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b)\(892^2+892.216+108^2=892^2+2.892.108+108^2\\ =\left(892+108\right)^2=1000^2=1000000\)
c)\(10,2.9,8-9,8.0,2+10,2^2-10,2.0,2=9,8.\left(10,2-0,2\right)+10,2.\left(10,2-0.2\right)\\ =9,8.10+10,2.10=98+102=200\)
a) 20042 - 16
= 20042 - 42
= (2004 - 4)(2004 + 4)
= 2000.2008
= 4016000
b) 8922 + 892.216 + 1082
= 8922 + 2.892.108 + 1082
= (892 + 108)2
= 10002
= 1000000
c) 10,2.9,8 - 9,8.0,2 + 10,2.0,2
= 9,8(10,2 - 0,2) + 2,04
= 9,8.10 + 2,04
= 98 + 2,04
= 100,04
d) 362 + 262 - 52.36
= 362 - 2.36.26 + 262
= (36 - 26)2
= 102
= 100
8922 + 892.216 + 1082
= 8922 + 2.892.108 + 1082
= (892 + 108)2
= 10002
= 1000000
Phân tích đa thức thành nhân tử:
\(6xy+5x-5y-3x^2-3y^2\)
\(=-3x^2+6xy-3y^2+5x-5y\)
\(=-3\left(x^2-2xy+y^2\right)+5\left(x-y\right)\)
\(=-3\left(x-y\right)^2+5\left(x-y\right)\)
\(=\left(x-y\right)\left[-3\left(x-y\right)+5\right]\)
\(=\left(x-y\right)\left(-3x+3y+5\right)\)
Thực hiện phép tính:
a)\(\left(x^2+x-3\right)\left(x^2-x+3\right)\)
\(=\left[x^2+\left(x-3\right)\right]\left[x^2-\left(x-3\right)\right]\)
\(=\left(x^2\right)^2-\left(x-3\right)^2\)
\(=x^4-\left(x^2-6x+9\right)\)
\(=x^4-x^2+6x-9\)
b)\(\left(5x-1\right)\left(x+3\right)-\left(x-2\right)\left(5x-4\right)\)
\(=\left(5x^2+15x-x-3\right)-\left(5x^2-4x-10x+8\right)\)
\(=5x^2+15x-x-3-5x^2+4x+10x-8\)
\(=28x-11\)
\(a,2004^2-16=2004^2-4^2=\left(2004-4\right)\left(2004+4\right)=2000.2008=4016000\)\(b,892^2+892.216+108^2=892^2+2.892.108+108^2=\left(892+108\right)^2=1000^2=1000000\)\(c,10,2.9,8-9,8.02+10,2^2-10,2.0,2=9,8\left(10,2-0,2\right)+10,2\left(10,2-0,2\right)=9,8.10+10,2.10=98+102=200\)\(d,36^2+26^2-52.36=36^2-2.36.26+26^2=\left(36-26\right)^2=10^2=100\)\(e,99^3+1+3.\left(99^2+99\right)=99^3+3.99^2+3.99+1^3=\left(99+1\right)^3=100^3=1000000\)
\(f.37.43=\left(40-3\right)\left(40+3\right)=40^2-3^2=1600-9=1591\)
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