Câu hỏi của Ko Có Tên

Question

Bài 1 ,Phân tích đa thức thành nhân tử

Câu 1. 25a² + 10a + 1

Câu 2. 2x⁸ - 12x⁴ + 18

Câu 3 . 4x + 4xy⁶ + xy¹²

๖²⁴ʱƘ-ƔℌŤ༉ · Accepted Answer

$1.25a^2+10a+1$

$=\left(5a\right)^2+2.5a.1+1^2$

$=\left(5a+1\right)^2$

$2.2x^8-12x^4+18$

$=2\left(x^8-6x^4+9\right)$

$=2\left[\left(x^4\right)^2-2.x^4.3+3^2\right]$

$=2\left(x^4-3\right)^2$

$=2\left(x^2-\sqrt{3}\right)^2\left(x^2+\sqrt{3}\right)^2$

$3.4x+4xy^6+xy^{12}$

$=x\left(y^{12}+4y^6+4\right)$

$=x\left[\left(y^6\right)^2+2.y^6.2+2^2\right]$

$=x\left(y^6+2\right)^2$

Câu trả lời:

$1.25a^2+10a+1$

$=\left(5a\right)^2+2.5a.1+1^2$

$=\left(5a+1\right)^2$

$2.2x^8-12x^4+18$

$=2\left(x^8-6x^4+9\right)$

$=2\left[\left(x^4\right)^2-2.x^4.3+3^2\right]$

$=2\left(x^4-3\right)^2$

$=2\left(x^2-\sqrt{3}\right)^2\left(x^2+\sqrt{3}\right)^2$

$3.4x+4xy^6+xy^{12}$

$=x\left(y^{12}+4y^6+4\right)$

$=x\left[\left(y^6\right)^2+2.y^6.2+2^2\right]$

$=x\left(y^6+2\right)^2$

zZz Cool Kid_new zZz · Answer

Câu 1

$25a^2+10a+1$

$=\left(5a\right)^2+2\cdot5\cdot a+1$

$=\left(5a+1\right)^2$

Câu trả lời:

Câu 1

$25a^2+10a+1$

$=\left(5a\right)^2+2\cdot5\cdot a+1$

$=\left(5a+1\right)^2$