Câu hỏi của Chu Nguyễn Bảo Trang

Question

a. 17,85 + 15,17- 120

c. 3 mũ 3 . 22 - 27 .19

b. 5. 7 mũ 2 - 24 : 2 mũ 3

d. - [ - 13] + [ -23]

e. - [- 13] + [-25] +12

f. 23 - [ 12 - 4 mũ 2 ] +15

...

Nguyễn Lê Phước Thịnh · Accepted Answer

a: $17\cdot85+15\cdot17-120$

$=17\left(85+15\right)-120$

$=17\cdot100-120=1700-120=1580$

c: $3^3\cdot22-27\cdot19$

$=27\cdot22-27\cdot19$

$=27\left(22-19\right)=27\cdot3=81$

b: $5\cdot7^2-24:2^3$

$=5\cdot49-24:8$

=245-3=242

d: -(-13)+(-23)

=13-23

=-10

e: -[-13]+[-25]+12

=13-25+12

=25-25=0

f: $23-\left(12-4^2\right)+15$

$=23-\left(12-16\right)+15$

=38-(-4)=38+4=42

g: $80-\left[130-\left(12-4\right)^2\right]$

$=80-130+8^2$

=64-50=14

h: $2^4\cdot5-\left[131-\left(13-2^2\right)^2\right]$

$=16\cdot5-\left[131-\left(13-4\right)^2\right]$

=80-131+81

=161-131=30

i: $-\left(-23\right)-\left(-13\right)-4^2$

=23+13-16

=36-16=20

k: $\dfrac{\left(3^{15}\cdot4+3^{15}\cdot5\right)}{3^{16}}=\dfrac{3^{15}\cdot\left(5+4\right)}{3^{16}}=\dfrac{9}{3}=3$

l: $1125:3^2+4^3\cdot125-125:5^2$

=1125:9+8*125-125:25

=125+1000-5

=1120

m: $375+\left[58+\left(-375\right)+38\right]$

=375+58-375+38

=58+38=96

n: -18:(-6)-(-12)+(-20)

=3+12-20

=15-20=-5

p: $2011-\left\{5\cdot5^2-\left[7^3:7+2012^0\right]\right\}$

$=2011-\left\{125-7^2-1\right\}$

=2011-125+49+1

=1936

p.1449 - {[( 216 +184) : 8 ] .9}

$=1449-\left\{400:8\cdot9\right\}$

=1449-450

=999

r. 120 : { 520 : [ 500- ( 5^3+ 35 .7 )]}

$=120:\left\{520:\left[500-\left(125+245\right)\right]\right\}$

$=120:\left\{520:\left[500-370\right]\right\}$

=120:(520:130)

=120:4=30

s .1500- { 5^3 .2^3 -11 . [ 7^2 - 5. 2^3 + 8 (11^2 -121)]}

$=1500-\left\{10^3-11\cdot\left[49-5\cdot8+8\cdot0\right]\right\}$

$=1500-1000+11\cdot\left(49-40\right)$

=500+11*9

=500+99

=599

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