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31 tháng 8 2019

2A=1+1/2+.........+1/2^51

2A-A={1+1/2+......+1/2^51}-{1/2+1/2^2+.....+1/2^50}

A=1-1/2^50

=>A<1

31 tháng 8 2019

\(A=\frac{1}{2}+\frac{1}{2^2}+\cdot\cdot\cdot+\frac{1}{2^{50}}\)

\(\Rightarrow2A=1+\frac{1}{2}+\cdot\cdot\cdot+\frac{1}{2^{49}}\)

\(\Rightarrow2A-A=\left(1+\cdot\cdot\cdot+\frac{1}{2^{49}}\right)-\left(\frac{1}{2}+\cdot\cdot\cdot\cdot+\frac{1}{2^{50}}\right)\)

\(\Rightarrow A=1-\frac{1}{2^{50}}\)

\(\Rightarrow A\) < \(1\)

29 tháng 8 2017

A=\(\frac{1}{1\cdot2}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{49\cdot50}\)

\(A=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{49}-\frac{1}{50}\)

A=\(1-\frac{1}{50}\)

\(A=\frac{49}{50}\)

BC chịu thua

3 tháng 8 2018

\(2A=1+\frac{1}{2}+...+\frac{1}{2^{49}}\)

\(2A-A=1-\frac{1}{2^{50}}\)

\(A=1-\frac{1}{2^{50}}\)=> A bé hơn 1

tương tự nha

3 tháng 8 2018

\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{49}}+\frac{1}{2^{50}}\)

\(2A=2.\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{49}}+\frac{1}{2^{50}}\right)\)

\(2A=1+\frac{1}{2}+\frac{1}{2^2}+....+\frac{1}{2^{48}}+\frac{1}{2^{49}}\)

\(2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{48}}+\frac{1}{2^{49}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{49}}+\frac{1}{2^{50}}\right)\)

\(A=1-\frac{1}{2^{50}}< 1\)

    

25 tháng 8 2020

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{n\left(n+1\right)}=\frac{49}{50}\)

\(\Rightarrow\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{n\left(n+1\right)}=\frac{49}{50}\)

\(\Rightarrow\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{n}-\frac{1}{n+1}=\frac{49}{50}\)

\(\Rightarrow1-\frac{1}{n+1}=\frac{49}{50}\)

\(\Rightarrow\frac{1}{n+1}=\frac{1}{50}\)

\(\Rightarrow n+1=50\)

\(\Rightarrow n=49\)

\(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+...+\frac{2}{\left(2n-1\right)\left(2n+1\right)}=\frac{50}{51}\)

\(\Rightarrow\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{\left(2n-1\right)\left(2n+1\right)}=\frac{50}{51}\)

\(\Rightarrow\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{2n-1}-\frac{1}{2n+1}=\frac{50}{51}\)

\(\Rightarrow\frac{1}{1}-\frac{1}{2n+1}=\frac{50}{51}\)

\(\Rightarrow\frac{1}{2n+1}=\frac{1}{51}\)

\(\Rightarrow2n+1=51\)

\(\Rightarrow2n=50\)

\(\Rightarrow n=25\)

6 tháng 10 2018

     \(\frac{49}{1}+\frac{48}{2}+\frac{47}{3}+...+\frac{2}{48}+\frac{1}{49}\)

\(=1+1+...+1+\frac{48}{2}+\frac{47}{3}+...+\frac{2}{48}+\frac{1}{49}\)(có 49 số 1)

\(=\left(1+\frac{48}{2}\right)+\left(1+\frac{47}{3}\right)+...+\left(1+\frac{2}{48}\right)+\left(1+\frac{1}{49}\right)+1\)

\(=\frac{50}{2}+\frac{50}{3}+...+\frac{50}{48}+\frac{50}{49}+\frac{50}{50}\)

\(=50\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{49}+\frac{1}{50}\right)\)

Chúc bạn học tốt.