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a) 126+ (-29)+ 2004+ (-106)
= [126+ (-106)] +2004+ (-29)
= 20+ 2004- 29
= 2024-29
= 1995
b) (-199)+ (-200)+ (-201)
= -(199+200+201)
= -600
a) 126 + (-20) + 2004 + (-106)
= [126 + (-20) + (-106)] + 2004
= 0 + 2004
= 2004
b) (-199) + (-200) + (-201)
= [(-199) + (-201)] + (-200)
= (-400) + (-200)
= -600
a) 126 + (-20) + 2004 + (-106) = 126 + 2004 + (-20) + (-106)
= 2130 + [- (20 + 106)] = 2130 + (-126) = 2130 – 126 = 2004.
b) (-199) + (-200) + (-201) = – (199 + 200 + 201)
= – (199 + 201 + 200) = – [(199 + 201) + 200] = – (400 + 200) = -600.
a) 126 + (-20) + 2004 + (-106) = 126 + 2004 + (-20) + (-106)
= 2130 + [- (20 + 106)] = 2130 + (-126) = 2130 – 126 = 2004.
b) (-199) + (-200) + (-201) = – (199 + 200 + 201)
= – (199 + 201 + 200) = – [(199 + 201) + 200] = – (400 + 200) = -600.
a) 126 + (-20) + 2004 + (-106)
= 106 + 1898
= 2004
b) (-199) + (-200) + (-201)
= (-399) + (-201)
= -600
a) 126 + ( -20) + 2004 +( -106 )
B1 : Bỏ các dấu ngoặc :
=126 - 20 + 2004 -106
B2 : Tính :
= 2004
b) ( -199 ) + ( -200 ) + ( -201 )
B1 : Bỏ ngoặc
= ( -199 ) -200 -201
B2 : Tính :
= -600
a) 26+(-20+20040+(-106)
=126+(2004-20)+(-106)
=126+1804+(-106)
=1930+(-106)
=1930-106
=1824
Chỉ help thế thui nha
a: \(\left(2345+45\right)-2345\)
\(=2345+45-2345\)
\(=45+\left(2345-2345\right)\)
=45+0
=45
b: \(\left(-2010\right)-\left(119-2010\right)\)
\(=-2010-119+2010\)
\(=\left(-2010+2010\right)-119\)
=0-119
=-119
c: \(\left(18+29\right)+\left(158-18-29\right)\)
\(=18+29+158-18-29\)
\(=158+\left(18-18\right)+\left(29-29\right)\)
=158+0+0
=158
d: \(126+\left(-20\right)+2004+\left(-106\right)\)
\(=126-20+2004-106\)
\(=\left(126-20-106\right)+2004\)
=0+2004
=2004
e: \(\left(-199\right)+\left(-200\right)+\left(201\right)\)
\(=-199-200+201\)
\(=-199+\left(201-200\right)\)
=-199+1
=-198
f: \(99+\left(-100\right)+101\)
\(=\left(99+101\right)-100\)
=200-100
=100
g: \(217+\left[43+\left(-217\right)+\left(-23\right)\right]\)
\(=217+43-217-23\)
\(=\left(217-217\right)+\left(43-23\right)\)
=0+20
=20
126+-20+2004+-106
=(126+-106+-20)+2004
=0+2004=2004
-199+-200+-201
=(-199+-201)+-200
=-400+-200
=-600
\(\frac{199}{200}>\frac{199}{200+201+202}\)
\(\frac{200}{201}>\frac{200}{200+201+202}\)
\(\frac{201}{202}>\frac{201}{200+201+202}\)
=>\(A>B\)
Do \(\frac{199}{200}\)> \(\frac{199}{200+201+202}\), \(\frac{200}{201}\)>\(\frac{200}{200+201+202}\),\(\frac{201}{202}\)>\(\frac{201}{200+201+202}\)nên A>B
\(A=\frac{199}{200}+\frac{200}{201}+\frac{201}{202}< \frac{199}{200+201+202}+\frac{200}{200+201+202}+\frac{201}{200+201+202}\)
A \(< \frac{199+200+201}{200+201+202}=B\)
\(A< B\)
Ta có: \(A=\frac{199}{200}+\frac{200}{201}+\frac{201}{202}< \frac{199}{200+201+202}+\frac{200}{200+201+202}+\frac{201}{200+201+202}< \)
\(< \frac{199+200+201}{200+201+202}\)
Vậy A < B
ỦNG HỘ TỚ NHA
a) 126+(−20)+2004+(−106)
=2004+126+[(−20)+(−106)]
=2004+126+[−(20+106)]
=2004+126+(−126)
=2004+[126+(−126)]=2004+0=2004.
b) (−199)+(−200)+(−201)=−(199+200+201)
=−(199+201+200)=−[(199+201)+200]
=−(400+200)=−600.