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a,2.53-36:32
=2.125-36:9
=250-4=246
b,13.75+13.25-140
=13.(75+25)-140
=13.100-140
=1300-140
=1160
c,50-[30-(6-2)2]
=50-[30-42]
=50-[30-16]
=50-14=36
a) \(\left(\frac{4}{13}.\frac{6}{5}+\frac{4}{13}.\frac{2}{5}\right).\left(2x+1\right)^2=\frac{10}{13}\)
\(\left(\frac{4}{13}.\frac{8}{5}\right).\left(2x+1\right)^2=\frac{10}{13}\)
\(\frac{32}{65}.\left(2x+1\right)^2=\frac{10}{13}\)
\(\left(2x+1\right)^2=\frac{10}{13}\div\frac{32}{65}\)
\(\left(2x+1\right)^2=\frac{25}{16}\)
\(\Rightarrow2x+1\in\left\{\frac{5}{4};-\frac{5}{4}\right\}\)
\(\hept{\begin{cases}2x+1=\frac{5}{4}\\2x+1=-\frac{5}{4}\end{cases}\Rightarrow\hept{\begin{cases}2x=\frac{1}{4}\\2x=-\frac{9}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x=\frac{1}{8}\\x=-\frac{9}{8}\end{cases}}}\)
Vậy \(x\in\left\{\frac{1}{8};-\frac{9}{8}\right\}\)
\(x^3-\frac{9}{16}.x=0\)
\(x\left(x^2-\frac{9}{16}\right)=0\)
\(\hept{\begin{cases}x=0\\x^2-\frac{9}{16}=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x^2=\frac{9}{16}\end{cases}\Rightarrow}\hept{\begin{cases}x=0\\x=\pm\frac{3}{4}\end{cases}}}\)
Vậy \(x\in\left\{0;\frac{3}{4};-\frac{3}{4}\right\}\)
2) = 19683 . 3 : 59049 + 32 : 16 . 4 - 9 . 1
= 59049 : 59049 + 2 . 4 - 9
= 1 + 8 - 9
= 9 - 9
= 0
1) = {53^3 - 67 . [(169+144)].5 +7.3^4]} :2011
=[53^3 - 67 . (313 . 5 + 7 . 81 ] :2011
= [53^3 - 67. ( 1565 + 567 )] : 2011
= (53^3 - 67 . 2132) :2011
=(148877 - 142844 ) : 2011
= 6033 : 2011
= 3
1125:1123-35:(110+23)-60
=1125:1123-35:(1+8)-60
=1125:1123-35:9-60
=1125-23-243:9-60
=112-27-60
=121-27-60
=34
Bài 1 :
a ) 13,75 + 13,25 - 300 = 27 - 300 = -273
b ) 5,42 - ( 30 - 33 ) = 29,16 - ( 30 - 27 ) = 29,16 - 3 = 26,16
c ) 62 : 2 + 2,32 = 36 : 2 + 5,29 = 18 + 5,29 = 23,29
Bài 2 : chịu
Bài 3 :
a ) x + 13 = 35
x = 35 - 13 = 22
b,c ) chịu
a) \(2^2.3-\left(1^{10}+8\right):3^2\)
\(=4.3-\left(1+8\right):9\)
\(=12-9:9\)
\(=12-1\)
\(=11\)
b) \(115^0+13.75+13.25-140\)
\(=0+13.\left(75+25\right)-140\)
\(=0+13.100-140\)
\(=0+1300-140\)
\(=1300-140\)
\(=1160\)