Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
J.
=2345-1000:[19-2*(3^2)]
=2345-1000:[19-18]
=2345-1000:1
=2345-1000
=1345
F.
=(11^2)-(3^2)*-3+50
=[(11-3)^2]*-3+50
=(8^2)*-3+50
=64-3+50
=61+50
=111
E.
=295+(31-4*5)
=295+(31-20)
=295+11
=306
mik het bit làm r
J. 2345-1000 : [ 19 - 2 ( 21 - 18 )2 ]
= 2345 - 1000 : [ 19 - 2.32 ]
= 2345 - 1000 : (19 - 18)
= 2345 - 1000
= 1345.
F. 1125 : 1123 - 33 + 50
= 112 - 27 + 50
= 121 - 27 + 50
= 144
E. 295 + ( 31 - 22 . 5 )2
= 295 + (31 - 4.5)2
= 295 + 112
= 295 + 121
= 416
H. 47 + ( 45 . 24 - 52 . 12) : 14
= 47 + (45 . 16 - 25.12) : 14
= 47 + 420 : 14
= 47 + 30
= 77
I. 102 - 60 : ( 56 : 54 - 3 . 5 )
= 100 - 60 : (25 - 15)
= 100 - 60 : 10
= 100 - 6
= 94.
K. 205 + [ 1200 - ( 42 - 2 . 3 ) 3 ] : 40
= 205 + [1200 - (16 - 6)3 ] : 40
= 205 + [1200 - 1000] : 40
= 205 + 200 : 40
= 205 + 5
= 210
L. 500 - { 5 . [ 409 - ( 23 . 3 - 21 ) 2 ] + 103 } : 15
= 500 - {5 . [409 - (24 - 21)2 ] + 1000} : 15
= 500 - {5 . [409 - 9] + 1000}: 15
= 500 - {5.400+1000}:15
= 500 -3000:15
= 500 - 200
= 300.
sau 58 ,7,50 ,2,-60 là phép tính khác .
mấy b giúp mk nha ?
a, \(11^{25}\div11^{23}-3^5\div\left(1^{10}+2^3\right)-60\)
\(=11^{25}\div11^{23}-3^5\div\left(1+8\right)-60\)
\(=11^{25}\div11^{23}-3^5\div3^2-60\)
\(=11^2-3^3-60\)
\(=121-27-60\)
\(=94-60=34\)
b, \(2345-1000\div\left[19-2\left(21-18\right)^2\right]\)
\(=2345-1000\div\left[19-2.3^2\right]\)
\(=2345-1000\div\left[19-2.9\right]\)
\(=2345-1000\div1=2345-1000=1345\)
c, \(128-\left[68+8\left(37-35\right)^2\right]\div4\)
\(=128-\left[68+8.2^2\right]\div4\)
\(=128-\left[68+8.4\right]\div4\)
\(=128-\left[68+32\right]\div4\)
\(=128-100\div4=128-25=103\)
d, \(107-\left\{38+\left[7.3^2-24\div6+\left(9-7\right)^3\right]\right\}\div15\)
\(=107-\left\{38+\left[7.9-4+2^3\right]\right\}\div15\)
\(=107-\left\{38+\left[63-4+8\right]\right\}\div15\)
\(=107-\left\{38+\left[59+8\right]\right\}\div15\)
\(=107-\left\{38+67\right\}\div15\)
\(=107-105\div15\)
\(=107-7=100\)
e, \(50-\left[50-\left(2^3.5\right)\div2+3\right]\)
\(=50-\left[50-8.5\div2+3\right]\)
\(=50-\left[50-40\div2+3\right]\)
\(=50-\left[50-20+3\right]\)
\(=50-\left[30+3\right]\)
\(=50-33=17\)
Bài 2 :
a, \(5\left(x-9\right)=350-5^2\)
\(5\left(x-9\right)=350-25\)
\(5\left(x-9\right)=325\)
\(x-9=325\div5\)
\(x-9=65\)
\(\Rightarrow x=65+9\)
\(\Rightarrow x=74\)
Vậy x = 74
b, \(2\left(x-51\right)=2.2^3+20\)
\(2\left(x-51\right)=16+20\)
\(2\left(x-51\right)=36\)
\(x-51=36\div2\)
\(x-51=18\)
\(\Rightarrow x=18+51\)
\(\Rightarrow x=69\)
Vậy x = 69
c, \(2.3^x=162\)
\(\Rightarrow2.3^x=2.3^4\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
Vậy x = 4
\(a)\)\(47-\left[\left(45.2^4-5^2.12\right)\div14\right]\)
\(=\)\(47-\left[\left(45.16-25.12\right)\div14\right]\)
\(=\)\(47-\left[\left(720-300\right)\div14\right]\)
\(=\)\(47-\left[420\div14\right]\)
\(=\)\(47-30\)
\(=\)\(17\)
\(b)\)\(10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]\div28\)
\(=\)\(10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]\div28\)
\(=\)\(10-\left[16.5+\left(80+8\right)\right]\div28\)
\(=\)\(10-\left[16.5+88\right]\div28\)
\(=\)\(10-\left[80+88\right]\div28\)
\(=\)\(10-168\div28\)
\(=\)\(10-6\)
\(=\)\(4\)
c) \(2345-1000:\left[19-2\left(21-18\right)^2\right]\)
= \(2345-1000:\left[19-2.3^2\right]\)
= \(2345-1000:\left[19-2.9\right]\)
= \(2345-1000:\left[19-18\right]\)
= \(2345-1000:1\)
= \(1345\)
Bài 1:
a)(-95)+(-105)=-(95+105)=-200
b)38+(-85)=-47
c)47-107=-60
d)18-(-2)=18+2=20
Bài 2:
a)295-(31-2^2.5)^2
=295-(31-20)^2
=295-(11)^2
=295-121
=147
b)11^25:11^23-3^5:(1^10+2^3)-60
=11^2-3^5:(1+8)-60
=121-3^5:3^2-60
=121-3^3-60
=121-27-60=34