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\(a,\left(7x-11\right)^3=2^5.5^2+200.\)
\(\left(7x+11\right)^3=32.25+200.\)
\(\left(7x+11\right)^3=800+200.\)
\(\left(7x-11\right)^3=1000.\)
\(\left(7x-11\right)^3=10^3.\)
\(\Rightarrow7x-11=10.\)
\(\Rightarrow x=\left(10+11\right):3=7\in Z.\)
Vậy.....
\(b,3^x+25=26.2^2+2.3^0.\)
\(3^x+25=26.4+2.\)
\(3^x+25=104+2.\)
\(3^x+25=106.\)
\(3^x=106-25.\)
\(3^x=81.\)
\(3^x=3^4\Rightarrow x=4\in Z.\)
Vậy.....
\(c,2^x+3.2=64.\)(có vấn đề).
\(d,5^{x+1}+5^x=750.\)
\(5^x.5^1+5^x+1=750.\)
\(5^x\left(5^1+1\right)=750.\)
\(5^x\left(5+1\right)=750.\)
\(5^x.6=750.\)
\(5^x=750:6.\)
\(5^x=125.\)
\(5^x=5^3\Rightarrow x=3\in Z.\)
Vậy.....
\(e,x^{15}=x.\)
\(\Rightarrow x\left(x^{14}-1\right)=0\Rightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right..\)
\(f,\left(x-5\right)^4=\left(x-5\right)^6.\)
\(\Leftrightarrow\left(x-5\right)^4-\left(x-5^6\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(1-x+5\right)\left(1+x-5\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(6-x\right)\left(x-4\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4=0\Rightarrow x-5=0\Rightarrow x=5\in Z.\)
\(6-x=0\Rightarrow x=6\in Z.\)
\(x-4=0\Rightarrow x=4\in Z.\)
Vậy.....
a, 4^x +4^x .4 =20
4^x(1+4) =20
4^x .5 =20
4^x =20:5
4^x = 4
x = 1
b,7^x .7^2=7^90
7^x = 7^90:7^2
7^x =7^88
x = 88
c, 5^x +5^x.5 = 750
5^x(1+5) =750
5^x . 6 =750
5^x = 750:6
5^x =125
5^x = 5^3
x =3
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\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
1) 3^4.2+2^3.5-7(5^7:5^5)
=3^4.2+2^3.5-7.5^2
=81.2+8.5-7.25
=162+40-175
=202-175=27
2) 5.2^2.2^3-4(5^8:5^6)
=5.4.8-3.5^2
=160-100=60
3) (3^5.3^7):3^10+5.2^4-7^3:7
=3^12:3^10+5.16-7^2
=3^2+80-7^2
=9+80-49=40
4) 15:(3^5:3^4)-2^9:2^7
=15:3-2^2
=5-4=1
5) 5.3^5:(3^8:3^5)-2^3.5
=5.3^5:3^3-8.5
=5.3^2-40
=5.9-40
=45-40=5
Quy ước toán học dấu x = dấu .
===================================
1. (3x - 5)4 = 28
<=> (3x - 5)4 = 44
=> Ta có 2 trường hợp :
* TH1 : \(3^x-5=4\Rightarrow3^x=9\Rightarrow x=2\)
* TH2 : \(3^x-5=-4\Rightarrow3^x=1\Rightarrow x=0\)
Vậy x=1 hoặc x=0