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1> Nua chu vi khu dat hinh chu nhat la:
280:2=140(m)
Goi chieu dai va chieu rong lan luot la x,y(x,y \(\varepsilon\)N)
Theo bai ra ta co : \(\frac{x}{4}=\frac{y}{3}\)va x+y=140
Ap dung tinh chat day ti so bang nhau ta co:
\(\frac{x}{4}=\frac{y}{3}=\frac{x+y}{4+3}=\frac{140}{7}=20\)
Tu \(\frac{x}{4}=20=>x=80\)
\(\frac{y}{3}=20=>y=60\)
Vaay chieu dai va chieu rong lan luot la 80,60
Dien h khu dat hinh chu nhat la
80.60=4800(\(m^2\))
D/s:4800m^2
Day la cach lam lop 7 nha boi vi ban hocj lop 7 nen mk giai theo cach lop7.
Nho k cho mk nhe
a) \(2\sqrt{9}+3\sqrt{16}+2\sqrt{49}\)
\(=2.3+3.4+2.7\)
\(=6+12+14\)
\(=32\)
b) \(4\sqrt{0,25}+2\sqrt{0,36}-2\sqrt{0,16}\)
\(=4.\sqrt{\frac{25}{100}}+2\sqrt{\frac{36}{100}}-2\sqrt{\frac{16}{100}}\)
\(=4.\frac{1}{2}+2.\frac{3}{5}-2.\frac{4}{25}\)
\(=2+\frac{6}{5}-\frac{8}{25}\)
\(=\frac{72}{25}\)
a) \(C=3\cdot\sqrt{25}-3\cdot\sqrt{\frac{1}{9}}\)
\(C=3\cdot5-3\cdot\frac{1}{3}\)
\(C=15-1=14\)
b) \(D=-4\sqrt{\frac{4}{25}}+3\sqrt{0,16}-2\sqrt{0,04}\)
\(D=-4\cdot\frac{2}{5}+3\cdot\frac{2}{5}-2\cdot\frac{1}{5}\)
\(D=\frac{1}{5}\cdot\left(-8+6-2\right)\)
\(D=\frac{1}{5}\cdot\left(-4\right)=-\frac{4}{5}\)
a\\(\sqrt{49}+\sqrt{4}=7+2=9\)
b\\(\sqrt{0,25}-\sqrt{0.01}=0.5-01=0.4\)
c\\(\sqrt{\dfrac{16}{25}}-\sqrt{\dfrac{1}{81}}=\dfrac{4}{5}-\dfrac{1}{9}=\dfrac{31}{45}\)
d\\(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3\right)^2}=8-4+3=7\)
e\\(2-\sqrt{0,36}=2-0.6=1.4\)
Cảm ơn bạn!
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\(\sqrt{12}+\sqrt{27}-\sqrt{3}\)
=\(\sqrt{4.3}+\sqrt{9.3}-\sqrt{3}\)
=\(\Leftrightarrow\)\(2\sqrt{3}+3\sqrt{3}-\sqrt{3}\)
=\(4\sqrt{3}\)
=\(\sqrt{3}\left(\sqrt{4}+\sqrt{9}-1\right)\)
=\(\sqrt{3}\left(2+3-1\right)\)
=\(4\sqrt{3}\)
\(=\sqrt{2^2.3}+\sqrt{3^3}-\sqrt{3}=2\sqrt{3}+3\sqrt{3}-\sqrt{3}=4\sqrt{3}\)
Trả lời
\(\sqrt{12}+\sqrt{27}-\sqrt{3}\)
= \(4\sqrt{2}\)
hok tốt
#Giải:
a)\(\sqrt{27}\)+\(\sqrt{75}\)-\(\sqrt{\dfrac{1}{3}}\)=8\(\sqrt{3}\)-\(\sqrt{\dfrac{1}{3}}\)=\(\dfrac{23\sqrt{3}}{3}\).
b)\(\sqrt{4+2\sqrt{3}}\)-\(\sqrt{4-2\sqrt{3}}\)=2.
c)\(\dfrac{3}{\sqrt{7}+\sqrt{2}}\)+\(\dfrac{2}{3+\sqrt{7}}\)+\(\dfrac{2-\sqrt{2}}{\sqrt{2}-1}\)=1,093+\(\dfrac{2-\sqrt{2}}{\sqrt{2}-1}\)=2,507.
a) = \(3\sqrt{3}+5\sqrt{3}-\dfrac{1}{\sqrt{3}}\)
= \(3\sqrt{3}+5\sqrt{3}-\dfrac{3}{\sqrt{3}}\)
= \(\dfrac{23\sqrt{3}}{3}\)
b) = \(\sqrt{\left(1+\sqrt{3}\right)^2}-\sqrt{\left(1-\sqrt{3}\right)^2}\)
= \(1+\sqrt{3}-\left(\sqrt{3}-1\right)\)
= \(1+\sqrt{3}-\sqrt{3}+1\)
= 2
c) = \(\dfrac{3\left(\sqrt{7}-\sqrt{2}\right)}{5}+\dfrac{2\left(3-\sqrt{7}\right)}{2}+\left(2-\sqrt{2}\right)\left(\sqrt{2}+1\right)\)
= \(3\sqrt{7}-3\sqrt{2}+3-\sqrt{7}+2\sqrt{2}+2-2-\sqrt{2}\)
= \(\dfrac{3\sqrt{7}-3\sqrt{2}}{5}+3-\sqrt{7}+\sqrt{2}\)
= \(\dfrac{3\sqrt{7}-3\sqrt{2}-5\sqrt{7}+5\sqrt{2}}{5}+3\)
= \(\dfrac{-2\sqrt{7}+2\sqrt{2}}{5}+3\)
\(\approx2,5\)
a)\(\sqrt{1}\)+\(\sqrt{9}\)+\(\sqrt{25}\)+\(\sqrt{49}\)+\(\sqrt{81}\)
=1+3+5+7+9
=25
b)=\(\dfrac{1}{2}\)+\(\dfrac{1}{3}\)+\(\dfrac{1}{6}\)+\(\dfrac{1}{4}\)
=\(\dfrac{6}{12}\)+\(\dfrac{4}{12}\)+\(\dfrac{2}{12}\)+\(\dfrac{3}{12}\)
=\(\dfrac{15}{12}\)
c) =0,2+0.3+0,4
= 0.9
d) =9-8+7
=8
j) =1,2-1,3+1.4
= (-0,1)+1,4
=1,4
g) \(\dfrac{2}{5}\)+\(\dfrac{5}{2}\)+\(\dfrac{9}{10}\)+\(\dfrac{3}{4}\)
= (\(\dfrac{4}{10}\)+\(\dfrac{15}{10}\)+\(\dfrac{9}{10}\))+\(\dfrac{3}{4}\)
= \(\dfrac{14}{5}\)+\(\dfrac{3}{4}\)
=\(\dfrac{56}{20}\)+\(\dfrac{15}{20}\)
= \(\dfrac{71}{20}\)
Nhớ tick cho mk nha~
\(\sqrt{12}+\sqrt{27}-\sqrt{3}=\sqrt{2.2.3}+\sqrt{3.3.3}-\sqrt{3}\)
\(=2\sqrt{3}+3\sqrt{3}-\sqrt{3}=4\sqrt{3}\)
\(\sqrt{0,16}-\sqrt{0,25}=0,4-0,5=\left(-0,1\right)\)