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6 tháng 8 2020

a/ \(ax-2x-a^2+2a\)

\(=x\left(a-2\right)-a\left(a-2\right)\)

\(=\left(x-a\right)\left(a-2\right)\)

Vậy....

b/ \(x^2+x-ax-a\)

\(=x\left(x+1\right)-a\left(x+1\right)\)

\(=\left(x+1\right)\left(x-a\right)\)

Vậy...

d/ \(2xy-ax+x^2-2ay\)

\(=2y\left(x-a\right)+x\left(x-a\right)\)

\(=\left(x-a\right)\left(2y+x\right)\)

e/ \(x^3+ax^2+x+a\)

\(=x^2\left(x+a\right)+\left(x+a\right)\)

\(=\left(x^2+1\right)\left(x+a\right)\)

Vậy...

13 tháng 8 2018

\(x\cdot\left(a-2\right)-a\left(a-2\right)\)

\(\left(x-a\right)\cdot\left(a-2\right)\)

b ,\(x\left(x+1\right)-a\left(x+1\right)\)

\(\left(x-a\right)\cdot\left(x+1\right)\)

c ,\(2x\left(x+2a\right)+x+2a\)

(2x+1)(x+2a)

d, 2xy+x^2-ax-2ay

x(2y+x)-a(x+2y)

(x-a)(x+2y)

e, x^2(x+a)+x+a

(x^2+1)(x+a)

f, y^2(y+x^2)+z(x^2+y)

(y^2+z)(y+x^2)

29 tháng 7 2018

a) ax - 2x - a2 + 2a

= ( ax - 2x ) - ( a2 - 2a )

= x ( a - 2 ) - a ( a - 2 )

= ( a - 2 ) ( x - a )

b) x2 + x - ax - a

= ( x2 + x ) - ( ax + a )

= x ( x + 1 ) - a ( x + 1 )

= ( x + 1 ) ( x - a )

Hok Tốt!!!

29 tháng 7 2018

a) ax -2x- a2+ 2a

= (ax -2x ) -(a2 -2a )

= x(a-2) -a ( a-2 )

= (x-a) (a-2)

b) x2 +x -ax -a

=( x2 +x ) - ( ax +a )

= x( x+1 ) -a ( x+1 )

= ( x-a ) (x+ 1)

c) 2x2 +4ax +x +2a

=( 2x2 + 4ax )  + ( x+ 2a )

= 2x ( x+ 2a ) + ( x+2a )

= ( 2x +1 ) (x+2a )

d) 2xy -ax +x2 - 2ay

= (2xy -2ay ) + (  -ax + x2 )

= 2y( x-a ) + x ( x-a)

= ( 2y +x ) ( x -a )

17 tháng 7 2019

\(a,xy+1-x-y\)

\(=\left(xy-y\right)+\left(1-x\right)\)

\(=y\left(x-1\right)- \left(x-1\right)\)

\(=\left(x-1\right)\left(y-1\right)\)

\(b,ax+ay-3x-3y\)

\(=a\left(x+y\right)-3\left(x+y\right)\)

\(=\left(x+y\right)\left(a-3\right)\)

\(c,x^3-2x^2+2x-4\)

\(=x^2\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x^2+2\right)\left(x-2\right)\)

\(d,x^2+ab+ax+bx\)

\(=\left(x^2+ax\right)+\left(ab+bx\right)\)

\(=x\left(a+x\right)+b\left(a+x\right)\)

\(=\left(a+x\right)\left(b+x\right)\)

\(e,16-x^2+2xy-y^2\)

\(=4^2-\left(x^2-2xy+y^2\right)\)

\(=4^2-\left(x-y\right)^2\)

\(=\left(4-x+y\right)\left(4+x-y\right)\)

17 tháng 7 2019

\(f,ax^2+ax-bx^2-bx-a+b\)

\(=\left(ax^2-bx^2\right)+\left(ax-bx\right)-\left(a-b\right)\)

\(=x^2\left(a-b\right)+x\left(a-b\right)-\left(a-b\right)\)

\(=\left(a-b\right)\left(x^2+x-1\right)\)

16 tháng 7 2018

câu 2 nx

17 tháng 7 2019

Hỏi đáp Toán

17 tháng 7 2019

a) \(xy+1-x-y\)

\(=x\left(y-1\right)-\left(y-1\right)\)

\(=\left(y-1\right)\left(x-1\right)\)

b) \(ax+ay-3x-3y\)

\(=a\left(x+y\right)-3\left(x+y\right)\)

\(=\left(x+y\right)\left(a-3\right)\)

c) \(x^3-2x^2+2x-4\)

\(=x^2\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2+2\right)\)

d) \(x^2+ab+ax+bx\)

\(=x\left(b+x\right)+a\left(b+x\right)\)

\(=\left(b+x\right)\left(a+x\right)\)

e) \(16-x^2+2xy-y^2\)

\(=16-\left(x^2-2xy+y^2\right)\)

\(=4^2-\left(x-y\right)^2\)

\(=\left(4-x+y\right)\left(4+x-y\right)\)

f) \(ax^2+ax-bx^2-bx-a+b\)

\(=\left(ax^2+ax-a\right)-\left(bx^2+bx-b\right)\)

\(=a\left(x^2+x-1\right)-b\left(x^2+x-1\right)\)

\(=\left(x^2+x-1\right)\left(a-b\right)\)

12 tháng 10 2018

\(a,ax+by+ay+bx=\left(ax+ay\right)+\left(by+bx\right)=a\left(x+y\right)+b\left(x+y\right)=\left(a+b\right)\left(x+y\right)\)

\(b,x^2y+xy+x+1=xy\left(x+1\right)+\left(x+1\right)=\left(xy+1\right)\left(x+1\right)\)

\(c,x^2-ax-bx+ab=x\left(x-a\right)-b\left(x-a\right)=\left(x-b\right)\left(x-2\right)\)

\(d,x^2y+xy^2-x-y=xy\left(x+y\right)-\left(x+y\right)=\left(xy-1\right)\left(x+y\right)\)

12 tháng 10 2018

\(e,a\left(x^2+y\right)-b\left(x^2+y\right)=\left(a-b\right)\left(x^2+y\right)\)

\(f,x\left(a-2\right)-a\left(a-2\right)=\left(x-a\right)\left(a-2\right)\)

21 tháng 7 2017

Câu hỏi của Mã Thu Thu

Chúc bạn học tốt!!!

21 tháng 7 2017

Thank!!! banhqua

c) \(x^2+x-ax-a\)

\(=x\left(x+1\right)-a\left(x+1\right)\)

\(=\left(x+1\right)\left(x-a\right)\)

d) \(2xy-ax+x^2-2ay\)

\(=2y\left(x-a\right)+x\left(x-a\right)\)

\(=\left(x-a\right)\left(2y+x\right)\)

e) \(x^2y+xy^2-x-y\)

\(=xy\left(x+y\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(xy-1\right)\)

f) \(25-10x-4y^2+x^2\)

\(=\left(x^2-10x+25\right)-\left(2y\right)^2\)

\(=\left(x-5\right)^2-\left(2y\right)^2\)

\(=\left(x-5-2y\right)\left(x-5+2y\right)\)

g) \(x^3-6xy+9y^2-36\)

h) \(4x^2-9y^2+4x-6y\)

\(=\left(2x\right)^2-\left(3y\right)^2+2\left(2x-3y\right)\)

\(=\left(2x-3y\right)\left(2x+3y\right)+2\left(2x-3y\right)\)

\(=\left(2x-3y\right)\left(2x+3y+2\right)\)

k) \(-x^2+5x+2xy-5y-y^2\)

\(=-\left(x^2-2xy+y^2\right)+5\left(x-y\right)\)

\(=-\left(x-y\right)^2+5\left(x-y\right)\)

\(=\left(x-y\right)\left(-x+y+5\right)\)

i) \(4x^2-25y^2-6x+15y\)

\(=\left(2x\right)^2-\left(5y\right)^2-3\left(2x-5y\right)\)

\(=\left(2x-5y\right)\left(2x+5y\right)-3\left(2x-5y\right)\)

\(=\left(2x-5y\right)\left(2x+5y-3\right)\)

28 tháng 1 2020

a, \(x\left(y+z\right)^2+y\left(x+z\right)^2+z\left(x+y\right)^2+4xyz\)

\(=x\left(y+z\right)^2+x^2\left(y+z\right)+yz\left(y+z\right)\)

\(=\left(y+z\right)\left(xy+xz+z^2+yz\right)\)

\(=\left(y+z\right)\left[x\left(x+y\right)+z\left(x+y\right)\right]\)

\(=\left(y+z\right)\left(x+z\right)\left(x+y\right)\)

b, \(yz\left(y+z\right)+xz\left(z-x\right)-xy\left(x+y\right)\)

\(=yz\left(y+z\right)+xz^2-x^2z-x^2y-xy^2\)

\(=yz\left(y+z\right)-x\left(y+z\right)\left(y-z\right)-x^2\left(y+z\right)\)

\(=\left(y+z\right)\left(yz-xy+xz-x^2\right)\)

\(=\left(y+z\right)\left[y\left(z-x\right)+x\left(z-x\right)\right]\)

\(=\left(y+z\right)\left(y+x\right)\left(z-x\right)\)