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a. => \(2^{6+x}=2^{10}\)
=> 6+x=10
=> x=10-6
Vậy x=4.
b. => \(7^{3x-1}:7^2=7^6\)
=> 73x-1-2=76
=> 73x-3=76
=> 3x-3=6
=> 3x=6+3
=> 3x=9
Vậy x=3.
c. =>\(7^{5x-1}-25=24\)
=>75x-1=24+25
=>75x-1=49
=>75x-1=72
=>5x-1=2
=>5x=3
Vậy x=\(\frac{3}{5}\).
d. => \(10^{x-3}=10^0\)
=>x-3=0
Vậy x=3.
e. => 2x=10
=> x=10:2
Vậy x=5.
a) (3x +5)3 =121.(-11)
(3x +5)3 = -113
3x + 5 = -11
3x = -11 - 5
x = \(-\frac{16}{3}\)
b) 3.|2x +1| - 10= |-11|
3.|2x+1| = 11 + 10
|2x+1| = 7
\(\Rightarrow\orbr{\begin{cases}2x+1=7\\2x+1=-7\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-4\end{cases}}}\)
c) 100-(x -5)2 = (-6)2
(x-5)2 = 82
x-5 = 8
x = 13
\(\left(3x+5\right)^3=121\left(-11\right)\)
\(\Rightarrow\left(3x+5\right)^3=-1331=\left(-11\right)^3\)
\(\Rightarrow3x+5=-11\)
\(\Rightarrow3x=-16\)
\(\Rightarrow x=-\frac{16}{3}\)
\(3\left|2x+1\right|-10=\left|-11\right|\)
\(\Rightarrow\left|2x+1\right|=7\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=7\\2x+1=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=-4\end{cases}}\)
\(100-\left(x-5\right)^2=\left(-6\right)^2\)
\(\Rightarrow\left(x-5\right)^2=64=\left(\pm8\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=8\\x-5=-8\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=13\\x=-3\end{cases}}\)
Đặt \(A=5+5^3+5^5+....+5^{47}+5^{49}\)
\(\Rightarrow5^2A=5^3+5^5+5^7+.....+5^{49}+5^{51}\)
\(\Rightarrow5^2A-A=\left(5^3+5^5+5^7+....+5^{49}+5^{51}\right)-\left(3+3^3+3^5+....+5^{47}+5^{49}\right)\)
\(\Rightarrow24A=5^{51}-5\)
\(\Rightarrow A=\dfrac{5^{51}-5}{24}\)
Vậy ............................................................
1)a) \(\left(3x-7\right)^5=32\Rightarrow\left(3x-7\right)^5=2^5\)
\(\Rightarrow3x-7=2\Rightarrow3x=9\Rightarrow x=3\)
Vậy \(x=3\)
b) \(\left(4x-1\right)^3=-27.125\)
\(\Rightarrow\left(4x-1\right)^3=-3^3.5^3=-15^3\)
\(\Rightarrow4x-1=-15\Rightarrow4x=-14\Rightarrow x=-3,5\)
Vậy \(x=-3,5\)
c) \(3^{4x+4}=81^{x+3}\Rightarrow3^{4x+4}=3^{4x+12}\)
\(\Rightarrow4x+4=4x+12\)
\(\Rightarrow4x=4x+8\)
\(\Rightarrow x\in\varnothing\)
d) \(\left(x-5\right)^7=\left(x-5\right)^9\)
\(\Rightarrow\left(x-5\right)^7-\left(x-5\right)^9=0\)
\(\Rightarrow\left(x-5\right)^7.\left[1-\left(x-5\right)^2\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}\left(x-5\right)^7=0\\1-\left(x-5\right)^2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\\left(x-5\right)^2=1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=5\\x-5=-1\\x-5=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=4\\x=6\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=5\\x=4\\x=6\end{matrix}\right.\)
a)(2x+1)2=25
\(\Rightarrow\)2x+1=5
2x=4
\(\Rightarrow\)x=2
b)(3-3x)2+12=16
\(\Rightarrow\)(3-3x)2=4
3-3x=2
3x=1
\(\Rightarrow\)x=\(\frac{1}{3}\)
C)(x+2)2=49
\(\Rightarrow\)x+2=7
\(\Rightarrow\)x=5
Bạn nhớ kết luận nha mik chưa kết luận
a)\(5^{2\text{x}-1}\)=174-49
\(^{5^{2\text{x}-1}}\)=125=\(^{5^3}\)
2x-1=3
2x=4
x=2
b)(3x+1)\(^3\)=10\(^{^{ }3}\)
3x+1=10
3x=9
x=3
Trả lời ;............................
a) x = 2
b) Sai đề.....................
Hk tốt..........................