{3\times3\times1}{2\times1\times5}=\dfrac{9}{10}\)