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b1
a) \(\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}\)
\(=\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=\dfrac{1}{5}-\dfrac{1}{10}\)
\(=\dfrac{2}{10}-\dfrac{1}{10}\)
\(=\dfrac{1}{10}\)
b) \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{99.100}\)
\(=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\)
\(=\dfrac{1}{1}-\dfrac{1}{100}\)
\(=\dfrac{99}{100}\)
c) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\)
\(=\dfrac{1}{3}-\dfrac{1}{11}\)
\(=\dfrac{8}{33}\)
d) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{99.101}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\)
\(=\dfrac{1}{3}-\dfrac{1}{101}\)
\(=\dfrac{98}{303}\)
1)tính
a)\(-18+\left(-19\right)+27\)
\(=-18-19+27\)
\(=-\left(18+19\right)+27\)
\(=-37+27\)
\(=-\left(37-27\right)\)
\(=-10\)
b)\(-198-194+286\)
\(=-\left(198+194\right)+286\)
\(=-392+286\)
\(=-\left(392-286\right)\)
\(=-6\)
c)\(-19-\left(-17\right)\)
\(=-19+17\)
\(=-\left(19-17\right)\)
\(=-2\)
d)\(-48+\left(-47\right)-\left(-15\right)\)
\(=-48-47+15\)
\(=-\left(48+47\right)+15\)
\(=-95+15\)
\(=-\left(95-15\right)\)
\(=-80\)
e)\(23-\left(-16\right)+\left(-80\right)\)
\(=23+16-80\)
\(=39-80\)
\(=-80+39\)
\(=-\left(80-39\right)\)
\(=-41\)
f)\(99-\left(-99\right)-198\)
\(=99+99-198\)
\(=198-198\)
\(=0\)
\(\frac{1}{19}+\frac{2}{18}+\frac{3}{17}+...+\frac{18}{2}+\frac{19}{1}\) = \(\left(\frac{1}{19}+1\right)+\left(\frac{2}{18}+1\right)+...+\left(\frac{18}{2}+1\right)+1\)
= \(\frac{20}{19}+\frac{20}{18}+...+\frac{20}{2}+\frac{20}{20}\)
=\(20.\left(\frac{1}{19}+\frac{1}{18}+...+\frac{1}{2}+\frac{1}{20}\right)\)
=\(20.\left(\frac{1}{20}+\frac{1}{19}+\frac{1}{18}+...+\frac{1}{2}\right)\)
Vì tử số gấp 20 lần mẫu số nên phân số này bằng 20
A= 99^18+1 / 99^19+1 < 99^18 +1 +98 / 99^19 +1+98 =99^18+99 / 99^19+99
= 99(99^17 + 1) / 99(99^18+1)
= 99^17+1 / 99^18+1 = B
=> A<B
11+12+13+14+15+16+17+18+19+...+89+88+87+86+85+84+83+82
=( 11 + 89 )+(12+88)+(13+87)+(14+86)+(15+85)+(16+84)+(17+83)+(18+82)+19
=100+100+100+100+100+100+100+100+19
=800+19
=819
ta co B=1717+1/1718+1=10x(1717+1)/10x(1718+1)
=1718+10/1719+10
mà A=1718+1/1719+1 < B=1718+10/1719+10
suy ra A < B
Kết quả là:4814
k mk mk
sẽ k lại cho!
17 + 18 + 19 +.....+ 99
= ( 99 + 17 ) . 99 : 2
= 116 . 49 + 1 - > ( 1 là số dư của phép chia 99 : 2 )
= 5648 + 1
= 5649 .