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B) 2017100.(x-60)=2017101
x-60=2017101 : 2017100
x-60 = 2017
x= 2017 + 60
x= 2077
C) 5.x+3.(10-x)+x=45
5x+30 - 3x + x = 45
3x = 45-30
3x = 15
x= 5
A) (17x-25):8+65=92
(17x-25):8 = 81 - 65
(17x-25):8 = 16
17x-25= 16:8
17x = 2+27
17x = 29
x= 29/17
a) (17.x - 25 ) : 8 = 92 : 65= 92/65
17x - 25 = 92/65.8
17x = 2361/65
x= 2361/65 : 17=2361/1105
b) x- 60 = 2017101 - 2017100
x-60 = 2017
x = 2017 + 60
x = 2077
c) 5x . 30-3x.x = 45
5x.3x.x = 45 + 30 = 75
15x.x = 75
Bài 1:
1,\(90-\left(2^2.2^5-3^2.7\right)\)
\(=90-\left(2^7-9.7\right)\)
\(=90-\left(128-63\right)\)
\(=25\)
2,\(720-\left\{40.\left[\left(120-70\right):25+2^3\right]\right\}\)
\(=720-\left(40.1258\right)\)
\(=-49600\)
Bài 2:
a,\(5x-17=38\)
\(5x=55\)
\(x=11\)
b,\(2x-138=2^3.3^2\)
\(2x-138=72\)
\(2x=210\)
\(x=105\)
c,\(7x-3^3=2^7:2^4\)
\(7x-27=8\)
\(7x=35\)
\(x=5\)
d,\(\left(81-x\right)-32=19\)
\(\left(81-x\right)=51\)
\(x=30\)
e,\(36+\left(x-19\right)=54\)
\(x-19=18\)
\(x=37\)
f,\(45+\left(x-6\right).3=60\)
\(\left(x-6\right).3=15\)
\(x-6=5\)
\(x=11\)
g,\(100-7.\left(x-5\right)=58\)
\(7\left(x-5\right)=42\)
\(x-5=6\)
\(x=11\)
h,\(\left|x\right|-5=3\)
\(\left|x\right|=8\)
\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-8\end{matrix}\right.\)
Vậy...
i,\(\left|x-5\right|=7\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=7\\x-5=-7\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-2\end{matrix}\right.\)
Vậy...
a) x- 18 = - 25
x =( -25 ) + 18
x = -7
b) 42 - x = 53 - 60
16 - x = 65
x = 16 - 65
x = -49
a)
\(5x+60=120\)
\(\Rightarrow5x=120-60\)
\(\Rightarrow5x=60\)
\(\Rightarrow x=60\div5\)
\(\Rightarrow x=12\)
Vậy \(x=12\)
b)
\(213-\left(x+25\right)=112\)
\(\Rightarrow x+25=213-112\)
\(\Rightarrow x+25=101\)
\(\Rightarrow x=101-25\)
\(\Rightarrow x=76\)
Vậy \(x=76\)
c)
\(5^x-25=100\)
\(\Rightarrow5^x=100+25\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
Vậy \(x=3\)