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\(\frac{15}{2}\)- 6 =\(\frac{3}{2}\);
\(\frac{5}{8}\)x 3 = \(\frac{15}{8}\);
\(\frac{7}{4}\): 4 = \(\frac{7}{16}\);
\(\frac{1}{6}\)+ 4 = \(\frac{25}{6}\);
\(\frac{5}{8}\)- \(\frac{2}{64}\)= \(\frac{38}{64}\)= \(\frac{19}{32}\).
Hok tốt !
15/2-6
15/2-6/1
15/2-12/2
3/2
5/8.3
5/8.3/1
15/8
7/4:4
7/4:4/1
7/4.1/4
7/16
1/6+4
1/6+4/1
1/6+24/6
27/6
5/8-2/64
40/64-2/64
38/64
a, 8 x 6/32 x 1/5 = 3/10
8 x 6/32 x 1/5 = 8 x 3/16 x 1/5 = 3/10
b, 15/16 x 36/35 x 28 = 27
A, X x 3/5 + X x 7/5 = 9/4 B, X - 4/7 = 1/5 : 7/2
<=> X x (3/5 + 7/5) = 9/4 <=> X - 4/7 = 2/35
<=> X x 2 = 9/4 <=> X = 2/35 + 4/7 <=> X = 22/35
<=> X= 9/4 : 2 <=> X = 9/8
#HT#
\(a,x.\frac{3}{5}+x.\frac{7}{5}=\frac{9}{4}\)
\(\Leftrightarrow x.\left(\frac{3}{5}+\frac{7}{5}\right)=\frac{9}{4}\)
\(\Leftrightarrow x.2=\frac{9}{4}\)
\(\Leftrightarrow x=\frac{9}{8}\)
\(b,x-\frac{4}{7}=\frac{1}{5}:\frac{7}{2}\)
\(\Leftrightarrow x-\frac{4}{7}=\frac{2}{35}\)
\(\Leftrightarrow x=\frac{22}{35}\)
a) \(x-\frac{4}{9}=\frac{5}{6}\)
\(\Leftrightarrow\frac{18x}{18}-\frac{8}{18}=\frac{15}{18}\)
\(\Rightarrow18x-8=15\)
\(\Leftrightarrow18x=15+8\)
\(\Leftrightarrow18x=23\)
\(\Leftrightarrow x=\frac{23}{18}\)
Vậy \(x=\frac{23}{18}\)
b)\(x-7=\frac{1}{6}\)
\(\Leftrightarrow\frac{6x}{6}-\frac{42}{6}=\frac{1}{6}\)
\(\Rightarrow6x-42=1\)
\(\Leftrightarrow6x=42+1\)
\(\Leftrightarrow6x=43\)
\(\Leftrightarrow x=\frac{43}{6}\)
Vậy \(x=\frac{43}{6}\)
c)\(x-\frac{7}{8}=11\)
\(\Leftrightarrow\frac{8x}{8}-\frac{7}{8}=\frac{88}{8}\)
\(\Rightarrow8x-7=88\)
\(\Leftrightarrow8x=88+7\)
\(\Leftrightarrow8x=95\)
\(\Leftrightarrow x=\frac{95}{8}\)
Vậy \(x=\frac{95}{8}\)
#bn cs thể bỏ\(\Leftrightarrow;\Rightarrow\)đều đc nhé #
#hoktot<3#
a, x - 4/9 = 5/6
x = 5/6 + 4/9
x = 69/54
b, x - 7 = 1/6
x = 1/6 + 7
x = 43/6
c, x - 7/8 = 11
x = 11 + 7/8
x = 95/8
Bài 1:
\(\dfrac{2}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{2}{5}\)
=\(\dfrac{40}{60}\) + \(\dfrac{45}{60}\) - \(\dfrac{24}{60}\)
= \(\dfrac{61}{60}\)
b; \(\dfrac{12}{13}\) x \(\dfrac{3}{4}\) - \(\dfrac{7}{13}\)
= \(\dfrac{9}{13}\) - \(\dfrac{7}{13}\)
= \(\dfrac{2}{13}\)
c; \(\dfrac{15}{17}\) : \(\dfrac{19}{34}\) - \(\dfrac{17}{19}\)
= \(\dfrac{15}{17}\) x \(\dfrac{34}{19}\) - \(\dfrac{17}{19}\)
= \(\dfrac{30}{19}\) - \(\dfrac{17}{19}\)
= \(\dfrac{13}{19}\)
Bài 2:
a; \(\dfrac{x}{5}\) x \(\dfrac{3}{7}\) = \(\dfrac{9}{35}\)
\(\dfrac{x}{5}\) = \(\dfrac{9}{35}\) : \(\dfrac{3}{7}\)
\(\dfrac{x}{5}\) = \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{3}{5}\) x 5
\(x\) = 3
Tính bằng 2 cách :
a). 234 x 25 + 234 x 75
C1: \(234\times25+234\times75\)
\(=5850+17550\)
\(=23400\)
C2: \(234\times25+234\times75\)
\(=234\times\left(25+75\right)\)
\(=234\times100\)
\(=23400\)
b). 765 x 123 - 755 x 23
C1: \(765\times123-765\times23\)
\(=94095-17595\)
\(=76500\)
C2: \(765\times123-765\times23\)
\(=765\times\left(123-23\right)\)
\(=765\times100\)
\(=76500\)
=> Bạn xem lại đề ạ!
c). 476 x ( 45 + 55 )
C1: \(476\times\left(45+55\right)\)
\(=476\times100\)
\(=47600\)
C2: \(476\times\left(45+55\right)\)
\(=476\times45+476\times55\)
\(=21420+26180\)
\(=47600\)
d). 2415 : 5 : 5
=> Xem lại đề ạ
e). ( 76 x 28 ) : 7
C1: \(\left(76\times28\right)\div7\)
\(=2128\div7\)
\(=304\)
C2: \(\left(76\times28\right)\div7\)
\(=76\times\left(28\div7\right)\)
\(=76\times4\)
\(=304\)
g). ( 175 + 29070 ) : 5
C1: \(\left(175+29070\right)\div5\)
\(=29245\div5\)
\(=5849\)
C2: \(\left(175+29070\right)\div5\)
\(=175\div5+29070\div5\)
\(=35+5814\)
\(=5849\)
h). ( 3224 - 1236 ) : 4
C1: \(\left(3224-1236\right)\div4\)
\(=1988\div4\)
\(=497\)
C2: \(\left(3224-1236\right)\div4\)
\(=3224\div4-1236\div4\)
\(=806-309\)
\(=497\)
( 11 x 9 - 100 +1 ) x ( 1 x 2 x ... x10 ) = (99 + 1 - 100) x 1 x 2 x .... x 10
= 0 x 1 x 2 x ....... x 10
= 0
Ta có
(11x9 -100+1)x (1x2x3x..x100)
= 0x ( 1x2x3x..x100)
=0
b, 3/5 + 4/7 + 2/8 + 10/25 + 9/21 + 28/16
= 3/5 + 4/7 + 2/8 + 2/5 + 3/7 + 14/8
= (3/5 + 2/5) + ( 4/7 + 3/7) + ( 2/8 + 14/8)
= 1 + 1 + 7/4
= 2 + 7/4 = 15/4
c , 8/7 + 7/6 + 5/8 + 10/12 + 24/28 + 6/16
= c , 8/7 + 7/6 + 5/8 + 5/6 + 6/7 + 1/2
= (8/7 + 6/7) + (7/6 + 5/6) + 5/8 + 1/2
= 14/7 + 12/6 + 5/8 + 1/2
= 2 + 2 + 5/8 + 1/2
= 4 + 9/8 = 41/8
\(x+\left[\frac{5}{5}+\frac{5}{45}+\frac{5}{117}+\frac{5}{221}+...+\frac{5}{1845}\right]=2\)
\(x+\left[\frac{5}{1.5}+\frac{5}{5.9}+\frac{5}{9.13}+\frac{5}{13.17}+...+\frac{5}{41.45}\right]=2\)
\(\frac{5}{4}x+\frac{5}{4}.\left(\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}\right)=\frac{2.5}{4}=\frac{5}{2}\)
\(\frac{5}{4}x+\frac{5}{4}.\left(1-\frac{1}{45}\right)=\frac{5}{2}\)
\(\frac{5}{4}x+\frac{11}{9}=\frac{5}{2}\)
\(\frac{5}{4}x=\frac{23}{18}\)
\(x=\frac{46}{45}\)